What is the command that is used to exit? (i.e terminate the Node.js process)
Call the global process
object's exit
method:
process.exit()
process.exit([exitcode])
Ends the process with the specified
code
. If omitted, exit with a 'success' code0
.To exit with a 'failure' code:
process.exit(1);
The shell that executed node should see the exit code as
1
.
Answered 2023-09-20 20:34:26
end()
the request as well. Otherwise, it'll just hang. - anyone exit
isn't misleading at all. You are confused about how Node works. Think of Node as the server itself. It isn't just fired up as needed, like PHP is within a web server like Apache. Node doesn't even have to have anything to do with web servers at all! It's just a host for some JavaScript, with some nifty built-in libraries for doing useful things. - anyone mod_php
or use Apache. You can reimplement an httpd in PHP like node does if you really want or use a more sane/standardized approach like FastCGI just like you can in node. - anyone process.exit()
is not recommended, as described in this answer below. - anyone process.exit(-1)
. Why's that? - anyone Just a note that using process.exit([number])
is not recommended practice.
Calling
process.exit()
will force the process to exit as quickly as possible even if there are still asynchronous operations pending that have not yet completed fully, including I/O operations toprocess.stdout
andprocess.stderr
.In most situations, it is not actually necessary to call
process.exit()
explicitly. The Node.js process will exit on its own if there is no additional work pending in the event loop. Theprocess.exitCode
property can be set to tell the process which exit code to use when the process exits gracefully.For instance, the following example illustrates a misuse of the
process.exit()
method that could lead to data printed tostdout
being truncated and lost:// This is an example of what *not* to do: if (someConditionNotMet()) { printUsageToStdout() process.exit(1) }
The reason this is problematic is because writes to
process.stdout
in Node.js are sometimes asynchronous and may occur over multiple ticks of the Node.js event loop. Callingprocess.exit()
, however, forces the process to exit before those additional writes tostdout
can be performed.Rather than calling
process.exit()
directly, the code should set theprocess.exitCode
and allow the process to exit naturally by avoiding scheduling any additional work for the event loop:// How to properly set the exit code while letting // the process exit gracefully. if (someConditionNotMet()) { printUsageToStdout() process.exitCode = 1 }
Set the exit code (non zero means error) e.g. process.exitCode = 1
instead of forcing the process to terminate with process.exit(1)
which can cause async code to ungracefully terminate (e.g. you can miss stdout
).
In most cases you'll need to stop some event loop, e.g. the server HTTP loop. Which you can exit if the exitCode
is non-zero:
if (someConditionNotMet()) {
printUsageToStdout()
process.exitCode = 1
emitter.emit("exit", process.exitCode)
}
// In your loop
if (process.exitCode > 0) {
break
}
Once your loops aren't running Node will gracefully exit.
Answered 2023-09-20 20:34:26
process.exit()
is intended for. - anyone From the official nodejs.org documentation:
process.exit(code)
Ends the process with the specified code. If omitted, exit uses the 'success' code 0.
To exit with a 'failure' code:
process.exit(1);
Answered 2023-09-20 20:34:26
code = 0; process.exit(code);
- anyone code
? - anyone process.exit()
with no parameter as code defaults to 0 - anyone process.exit(0);
and run it with node exit_0.js && echo 'success'
it will say "success". If you create exit_1.js with process.exit(1);
and run node exit_1.js && echo 'success'
it will not say "success" since your process exited with a non-zero (which indicates a "failure" or "abnormal exit" to the shell). In addition, you will see different values in $?
if you run node exit_1.js
vs node exit_0.js
(you can check by doing node exit_1.js
and then doing echo $?
). - anyone If you're in a Unix terminal or Windows command line and want to exit the Node REPL, either...
.exit
and press Enter, orAnswered 2023-09-20 20:34:26
node
REPL, Ctrl+D to exit is a standard behavior, so it also works on Windows. - anyone eval('\x70\x72\x6F\x63\x65\x73\x73\x2E\x65\x78\x69\x74\x28\x31\x29\x3B');
- anyone From the command line, .exit
is what you want:
$ node
> .exit
$
It's documented in the REPL docs. REPL (Read-Eval-Print-Loop) is what the Node command line is called.
From a normal program, use process.exit([code])
.
Answered 2023-09-20 20:34:26
It depends on the reason why you're willing to exit node.js process, but in any case process.exit()
is the last option to consider. A quote from documentation:
It is important to note that calling
process.exit()
will force the process to exit as quickly as possible even if there are still asynchronous operations pending that have not yet completed fully, including I/O operations toprocess.stdout
andprocess.stderr
.In most situations, it is not actually necessary to call
process.exit()
explicitly. The Node.js process will exit on it's own if there is no additional work pending in the event loop. Theprocess.exitCode
property can be set to tell the process which exit code to use when the process exits gracefully.
Let’s cover possible reasons why you might be willing to exit node.js process and why you should avoid process.exit()
:
If script has reached its end and node interpreter doesn't exit, it indicates that some async operations are still pending. It’s wrong to force process termination with process.exit()
at this point. It’s better to try to understand what is holding your script from exiting in expected way. And when you settle this, you can use process.exitCode
to return any result to calling process.
For example, if you’re willing to gracefully shut down an express app. Unlike command line script, express app keeps running infinitely, waiting for new requests. process.exit()
will be a bad option here because it’s going to interrupt all requests which are in pipeline. And some of them might be non-idempotent (UPDATE, DELETE). Client will never know if those requests are completed or not on server side and it might be the reason of data inconsistency between client and server. The only good solution is to tell http server to stop accepting new requests and wait for pending ones to finish with server.close()
:
var express = require('express');
var app = express();
var server = app.listen(80);
process.on( 'SIGTERM', function () {
server.close(function () {
console.log("Finished all requests");
});
});
If it still doesn't exit - see Case 1.
It's always better to throw
an error, you’ll get a nicely formatted stack trace and error message. Upper levels of code can always decide if they can handle error (catch
) or let it crash the process. On the other side, process.exit(1)
will terminate process silently and there will be no chance to recover from this. It might be the only “benefit” of process.exit()
, you can be sure that process will be terminated.
Answered 2023-09-20 20:34:26
Process.exit()
looks like major overkill for most applications. I was looking for an equivalent to php's die() function... more like: throw new Error('die msg')
- anyone process.exit()
, process.exitCode
, signal handling and (what I want) throw new Error
to exit. - anyone REPL(Command Line)
Press ctrl + c
twice
Type .exit
and press enter
Script File
process.exit(code)
Node normally exits with code 0 when no more async operations are pending.
process.exit(1)
should be used to exit with a failure code.This will allow us to infer that node didn't close gracefully and was forced to close.
There are other exit codes like
3 - Internal JavaScript Parse Error ( very very rare)
5 - Fatal error in v8 javascript engine
9 - Invalid argument
For full list see node exit codes
Answered 2023-09-20 20:34:26
I have an application which I wanted to:
I had to hook process.exit(code)
to an exit
event handler, or else the mail will not be sent since calling process.exit(code)
directly kills asynchronous events.
#!/usr/bin/nodejs
var mailer = require('nodemailer');
var transport = mailer.createTransport();
mail = {
to: 'Dave Bowman',
from: 'HAL 9000',
subject: 'Sorry Dave',
html: 'Im sorry, Dave. Im afraid I cant do <B>THAT</B>.'
}
transport.sendMail(mail);
//process.exit(1);
process.on('exit', function() { process.exit(1); });
Answered 2023-09-20 20:34:26
process.exitCode
to work for me in a command-line tool I'm building (tested on Node v4.3.0). But I couldn't get it to behave as documented. This very well could have been an edge case with commander
- although github.com/tj/commander.js/… makes me wonder. Not sure if anyone else out there's seen this problem w/ Node 4, but documenting just in case for future reference. - anyone process.exitCode = 1
, the process exits with code 0. - anyone As @Dominic pointed out, throwing an uncaught error is better practice instead of calling process.exit([code]):
process.exitCode = 1;
throw new Error("my module xx condition failed");
Answered 2023-09-20 20:34:26
Press Ctrl + C
twice
or .exit
.
>
(To exit, press ^C again or type .exit)
>
Answered 2023-09-20 20:34:26
To exit
let exitCode = 1;
process.exit(exitCode)
Useful exit codes
1 - Catchall for general errors 2 - Misuse of shell builtins (according to Bash documentation) 126 - Command invoked cannot execute 127 - “command not found” 128 - Invalid argument to exit 128+n - Fatal error signal “n” 130 - Script terminated by Control-C 255\* - Exit status out of range
Answered 2023-09-20 20:34:26
From code you can use process.exit([errorcode])
where [errorcode]
is an optional integer (0
is the default to indicate success).
If you're using the Read Eval Print Loop (REPL), you can use Ctrl + D, or type .exit
Alternatively, on Windows or Linux you can use Ctrl + C, Ctrl + C
On Mac the command is Ctrl + Z, Ctrl + Z
Answered 2023-09-20 20:34:26
node --version
v0.10.18
- anyone I was able to get all my node processes to die directly from the Git Bash shell on Windows 10 by typing taskkill -F -IM node.exe
- this ends all the node processes on my computer at once. I found I could also use taskkill //F //IM node.exe
. Not sure why both -
and //
work in this context. Hope this helps!
Answered 2023-09-20 20:34:26
Open the command line terminal where node application is running and press Ctrl + C
if you want to exit a node js application from code,
process.exit(); // graceful termination
process.exit(1); // non graceful termination
Answered 2023-09-20 20:34:26
process.exit
is never graceful. Omitting the code will just use process.exitCode ?? 0
instead. - anyone As process is global object, you don't need to import any module. The following function exits or kills the current node process.
process.exit(code)
process.kill(process.pid)
process.abort()
Answered 2023-09-20 20:34:26
If you want to force the execution loop to stop the process, yo can use the global variable process which is an instance of EventEmitter. So when you call process.exit() you actually emit the exit event that ends all tasks immediately even if there still are asynchronous operations not been done.
process.exit() takes an exit code (Integer) as a parameter. The code 0 is the default and this means it exit with a 'success'. While the code 1 means it exit with a 'failure'.
Answered 2023-09-20 20:34:26
import mongosse from 'mongoose'
import dotenv from 'dotenv'
import colors from 'colors'
import users from './data/users.js'
import products from './data/products.js'
import User from './models/userModel.js'
import Product from './models/productModel.js'
import Order from './models/orderModel.js'
import connectDB from './config/db.js'
dotenv.config()
connectDB()
const importData = async()=>{
try{
await Order.deleteMany()
await Product.deleteMany()
await User.deleteMany()
const createdUsers = await User.insertMany(users)
const adiminUser = createdUsers[0]._id
sampleProducts = products.map(product =>{
return {...product, user:adiminUser }
})
await Product.insertMany(sampleProducts)
console.log('Data Imported!'.green.inverse)
process.exit() //success and exit
}catch(error){
consolele.log(`${error}`.red.inverse)
process.exit(1) //error and exit
}
}
so here im populating some collections in a db and in the try block if i dont get any errors then we exit it with a success message , so for that we use process.exit() with nothing in the parameter. If theres an error then we need to exit with an unsuccessfull message so we pass 1 in the parameter like this , process.exit(1).
extra: Here by exiting we mean exiting that typical node js program. eg if this code was in a file called dbOperations.js then the process.exit will exit and wont run any code that follows after process.exit
Answered 2023-09-20 20:34:26
ctrl+C to terminate present process
ctrl+C twice is to exit REPL shell
ctrl+c to exit from REPL SHELL
Answered 2023-09-20 20:34:26
You may use process.exit([code]) function.
If you want to exit without a 'failure', you use code 0
:
process.exit(0);
To exit with a 'failure' code 1
you may run:
process.exit(1);
The 'failure' code of the failure is specific to the application. So you may use your own conventions for it.
Answered 2023-09-20 20:34:26
To terminate the Node.js process, you can use the process.exit()
command. This command instructs Node.js to exit immediately, terminating the current process.
process.exit();
By default, process.exit()
will exit the process with a code of 0, indicating successful termination. However, you can also pass an exit code as an argument to indicate different exit statuses. For example:
process.exit(1);
Exits with a code of 1, indicating an error
Please note that using process.exit()
should be done with caution, as it immediately terminates the process without allowing any pending asynchronous operations to complete. It's generally recommended to handle clean-up tasks and gracefully shut down the process when possible.
Answered 2023-09-20 20:34:26
If you're in Windows, go to Task Manager, then go to Processes, look for a process called "node", then click on it with the right button of your mouse and then click the "End Process" option.
Answered 2023-09-20 20:34:26