How do I get a substring of a string in Python? [duplicate]

Asked 2023-09-20 20:27:22 View 359,507

I want to get a new string from the third character to the end of the string, e.g. myString[2:end]. If omitting the second part means 'to the end', and if you omit the first part, does it start from the start?

Answers

>>> x = "Hello World!"
>>> x[2:]
'llo World!'
>>> x[:2]
'He'
>>> x[:-2]
'Hello Worl'
>>> x[-2:]
'd!'
>>> x[2:-2]
'llo Worl'

Python calls this concept "slicing" and it works on more than just strings. Take a look here for a comprehensive introduction.

Answered   2023-09-20 20:27:22

Just for completeness as nobody else has mentioned it. The third parameter to an array slice is a step. So reversing a string is as simple as:

some_string[::-1]

Or selecting alternate characters would be:

"H-e-l-l-o- -W-o-r-l-d"[::2] # outputs "Hello World"

The ability to step forwards and backwards through the string maintains consistency with being able to array slice from the start or end.

Answered   2023-09-20 20:27:22

  • @mtahmed absolutely related to question. What if you wanted to substring by selecting alternate characters from the string? That would be my_string[::2] - anyone
  • I think it's more likely you wanted to mention the third parameter to slice. Needing to get every other character from a string may be an important use case somewhere, but I've never had to do it. Not that there's anything wrong with wanting to show off what you know -- what's the point of knowing things if you can't do that. :) But the case for relevance to the question is overstated. - anyone
  • Sure, the specific example of selecting alternate characters may not be relevant to the question, but understanding there is a 3rd parameter to slicing very much is relevant and the simple examples serve to illustrate how it works. The Python community also has a great history of educating new members in a friendly way :-) - anyone
  • It is clear that if you put some_string[::-1] you got back, the string in reverse order. However, I really don't understand what you do in this case with the other numbers? Ex.: test_string[5:1:-1] - will result a totally different way that I expect. How the first and second numbers will effect the string if the third number is "-1" ? - anyone

Substr() normally (i.e. PHP and Perl) works this way:

s = Substr(s, beginning, LENGTH)

So the parameters are beginning and LENGTH.

But Python's behaviour is different; it expects beginning and one after END (!). This is difficult to spot by beginners. So the correct replacement for Substr(s, beginning, LENGTH) is

s = s[ beginning : beginning + LENGTH]

Answered   2023-09-20 20:27:22

  • The beginners should learn the pythonic way when moving to python, not stick to other language habits - anyone
  • And just for completeness, Java is like Python in that the String.substring() method takes start and one-past-end. This one just bit me hard, I had assumed it was length like every other substring function in the world. - anyone
  • A (probably) more pythonic way to do that is s[beginning:][:length] - anyone
  • As someone who began with Python instead of [dirty word]-languages like PHP, I think Python is much more simple and intuitive with its string[beginning:end]. Length generally isn't relevant. - anyone
  • @PhilHibbs "Like every other substring function" is rather too strong a statement, since there are at least two other common ways to interpret substring arguments. One is (start, length) and the other is (start, end). Python's (start, end+1) is admittedly unusual, but fits well with the way other things in Python work. - anyone

A common way to achieve this is by string slicing.

MyString[a:b] gives you a substring from index a to (b - 1).

Answered   2023-09-20 20:27:22

One example seems to be missing here: full (shallow) copy.

>>> x = "Hello World!"
>>> x
'Hello World!'
>>> x[:]
'Hello World!'
>>> x==x[:]
True
>>>

This is a common idiom for creating a copy of sequence types (not of interned strings), [:]. Shallow copies a list, see Python list slice syntax used for no obvious reason.

Answered   2023-09-20 20:27:22

  • This has almost nothing to do with the question about substring. Doesn't even apply to string. Saying stringA = stringB is enough ... - anyone
  • The [:] full copy creates a NEW COPY, uses slice syntax and is read as "substring from start to end" - anyone
  • What’s the point since strings are immutable? a=b should be sufficient. - anyone
  • @gimel: Actually, [:] on an immutable type doesn't make a copy at all. While mysequence[:] is mostly harmless when mysequence is an immutable type like str, tuple, bytes (Py3) or unicode (Py2), a = b[:] is equivalent to a = b, it just wastes a little time dispatching the slicing byte codes which the object responds to by returning itself since it's pointless to shallow copy when, aside from object identity tests, it's equivalent to just return another reference to one's immutable self. - anyone
  • Attempting to sum up the other criticisms of this answer: In Python, strings are immutable, therefore there is no reason to make a copy of a string - so s[:] doesn't make a copy at all: s = 'abc'; s0 = s[:]; assert s is s0. Yes it was the idiomatic way to copy a list in Python until lists got list.copy, but a full slice of an immutable type has no reason to make a copy because it can't be changed, so there may as well be only one in memory and we shouldn't waste time copying it. Since this answer is wrong and doesn't even answer the question - should it be deleted? - anyone

Is there a way to substring a string in Python, to get a new string from the 3rd character to the end of the string?

Maybe like myString[2:end]?

Yes, this actually works if you assign, or bind, the name,end, to constant singleton, None:

>>> end = None
>>> myString = '1234567890'
>>> myString[2:end]
'34567890'

Slice notation has 3 important arguments:

  • start
  • stop
  • step

Their defaults when not given are None - but we can pass them explicitly:

>>> stop = step = None
>>> start = 2
>>> myString[start:stop:step]
'34567890'

If leaving the second part means 'till the end', if you leave the first part, does it start from the start?

Yes, for example:

>>> start = None
>>> stop = 2
>>> myString[start:stop:step]
'12'

Note that we include start in the slice, but we only go up to, and not including, stop.

When step is None, by default the slice uses 1 for the step. If you step with a negative integer, Python is smart enough to go from the end to the beginning.

>>> myString[::-1]
'0987654321'

I explain slice notation in great detail in my answer to Explain slice notation Question.

Answered   2023-09-20 20:27:22

I would like to add two points to the discussion:

  1. You can use None instead on an empty space to specify "from the start" or "to the end":

    'abcde'[2:None] == 'abcde'[2:] == 'cde'
    

    This is particularly helpful in functions, where you can't provide an empty space as an argument:

    def substring(s, start, end):
        """Remove `start` characters from the beginning and `end` 
        characters from the end of string `s`.
    
        Examples
        --------
        >>> substring('abcde', 0, 3)
        'abc'
        >>> substring('abcde', 1, None)
        'bcde'
        """
        return s[start:end]
    
  2. Python has slice objects:

    idx = slice(2, None)
    'abcde'[idx] == 'abcde'[2:] == 'cde'
    

Answered   2023-09-20 20:27:22

You've got it right there except for "end". It's called slice notation. Your example should read:

new_sub_string = myString[2:]

If you leave out the second parameter it is implicitly the end of the string.

Answered   2023-09-20 20:27:22

If myString contains an account number that begins at offset 6 and has length 9, then you can extract the account number this way: acct = myString[6:][:9].

If the OP accepts that, they might want to try, in an experimental fashion,

myString[2:][:999999]

It works - no error is raised, and no default 'string padding' occurs.

Answered   2023-09-20 20:27:22

  • I think if you want to use this method myString[offset:][:length] in the case of OP you can just use myString[offset:][:] - anyone
  • @VictorVal The answer is for those (like me) who have learned Python as a 2nd (3rd, 4th, ...) programming language and want to some familiar 'syntax hooks' to approach the language. Any experts in the language will most likely view my answer as a bit silly. - anyone
  • Should answers like this be flagged for deletion? Other answers explain similar solution much better, and seeing this one had made me scratch my head and lookup python for few minutes before realising that it's just that type answer. - anyone

Well, I got a situation where I needed to translate a PHP script to Python, and it had many usages of substr(string, beginning, LENGTH).
If I chose Python's string[beginning:end] I'd have to calculate a lot of end indexes, so the easier way was to use string[beginning:][:length], it saved me a lot of trouble.

Answered   2023-09-20 20:27:22

str1='There you are'
>>> str1[:]
'There you are'

>>> str1[1:]
'here you are'

#To print alternate characters skipping one element in between

>>> str1[::2]
'Teeyuae'

#To print last element of last two elements
>>> str1[:-2:-1]
'e'

#Similarly
>>> str1[:-2:-1]
'e'


#Using slice datatype

>>> str1='There you are'
>>> s1=slice(2,6)
>>> str1[s1]
'ere '


Answered   2023-09-20 20:27:22

  • I like your approach in listing out the options. It seems two of your options are the same, though? - anyone
text = "StackOverflow"
#using python slicing, you can get different subsets of the above string

#reverse of the string
text[::-1] # 'wolfrevOkcatS' 

#fist five characters
text[:5] # Stack'

#last five characters
text[-5:] # 'rflow'

#3rd character to the fifth character
text[2:5] # 'ack'

#characters at even positions
text[1::2] # 'tcOefo'

Answered   2023-09-20 20:27:22

  • The text[2:5] comment says "rflow" but I think that example output is actually "ack". Thanks for the helpful examples! - anyone

Maybe I missed it, but I couldn't find a complete answer on this page to the original question(s) because variables are not further discussed here. So I had to go on searching.

Since I'm not yet allowed to comment, let me add my conclusion here. I'm sure I was not the only one interested in it when accessing this page:

 >>>myString = 'Hello World'
 >>>end = 5

 >>>myString[2:end]
 'llo'

If you leave the first part, you get

 >>>myString[:end]
 'Hello' 

And if you left the : in the middle as well you got the simplest substring, which would be the 5th character (count starting with 0, so it's the blank in this case):

 >>>myString[end]
 ' '

Answered   2023-09-20 20:27:22

Using hardcoded indexes itself can be a mess.

In order to avoid that, Python offers a built-in object slice().

string = "my company has 1000$ on profit, but I lost 500$ gambling."

If we want to know how many money I got left.

Normal solution:

final = int(string[15:19]) - int(string[43:46])
print(final)
>>>500

Using slices:

EARNINGS = slice(15, 19)
LOSSES = slice(43, 46)
final = int(string[EARNINGS]) - int(string[LOSSES])
print(final)
>>>500

Using slice you gain readability.

Answered   2023-09-20 20:27:22

  • Maybe this isn't the best example, because the hardcoded indexes remain and the readability comes from intermediate variables, which you could have used in the first example. - anyone
a="Helloo"
print(a[:-1])

In the above code, [:-1] declares to print from the starting till the maximum limit-1.

OUTPUT :

>>> Hello

Note: Here a [:-1] is also the same as a [0:-1] and a [0:len(a)-1]

a="I Am Siva"
print(a[2:])

OUTPUT:

>>> Am Siva

In the above code a [2:] declares to print a from index 2 till the last element.

Remember that if you set the maximum limit to print a string, as (x) then it will print the string till (x-1) and also remember that the index of a list or string will always start from 0.

Answered   2023-09-20 20:27:22

I have a simpler solution using for loop to find a given substring in a string. Let's say we have two string variables,

main_string = "lullaby"
match_string = "ll"

If you want to check whether the given match string exists in the main string, you can do this,

match_string_len = len(match_string)
for index,value in enumerate(main_string):
    sub_string = main_string[index:match_string_len+index]
    if sub_string == match_string:
       print("match string found in main string")

Answered   2023-09-20 20:27:22