How do you check if a value is an object in JavaScript?
null
is an object). - anyone If typeof yourVariable === 'object'
, it's an object or null
.
If you want null
, arrays or functions to be excluded, just make it:
if (
typeof yourVariable === 'object' &&
!Array.isArray(yourVariable) &&
yourVariable !== null
) {
executeSomeCode();
}
Answered 2023-09-20 20:55:12
yourVariable !== null
be better practice? - anyone typeof null == 'object'
will not be fixed in ES6. They said: This proposal has been rejected. It was implemented in V8 but it turned out that it broke a lot of existing sites. In the spirit of One JavaScript this is not feasible.
- anyone Object.prototype.toString.call(yourVar)
, being yourVar what you need to inspect. In case of arrays, Object.prototype.toString.call([1,2])
returns [object Array]
- anyone Array.isArray(yourVariable)
. - anyone UPDATE:
This answer is incomplete and gives misleading results. For example, null
is also considered of type object
in JavaScript, not to mention several other edge cases. Follow the recommendation below and move on to other "most upvoted (and correct!) answer":
typeof yourVariable === 'object' && yourVariable !== null
Original answer:
Try using typeof(var)
and/or var instanceof something
.
EDIT: This answer gives an idea of how to examine variable's properties, but it is not a bulletproof recipe (after all there's no recipe at all!) for checking whether it's an object, far from it. Since people tend to look for something to copy from here without doing any research, I'd highly recommend that they turn to the other, most upvoted (and correct!) answer.
Answered 2023-09-20 20:55:12
typeof
returns 'object' for null, which is not an object, and instanceof
doesn't work for objects created using Object.create(null)
. - anyone typeof null
... object
! - anyone someArray instanceof Object //true
or typeof someArray === 'object' // true
. What about: Object.prototype.toString.call(someObject) === "[object Object]"
, or "[object Array]"
if you're trying to detect an array? - anyone Let's define "object" in Javascript. According to the MDN docs, every value is either an object or a primitive:
primitive, primitive value
A data that is not an object and does not have any methods. JavaScript has 7 primitive data types: string, number, bigint, boolean, undefined, symbol, and null.
What's a primitive?
3
'abc'
true
null
undefined
What's an object (i.e. not a primitive)?
Object.prototype
Object.prototype
Function.prototype
Object
Function
function C(){}
-- user-defined functionsC.prototype
-- the prototype property of a user-defined function: this is not C
s prototype
new C()
-- "new"-ing a user-defined functionMath
Array.prototype
{"a": 1, "b": 2}
-- objects created using literal notationnew Number(3)
-- wrappers around primitivesObject.create(null)
Object.create(null)
How to check whether a value is an object
instanceof
by itself won't work, because it misses two cases:
// oops: isObject(Object.prototype) -> false
// oops: isObject(Object.create(null)) -> false
function isObject(val) {
return val instanceof Object;
}
typeof x === 'object'
won't work, because of false positives (null
) and false negatives (functions):
// oops: isObject(Object) -> false
function isObject(val) {
return (typeof val === 'object');
}
Object.prototype.toString.call
won't work, because of false positives for all of the primitives:
> Object.prototype.toString.call(3)
"[object Number]"
> Object.prototype.toString.call(new Number(3))
"[object Number]"
So I use:
function isObject(val) {
if (val === null) { return false;}
return ( (typeof val === 'function') || (typeof val === 'object') );
}
@Daan's answer also seems to work:
function isObject(obj) {
return obj === Object(obj);
}
because, according to the MDN docs:
The Object constructor creates an object wrapper for the given value. If the value is null or undefined, it will create and return an empty object, otherwise, it will return an object of a type that corresponds to the given value. If the value is an object already, it will return the value.
A third way that seems to work (not sure if it's 100%) is to use Object.getPrototypeOf
which throws an exception if its argument isn't an object:
// these 5 examples throw exceptions
Object.getPrototypeOf(null)
Object.getPrototypeOf(undefined)
Object.getPrototypeOf(3)
Object.getPrototypeOf('abc')
Object.getPrototypeOf(true)
// these 5 examples don't throw exceptions
Object.getPrototypeOf(Object)
Object.getPrototypeOf(Object.prototype)
Object.getPrototypeOf(Object.create(null))
Object.getPrototypeOf([])
Object.getPrototypeOf({})
Answered 2023-09-20 20:55:12
obj === Object(obj)
returns true
for arrays. - anyone var x = []; console.log(x === Object(x)); // return true
- anyone getPrototypeOf
does not work e.g. with revoked proxies, which are objects but throw. - anyone ({}).toString.apply(obj) === '[object Object]'
this distinguishes between arrays and objects that are not arrays - anyone underscore.js provides the following method to find out if something is really an object:
_.isObject = function(obj) {
return obj === Object(obj);
};
UPDATE
Because of a previous bug in V8 and minor micro speed optimization, the method looks as follows since underscore.js 1.7.0 (August 2014):
_.isObject = function(obj) {
var type = typeof obj;
return type === 'function' || type === 'object' && !!obj;
};
Answered 2023-09-20 20:55:12
return obj === Object(obj) && Object.prototype.toString.call(obj) !== '[object Array]'
- anyone null
, too. Should be the accepted answer. - anyone Object.prototype.toString.call(myVar)
will return:
"[object Object]"
if myVar is an object"[object Array]"
if myVar is an arrayFor more information on this and why it is a good alternative to typeof, check out this article.
Answered 2023-09-20 20:55:12
typeof [] === 'object'
--> true
. That's what you need this method. - anyone Object.prototype.toString.call(3)
-> "[object Number]"
. Object.prototype.toString.call(new Number(3))
-> "[object Number]
" - anyone getType=function(obj){return Object.prototype.toString.call(obj).match(/\[object (\w+)\]/)[1];};
- anyone For simply checking against Object
or Array
without additional function call (speed). As also posted here.
isArray()
isArray = function(a) {
return (!!a) && (a.constructor === Array);
};
console.log(isArray( )); // false
console.log(isArray( null)); // false
console.log(isArray( true)); // false
console.log(isArray( 1)); // false
console.log(isArray( 'str')); // false
console.log(isArray( {})); // false
console.log(isArray(new Date)); // false
console.log(isArray( [])); // true
isLiteralObject()
- Note: use for Object
literals only, as it returns false
for custom objects, like new Date
or new YourCustomObject
.
isLiteralObject = function(a) {
return (!!a) && (a.constructor === Object);
};
console.log(isLiteralObject( )); // false
console.log(isLiteralObject( null)); // false
console.log(isLiteralObject( true)); // false
console.log(isLiteralObject( 1)); // false
console.log(isLiteralObject( 'str')); // false
console.log(isLiteralObject( [])); // false
console.log(isLiteralObject(new Date)); // false
console.log(isLiteralObject( {})); // true
Answered 2023-09-20 20:55:12
Boolean(a)
is longer, but far more intuitive. Just don't use new Boolean(a)
: (here's why)! - anyone {
character. For the array case, as long as you don't need to support IE < 9, you can use Array.isArray()
to determine if something is an array. It passes all the test cases you provided. - anyone !!a
isObject(null)
would return null
instead of false
- anyone I'm fond of simply:
function isObject (item) {
return (typeof item === "object" && !Array.isArray(item) && item !== null);
}
If the item is a JS object, and it's not a JS array, and it's not null
…if all three prove true, return true
. If any of the three conditions fails, the &&
test will short-circuit and false
will be returned. The null
test can be omitted if desired (depending on how you use null
).
DOCS:
http://devdocs.io/javascript/operators/typeof
http://devdocs.io/javascript/global_objects/object
Answered 2023-09-20 20:55:12
new Date()
returns an object. An array is from a logical point of view not an object - although JavaScript handles and reports them as such. In practice however, it is not helpful to see them equal, because they are not. An object has no length
attribute for example and it has no methods like push(). And sometimes you might want to give a function overloaded params, where you need to make a difference between an array or an object especially if other parameters depend on which one was given. - anyone length
property nor methods like push
, Object.create(Array.prototype)
is a trivial counterexample of a non-array object which has these. What makes arrays special is that they are exotic objects with a custom [[DefineOwnProperty]] essential internal method, but they are still objects. - anyone length
property (I meant that object literals have no length
attribute by default). I wrote that arrays are not objects from a logical point of view. I'm speaking about program logic. It is sometimes necessary to check if an array is a "real" array and definitely not an "real" object. That's what Array.isArray()
is for. Imagine you have a function which accepts an object or an array of objects. Checking for a special attribute or method is a dirty solution. The native way is always better. - anyone typeof null
is "object"
, not "undefined"
. - anyone Array.isArray
:function isObject(o) {
return o !== null && typeof o === 'object' && Array.isArray(o) === false;
}
Array.isArray
:Just surprised how many upvotes for wrong answers 😮
Only 1 answer passed my tests!!! Here I've created my simplified version:
function isObject(o) {
return o instanceof Object && o.constructor === Object;
}
As for me, it's clear and simple, and just works! Here my tests:
console.log(isObject({})); // Will return: true
console.log(isObject([])); // Will return: false
console.log(isObject(null)); // Will return: false
console.log(isObject(/.*/)); // Will return: false
console.log(isObject(function () {})); // Will return: false
ONE MORE TIME: not all answers pass this tests !!! 🙈
In case you need to verify that object is instance of particular class you have to check constructor with your particular class, like:
function isDate(o) {
return o instanceof Object && o.constructor === Date;
}
simple test:
var d = new Date();
console.log(isObject(d)); // Will return: false
console.log(isDate(d)); // Will return: true
As result, you will have strict and robust code!
In case you won't create functions like isDate
, isError
, isRegExp
, etc you may consider option to use this generalized functions:
function isObject(o) {
return o instanceof Object && typeof o.constructor === 'function';
}
it won't work correctly for all test cases mentioned earlier, but it's good enough for all objects (plain or constructed).
isObject
won't work in case of Object.create(null)
because of internal implementation of Object.create
which is explained here but you can use isObject
in more sophisticated implementation:
function isObject(o, strict = true) {
if (o === null || o === undefined) {
return false;
}
const instanceOfObject = o instanceof Object;
const typeOfObject = typeof o === 'object';
const constructorUndefined = o.constructor === undefined;
const constructorObject = o.constructor === Object;
const typeOfConstructorObject = typeof o.constructor === 'function';
let r;
if (strict === true) {
r = (instanceOfObject || typeOfObject) && (constructorUndefined || constructorObject);
} else {
r = (constructorUndefined || typeOfConstructorObject);
}
return r;
};
There is already created package on npm v1 based on this implementation! And it works for all earlier described test cases! 🙂
Answered 2023-09-20 20:55:12
isDate
for yourDateObject with purpose to write robust code otherwise you will have brittle isObject
method. - anyone Date
in my comment was ill-chosen because yes, the answer does discuss Date
. But Date
is just one of infinite possible classes and the point holds for any other class. Example: class Foo() { }; var x = new Foo(); isObject(x)
returns false
. I don't know exactly what the OP's use case is, but it's easy to conceive of scenarios in which having to know about all possible classes and checking specifically against every one of them is going to be infeasible. - anyone Oh My God! I think this could be more shorter than ever, let see this:
function isObject(obj)
{
return obj != null && obj.constructor.name === "Object"
}
console.log(isObject({})) // returns true
console.log(isObject([])) // returns false
console.log(isObject(null)) // returns false
typeof JavaScript objects (including null
) returns "object"
console.log(typeof null, typeof [], typeof {})
Checking on their constructor
property returns function with their names.
console.log(({}).constructor) // returns a function with name "Object"
console.log(([]).constructor) // returns a function with name "Array"
console.log((null).constructor) //throws an error because null does not actually have a property
Function.name
returns a readonly name of a function or "anonymous"
for closures.
console.log(({}).constructor.name) // returns "Object"
console.log(([]).constructor.name) // returns "Array"
console.log((null).constructor.name) //throws an error because null does not actually have a property
Answered 2023-09-20 20:55:12
Object.create(null)
and quite why you would do that anyway...? - anyone return obj != null && obj.constructor && obj.constructor.name === "Object"
The condition 'obj.constructor' returns false because Object.create(null) creates an object with no properties, not even .__proto__ or .constructor. - anyone const isObject = (obj) => (obj ?? false)?.constructor?.name === "Object";
Thank you! - anyone Try this
if (objectName instanceof Object) {
alert('An object');
} else {
alert('Not an object');
}
Answered 2023-09-20 20:55:12
Object.prototype instanceof Object
-> false. Object.create(null) instanceof Object
-> false. - anyone new Date() instanceof Object
=> true - anyone Date
s and arrays are objects. - anyone OK, let's give you this concept first before answering your question, in JavaScript Functions are Object, also null, Object, Arrays and even Date, so as you see there is not a simple way like typeof obj === 'object', so everything mentioned above will return true, but there are ways to check it with writing a function or using JavaScript frameworks, OK:
Now, imagine you have this object that's a real object (not null or function or array):
var obj = {obj1: 'obj1', obj2: 'obj2'};
Pure JavaScript:
//that's how it gets checked in angular framework
function isObject(obj) {
return obj !== null && typeof obj === 'object';
}
or
//make sure the second object is capitalised
function isObject(obj) {
return Object.prototype.toString.call(obj) === '[object Object]';
}
or
function isObject(obj) {
return obj.constructor.toString().indexOf("Object") > -1;
}
or
function isObject(obj) {
return obj instanceof Object;
}
You can simply use one of these functions as above in your code by calling them and it will return true if it's an object:
isObject(obj);
If you are using a JavaScript framework, they usually have prepared these kind of functions for you, these are few of them:
jQuery:
//It returns 'object' if real Object;
jQuery.type(obj);
Angular:
angular.isObject(obj);
Underscore and Lodash:
//(NOTE: in Underscore and Lodash, functions, arrays return true as well but not null)
_.isObject(obj);
Answered 2023-09-20 20:55:12
It depends on what you mean with "is an object". If you want everything that is not a primitive, i.e. things that you can set new properties on, this should do the trick:
function isAnyObject(value) {
return value != null && (typeof value === 'object' || typeof value === 'function');
}
It excludes the primitives (plain numbers/NaN
/Infinity
, plain strings, symbols, true
/false
, undefined
and null
) but should return true for everything else (including Number
, Boolean
and String
objects). Note that JS does not define what "host" objects, such as window
or console
, should return when used with typeof
, so those are hard to cover with a check like this.
If you want to know whether something is a "plain" object, i.e. it was created as a literal {}
or with Object.create(null)
, you might do this:
function isPlainObject(value) {
if (Object.prototype.toString.call(value) !== '[object Object]') {
return false;
} else {
var prototype = Object.getPrototypeOf(value);
return prototype === null || prototype === Object.prototype;
}
}
Edit 2018: Because Symbol.toStringTag
now allows customizing the output of Object.prototype.toString.call(...)
, the isPlainObject
function above might return false
in some cases even when the object started its life as a literal. Arguably, by convention an object with a custom string tag isn't exactly a plain object any more, but this has further muddied the definition of what a plain object even is in Javascript.
Answered 2023-09-20 20:55:12
instanceof Object
, two identical function literals are not strictly equal, they are passed by reference, etc. - anyone My God, too much confusion in other answers.
Short Answer
typeof anyVar == 'object' && anyVar instanceof Object && !(anyVar instanceof Array)
To test this simply run the following statements in chrome console.
Case 1.
var anyVar = {};
typeof anyVar == 'object' && anyVar instanceof Object && !(anyVar instanceof Array) // true
Case 2.
anyVar = [];
typeof anyVar == 'object' && anyVar instanceof Object && !(anyVar instanceof Array) // false
Case 3.
anyVar = null;
typeof anyVar == 'object' && anyVar instanceof Object && !(anyVar instanceof Array); // false
Explanation
Okay.Let's break it down
typeof anyVar == 'object'
is returned true from three candidates - [], {} and null
,
anyVar instanceof Object
narrows down these candidates to two - [], {}
!(anyVar instanceof Array)
narrows to only one - {}
Drum rolls please!
By this you may have already learnt how to check for Array in Javascript.
Answered 2023-09-20 20:55:12
false
(as desired) when anyVar
is a function. - anyone Here's an answer with optional chaining, and perhaps the smallest isObj
function for this question.
const isObj = o => o?.constructor === Object;
// True for this
console.log(isObj({})); // object!
// False for these
console.log(isObj(0)); // number
console.log(isObj([])); // array
console.log(isObj('lol')); // string
console.log(isObj(null)); // null
console.log(isObj(undefined)); // undefined
console.log(isObj(() => {})); // function
console.log(isObj(Object)); // class
Answered 2023-09-20 20:55:12
new Error()
would be false in your function. - anyone The most reasonable way to check the type of a value seems the typeof
operator. The only problem is that it's horribly broken:
"object"
for null
, which belongs to Null type."function"
for callable objects, which belong to Object type."unknown"
. The only forbidden results are "function"
and primitive types.typeof
is only reliable for non-null
primitives. So a way to check if a value is an object would be ensuring that the string returned by typeof
does not correspond to a primitive, and that the object is not null
. However, the problem is that a future standard could introduce a new primitive type, and our code would consider it to be an object. New types don't appear frequently, but for example ECMAScript 6 introduced the Symbol type.
Therefore, instead of typeof
, I only recommend approaches whose result varies depending on if the value is an object or not. The following intends to be a
Object
constructor
The Object
constructor coerces the passed argument to an object. If it's already an object, the same object is returned.
Therefore, you can use it to coerce the value to an object, and strictly compare that object with the original value.
The following function requires ECMAScript 3, which introduced ===
:
function isObject(value) { /* Requires ECMAScript 3 or later */
return Object(value) === value;
}
I like this approach because it's simple and self-descriptive, and an analogous check will also work for booleans, numbers and strings. However, be aware it relies on the global Object
not being shadowed nor altered.
Constructors
When you instantiate a constructor, it can return a value different than the just-created instance. But that value will be ignored unless it's an object.
The following function requires ECMAScript 3, which allowed constructors to return non-objects. Before ECMAScript 3 that threw an error, but try
statements didn't exist back then.
function isObject(value) { /* Requires ECMAScript 3 or later */
return new function() { return value; }() === value;
}
While a bit less simple than the previous example, this one does not rely on any global property, and thus might be the safest.
this
value
Old ECMAScript specifications required the this
value to be an object. ECMAScript 3 introduced Function.prototype.call
, which allowed to call a function with an arbitrary this
value, but coerced to an object.
ECMAScript 5 introduced a strict mode which removed this behavior, but in sloppy mode we still can (but arguably shouldn't) rely on it.
function isObject(value) { /* Requires ECMAScript 3 or later in sloppy mode */
return function() { return this === value; }.call(value);
}
[[Prototype]]
All ordinary objects have an internal slot called [[Prototype]], whose value determines from which other object it inherits from. The value can only be an object or null
. Therefore, you can attempt to create an object which inherits from the desired value, and check if it worked.
Both Object.create
and Object.getPrototypeOf
require ECMAScript 5.
function isObject(value) { /* Requires ECMAScript 5 or later */
try {
Object.create(value);
return value !== null;
} catch(err) {
return false;
}
}
function isObject(value) { /* Requires ECMAScript 5 or later */
function Constructor() {}
Constructor.prototype = value;
return Object.getPrototypeOf(new Constructor()) === value;
}
Some new ECMAScript 6 ways
ECMAScript 6 introduces some new indirect ways to check is a value is an object. They use the previously seen approach to pass the value to some code which requires an object, wrapped inside a try
statement to catch errors. Some hidden examples, not worth commenting
function isObject(value) { /* Requires ECMAScript 6 or later */
try {
Object.setPrototypeOf({}, value);
return value !== null;
} catch(err) {
return false;
}
}
function isObject(value) { /* Requires ECMAScript 6 or later */
try {
new WeakSet([value]);
return true;
} catch(err) {
return false;
}
}
Note: I intentionally skipped some approaches like Object.getPrototypeOf(value)
(ES5) and Reflect
methods (ES6) because they call essential internal methods which might do nasty things, e.g. if value
is a proxy. For safety reasons my examples only reference value
without accessing it directly.
Answered 2023-09-20 20:55:12
function isObject(o) {
return null != o &&
typeof o === 'object' &&
Object.prototype.toString.call(o) === '[object Object]';
}
function isDerivedObject(o) {
return !isObject(o) &&
null != o &&
(typeof o === 'object' || typeof o === 'function') &&
/^\[object /.test(Object.prototype.toString.call(o));
}
// Loose equality operator (==) is intentionally used to check
// for undefined too
// Also note that, even null is an object, within isDerivedObject
// function we skip that and always return false for null
In Javascript, null
, Object
, Array
, Date
and function
s are all objects. Although, null
is bit contrived. So, it's better to check for the null
first, to detect it's not null.
Checking for typeof o === 'object'
guarantees that o
is an object. Without this check, Object.prototype.toString
would be meaningless, since it would return object for everthing, even for undefined
and null
! For example: toString(undefined)
returns [object Undefined]
!
After typeof o === 'object'
check, toString.call(o) is a great method to check whether o
is an object, a derived object like Array
, Date
or a function
.
In isDerivedObject
function, it checks for the o
is a function. Because, function also an object, that's why it's there. If it didn't do that, function will return as false. Example: isDerivedObject(function() {})
would return false
, however now it returns true
.
One can always change the definition of what is an object. So, one can change these functions accordingly.
function isObject(o) {
return null != o &&
typeof o === 'object' &&
Object.prototype.toString.call(o) === '[object Object]';
}
function isDerivedObject(o) {
return !isObject(o) &&
null != o &&
(typeof o === 'object' || typeof o === 'function') &&
/^\[object /.test(Object.prototype.toString.call(o));
}
// TESTS
// is null an object?
console.log(
'is null an object?', isObject(null)
);
console.log(
'is null a derived object?', isDerivedObject(null)
);
// is 1234 an object?
console.log(
'is 1234 an object?', isObject(1234)
);
console.log(
'is 1234 a derived object?', isDerivedObject(1234)
);
// is new Number(1234) an object?
console.log(
'is new Number(1234) an object?', isObject(new Number(1234))
);
console.log(
'is new Number(1234) a derived object?', isDerivedObject(1234)
);
// is function object an object?
console.log(
'is (new (function (){})) an object?',
isObject((new (function (){})))
);
console.log(
'is (new (function (){})) a derived object?',
isObject((new (function (){})))
);
// is {} an object?
console.log(
'is {} an object?', isObject({})
);
console.log(
'is {} a derived object?', isDerivedObject({})
);
// is Array an object?
console.log(
'is Array an object?',
isObject([])
)
console.log(
'is Array a derived object?',
isDerivedObject([])
)
// is Date an object?
console.log(
'is Date an object?', isObject(new Date())
);
console.log(
'is Date a derived object?', isDerivedObject(new Date())
);
// is function an object?
console.log(
'is function an object?', isObject(function(){})
);
console.log(
'is function a derived object?', isDerivedObject(function(){})
);
Answered 2023-09-20 20:55:12
Little late... for "plain objects" (i mean, like {'x': 5, 'y': 7}) i have this little snippet:
function isPlainObject(o) {
return (o === null || Array.isArray(o) || typeof o == 'function' || o.constructor === Date ) ?
false
:(typeof o == 'object');
}
It generates the next output:
console.debug(isPlainObject(isPlainObject)); //function, false
console.debug(isPlainObject({'x': 6, 'y': 16})); //literal object, true
console.debug(isPlainObject(5)); //number, false
console.debug(isPlainObject(undefined)); //undefined, false
console.debug(isPlainObject(null)); //null, false
console.debug(isPlainObject('a')); //string, false
console.debug(isPlainObject([])); //array?, false
console.debug(isPlainObject(true)); //bool, false
console.debug(isPlainObject(false)); //bool, false
It always works for me. If will return "true" only if the type of "o" is "object", but no null, or array, or function. :)
Answered 2023-09-20 20:55:12
If you would like to check if the prototype
for an object
solely comes from Object
. Filters out String
, Number
, Array
, Arguments
, etc.
function isObject (n) {
return Object.prototype.toString.call(n) === '[object Object]';
}
Or as a single-expression arrow function (ES6+)
const isObject = n => Object.prototype.toString.call(n) === '[object Object]'
Answered 2023-09-20 20:55:12
return Object.prototype.toString.call(n) === '[object Object]'
- anyone null
check, because Object.prototype.toString.call(null) === '[object Null]'
- anyone var a = [1]
typeof a //"object"
a instanceof Object //true
a instanceof Array //true
var b ={a: 1}
b instanceof Object //true
b instanceof Array //false
var c = null
c instanceof Object //false
c instanceof Array //false
I was asked to provide more details. Most clean and understandable way of checking if our variable is an object is typeof myVar
. It returns a string with a type (e.g. "object"
, "undefined"
).
Unfortunately either Array and null also have a type object
. To take only real objects there is a need to check inheritance chain using instanceof
operator. It will eliminate null, but Array has Object in inheritance chain.
So the solution is:
if (myVar instanceof Object && !(myVar instanceof Array)) {
// code for objects
}
Answered 2023-09-20 20:55:12
/./ instanceof Object //true
- anyone lodash has isPlainObject, which might be what many who come to this page are looking for. It returns false when give a function or array.
Answered 2023-09-20 20:55:12
_.isObject
which matches what JS considers an object. But what I usually need is to differentiate between e.g. an object literal and an array, which is exactly what _.isPlainObject
lets me do. - anyone The Ramda functional library has a wonderful function for detecting JavaScript types.
Paraphrasing the full function:
function type(val) {
return val === null ? 'Null' :
val === undefined ? 'Undefined' :
Object.prototype.toString.call(val).slice(8, -1);
}
I had to laugh when I realized how simple and beautiful the solution was.
Example usage from Ramda documentation:
R.type({}); //=> "Object"
R.type(1); //=> "Number"
R.type(false); //=> "Boolean"
R.type('s'); //=> "String"
R.type(null); //=> "Null"
R.type([]); //=> "Array"
R.type(/[A-z]/); //=> "RegExp"
R.type(() => {}); //=> "Function"
R.type(undefined); //=> "Undefined"
Answered 2023-09-20 20:55:12
Today 2020.09.26 I perform tests on MacOs HighSierra 10.13.6 on Chrome v85, Safari v13.1.2 and Firefox v80 for chosen solutions.
I perform 3 tests cases for solutions A B C D E F G H I J K L M N O P Q R S T U V
Below snippet presents differences between solutions. Solutions A-G give proper answers for chosen cases described by Matt Fenwick
// https://stackoverflow.com/a/14706877/860099
function A(x) {
return x === Object(x);
};
// https://stackoverflow.com/a/42250981/860099
function B(x) {
return _.isObject(x);
}
// https://stackoverflow.com/a/34864175/860099
function C(x) {
return x != null && (typeof x === 'object' || typeof x === 'function');
}
// https://stackoverflow.com/a/39187058/860099
function D(x) {
return new function() { return x; }() === x;
}
// https://stackoverflow.com/a/39187058/860099
function E(x) {
return function() { return this === x; }.call(x);
}
// https://stackoverflow.com/a/39187058/860099
function F(x) { /* Requires ECMAScript 5 or later */
try {
Object.create(x);
return x !== null;
} catch(err) {
return false;
}
}
// https://stackoverflow.com/a/39187058/860099
function G(x) { /* Requires ECMAScript 5 or later */
function Constructor() {}
Constructor.prototype = x;
return Object.getPrototypeOf(new Constructor()) === x;
}
// https://stackoverflow.com/a/8511332/860099
function H(x) {
return typeof x === 'object' && x !== null
}
// https://stackoverflow.com/a/25715455/860099
function I(x) {
return (typeof x === "object" && !Array.isArray(x) && x !== null);
};
// https://stackoverflow.com/a/22482737/860099
function J(x) {
return x instanceof Object;
}
// https://stackoverflow.com/a/50712057/860099
function K(x)
{
let t= JSON.stringify(x);
return t ? t[0] === '{' : false;
}
// https://stackoverflow.com/a/13356338/860099
function L(x) {
return Object.prototype.toString.call(x) === "[object Object]";
};
// https://stackoverflow.com/a/46663081/860099
function M(o, strict = true) {
if (o === null || o === undefined) {
return false;
}
const instanceOfObject = o instanceof Object;
const typeOfObject = typeof o === 'object';
const constructorUndefined = o.constructor === undefined;
const constructorObject = o.constructor === Object;
const typeOfConstructorObject = typeof o.constructor === 'function';
let r;
if (strict === true) {
r = (instanceOfObject || typeOfObject) && (constructorUndefined || constructorObject);
} else {
r = (constructorUndefined || typeOfConstructorObject);
}
return r;
}
// https://stackoverflow.com/a/42250981/860099
function N(x) {
return $.type(x) === 'object';
}
// https://stackoverflow.com/a/34864175/860099
function O(x) {
if (Object.prototype.toString.call(x) !== '[object Object]') {
return false;
} else {
var prototype = Object.getPrototypeOf(x);
return prototype === null || prototype === Object.prototype;
}
}
// https://stackoverflow.com/a/57863169/860099
function P(x) {
while ( Object.prototype.toString.call(x) === '[object Object]')
if ((x = Object.getPrototypeOf(x)) === null)
return true
return false
}
// https://stackoverflow.com/a/43289971/860099
function Q(x){
try{
switch(x.constructor){
case Number:
case Function:
case Boolean:
case Symbol:
case Date:
case String:
case RegExp:
return x.constructor === Object;
case Error:
case EvalError:
case RangeError:
case ReferenceError:
case SyntaxError:
case TypeError:
case URIError:
return (Object === Error ? Error : x.constructor) === Object;
case Array:
case Int8Array:
case Uint8Array:
case Uint8ClampedArray:
case Int16Array:
case Uint16Array:
case Int32Array:
case Uint32Array:
case Float32Array:
case Float64Array:
return (Object === Array ? Array : x.constructor) === Object;
case Object:
default:
return (Object === Object ? Object : x.constructor) === Object;
}
} catch(ex){
return x == Object;
}
}
// https://stackoverflow.com/a/52478680/860099
function R(x) {
return typeof x == 'object' && x instanceof Object && !(x instanceof Array);
}
// https://stackoverflow.com/a/51458052/860099
function S(x)
{
return x != null && x.constructor?.name === "Object"
}
// https://stackoverflow.com/a/42250981/860099
function T(x) {
return x?.constructor?.toString().indexOf("Object") > -1;
}
// https://stackoverflow.com/a/43223661/860099
function U(x)
{
return x?.constructor === Object;
}
// https://stackoverflow.com/a/46663081/860099
function V(x) {
return x instanceof Object && x.constructor === Object;
}
// -------------
// TEST
// -------------
console.log('column: 1 2 3 4 5 6 - 7 8 9 10 11');
[A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V]
.map(f=> console.log(`${f.name}: ${1*f(new Date())} ${1*f(/./)} ${1*f({})} ${1*f(Object.prototype)} ${1*f(Object.create(null))} ${1*f(()=>{})} - ${1*f("abc")} ${1*f(3)} ${1*f(true)} ${1*f(null)} ${1*f(undefined)}`))
console.log(`
Columns legend (test cases):
1: new Date()
2: /./ (RegExp)
3: {}
4: Object.prototype
5: Object.create(null)
6: ()=>{} (function)
7: "abc" (string)
8: 3 (number)
9: true (boolean)
10: null
11: undefined
Rows:
1 = is object
0 = is NOT object
Theoretically columns 1-6 should have have 1, columns 7-11 shoud have 0
`);
<script
src="https://code.jquery.com/jquery-3.5.1.min.js"
integrity="sha256-9/aliU8dGd2tb6OSsuzixeV4y/faTqgFtohetphbbj0="
crossorigin="anonymous"></script>
<script
src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.20/lodash.min.js"
integrity="sha512-90vH1Z83AJY9DmlWa8WkjkV79yfS2n2Oxhsi2dZbIv0nC4E6m5AbH8Nh156kkM7JePmqD6tcZsfad1ueoaovww=="
crossorigin="anonymous"></script>
This shippet only presents functions used in performance tests - it not perform tests itself!
And here are example results for chrome
Answered 2023-09-20 20:55:12
Since there seems a lot of confusion about how to handle this problem correctly, I'll leave my 2 cents (this answer is spec compliant and produces correct results under all circumstances):
Testing for primitives:
undefined
null
boolean
string
number
function isPrimitive(o){return typeof o!=='object'||null}
An object is not a primitive:
function isObject(o){return !isPrimitive(o)}
Or alternatively:
function isObject(o){return o instanceof Object}
function isPrimitive(o){return !isObject(o)}
Testing for any Array:
const isArray=(function(){
const arrayTypes=Object.create(null);
arrayTypes['Array']=true;
arrayTypes['Int8Array']=true;
arrayTypes['Uint8Array']=true;
arrayTypes['Uint8ClampedArray']=true;
arrayTypes['Int16Array']=true;
arrayTypes['Uint16Array']=true;
arrayTypes['Int32Array']=true;
arrayTypes['Uint32Array']=true;
arrayTypes['BigInt64Array']=true;
arrayTypes['BigUint64Array']=true;
arrayTypes['Float32Array']=true;
arrayTypes['Float64Array']=true;
return function(o){
if (!o) return false;
return !isPrimitive(o)&&!!arrayTypes[o.constructor.name];
}
}());
Testing for object excluding: Date
RegExp
Boolean
Number
String
Function
any Array
const isObjectStrict=(function(){
const nativeTypes=Object.create(null);
nativeTypes['Date']=true;
nativeTypes['RegExp']=true;
nativeTypes['Boolean']=true;
nativeTypes['Number']=true;
nativeTypes['String']=true;
nativeTypes['Function']=true;
return function(o){
if (!o) return false;
return !isPrimitive(o)&&!isArray(o)&&!nativeTypes[o.constructor.name];
}
}());
Answered 2023-09-20 20:55:12
After reading and trying out a lot of implementations, I've noticed that very few people try to check for values like JSON
, Math
, document
or objects with prototype chains longer than 1 step.
Instead of checking the typeof
of our variable and then hacking away edge-cases, I thought it'd be better if the check is kept as simple as possible to avoid having to refactor when there's new primitives or native objects added that register as typeof
of 'object'.
After all, the typeof
operator will tell you if something is an object to JavaScript, but JavaScript's definition of an object is too broad for most real-world scenarios (e.g. typeof null === 'object'
).
Below is a function that determines whether variable v
is an object by essentially repeating two checks:
v
is '[object Object]'
.v
is replaced with the next prototype in the chain with v = Object.getPrototypeOf(v)
, but also directly evaluated after. When the new value of v
is null
, it means that every prototype including the root prototype (which could very well have been the only prototype inside the chain) have passed the check in the while loop and we can return true. Otherwise, a new iteration starts.function isObj (v) {
while ( Object.prototype.toString.call(v) === '[object Object]')
if ((v = Object.getPrototypeOf(v)) === null)
return true
return false
}
console.log('FALSE:')
console.log('[] -> ', isObj([]))
console.log('null -> ', isObj(null))
console.log('document -> ', isObj(document))
console.log('JSON -> ', isObj(JSON))
console.log('function -> ', isObj(function () {}))
console.log('new Date() -> ', isObj(new Date()))
console.log('RegExp -> ', isObj(/./))
console.log('TRUE:')
console.log('{} -> ', isObj({}))
console.log('new Object() -> ', isObj(new Object()))
console.log('new Object(null) -> ', isObj(new Object(null)))
console.log('new Object({}) -> ', isObj(new Object({foo: 'bar'})))
console.log('Object.prototype -> ', isObj(Object.prototype))
console.log('Object.create(null) -> ', isObj(Object.create(null)))
console.log('Object.create({}) -> ', isObj(Object.create({foo: 'bar'})))
console.log('deep inheritance -> ', isObj(Object.create(Object.create({foo: 'bar'}))))
Answered 2023-09-20 20:55:12
When everything else fails, I use this:
var isObject = function(item) {
return item.constructor.name === "Object";
};
Answered 2023-09-20 20:55:12
item.constructor === Object
? - anyone null
throws an exception Uncaught TypeError: Cannot read property 'constructor' of null(…)
- anyone indexOf
or because of constructor.name
? - anyone varName && varName.constructor.name === "Object"
if your variable may have falsy value varName != null && varName != undefined && varName.constructor.name === "Object" - anyone This will work. It is a function that returns true, false, or possibly null.
const isObject = obj => obj && obj.constructor && obj.constructor === Object;
console.log(isObject({})); // true
console.log(isObject([])); // false
console.log(isObject(new Function)); // false
console.log(isObject(new Number(123))); // false
console.log(isObject(null)); // null
Answered 2023-09-20 20:55:12
null
as the result for the final test rather than false
. See When should I make edits to code? - anyone For the purpose of my code I found out this decision which corresponds with some of the answers above:
ES6 variant:
const checkType = o => Object.prototype
.toString
.call(o)
.replace(/\[|object\s|\]/g, '')
.toLowerCase();
ES5 variant:
function checkType(o){
return Object.prototype
.toString
.call(o)
.replace(/\[|object\s|\]/g, '')
.toLowerCase();
}
You can use it very simply:
checkType([]) === 'array'; // true
checkType({}) === 'object'; // true
checkType(1) === 'number'; // true
checkType('') === 'string'; // true
checkType({}.p) === 'undefined'; // true
checkType(null) === 'null'; // true
and so on..
Answered 2023-09-20 20:55:12
slice(8, -1)
could be used instead of replace(/\[|object\s|\]/g, '')
. It runs horribly faster. - anyone if(typeof value === 'object' && value.constructor === Object)
{
console.log("This is an object");
}
Answered 2023-09-20 20:55:12
false
for the object Object.assign({}, {constructor: null})
. - anyone const isObject = function(obj) {
const type = typeof obj;
return type === 'function' || type === 'object' && !!obj;
};
!!obj
is shorthand for checking if obj
is truthy (to filter out null
)
Answered 2023-09-20 20:55:12
It is an old question but thought to leave this here. Most people are checking if the variable is {}
meaning a key-value paired and not what is the underline construct that JavaScript is using for a given thing, cuz to be honest mostly everything in JavaScript is an object. So taking that out of the way. If you do...
let x = function() {}
typeof x === 'function' //true
x === Object(x) // true
x = []
x === Object(x) // true
// also
x = null
typeof null // 'object'
Most of the time what we want is to know if we have a resource object from an API or our database call returned from the ORM. We can then test if is not an Array
, is not null
, is not typeof 'function'
, and is an Object
// To account also for new Date() as @toddmo pointed out
x instanceof Object && x.constructor === Object
x = 'test' // false
x = 3 // false
x = 45.6 // false
x = undefiend // false
x = 'undefiend' // false
x = null // false
x = function(){} // false
x = [1, 2] // false
x = new Date() // false
x = {} // true
Answered 2023-09-20 20:55:12
true
for new Date()
- anyone new Date()
- anyone