I want to write a script that loops through 15 strings (array possibly?) Is that possible?
Something like:
for databaseName in listOfNames
then
# Do something
end
You can use it like this:
## declare an array variable
declare -a arr=("element1" "element2" "element3")
## now loop through the above array
for i in "${arr[@]}"
do
echo "$i"
# or do whatever with individual element of the array
done
# You can access them using echo "${arr[0]}", "${arr[1]}" also
Also works for multi-line array declaration
declare -a arr=("element1"
"element2" "element3"
"element4"
)
Answered 2023-09-20 20:54:21
"${arr[@]}"
are really important. Without them, the for loop will break up the array by substrings separated by any spaces within the strings instead of by whole string elements within the array. ie: if you had declare -a arr=("element 1" "element 2" "element 3")
, then for i in ${arr[@]}
would mistakenly iterate 6 times since each string becomes 2 substrings separated by the space in the string, whereas for i in "${arr[@]}"
would iterate 3 times, correctly, as desired, maintaining each string as a single unit despite having a space in it. - anyone That is possible, of course.
for databaseName in a b c d e f; do
# do something like: echo $databaseName
done
See Bash Loops for, while and until for details.
Answered 2023-09-20 20:54:21
for year in $(seq 2000 2013)
. - anyone DATABASES="a b c d e f"
. - anyone None of those answers include a counter...
#!/bin/bash
## declare an array variable
declare -a array=("one" "two" "three")
# get length of an array
arraylength=${#array[@]}
# use for loop to read all values and indexes
for (( i=0; i<${arraylength}; i++ ));
do
echo "index: $i, value: ${array[$i]}"
done
Output:
index: 0, value: one
index: 1, value: two
index: 2, value: three
Answered 2023-09-20 20:54:21
echo "$i / ${arraylength} : ${array[$i-1]}"
-- otherwise, if your $i
contains a glob it'll be expanded, if it contains a tab it'll be changed to a space, etc. - anyone $i
won't contain a glob, because it's the loop counter in this example and so you control its value. - anyone Yes
for Item in Item1 Item2 Item3 Item4 ;
do
echo $Item
done
Output:
Item1
Item2
Item3
Item4
To preserve spaces; single or double quote list entries and double quote list expansions.
for Item in 'Item 1' 'Item 2' 'Item 3' 'Item 4' ;
do
echo "$Item"
done
Output:
Item 1
Item 2
Item 3
Item 4
To make list over multiple lines
for Item in Item1 \
Item2 \
Item3 \
Item4
do
echo $Item
done
Output:
Item1
Item2
Item3
Item4
List=( Item1 Item2 Item3 )
or
List=(
Item1
Item2
Item3
)
Display the list variable:
echo ${List[*]}
Output:
Item1 Item2 Item3
Loop through the list:
for Item in ${List[*]}
do
echo $Item
done
Output:
Item1
Item2
Item3
Create a function to go through a list:
Loop(){
for item in ${*} ;
do
echo ${item}
done
}
Loop ${List[*]}
Using the declare keyword (command) to create the list, which is technically called an array:
declare -a List=(
"element 1"
"element 2"
"element 3"
)
for entry in "${List[@]}"
do
echo "$entry"
done
Output:
element 1
element 2
element 3
Creating an associative array. A dictionary:
declare -A continent
continent[Vietnam]=Asia
continent[France]=Europe
continent[Argentina]=America
for item in "${!continent[@]}";
do
printf "$item is in ${continent[$item]} \n"
done
Output:
Argentina is in America
Vietnam is in Asia
France is in Europe
CSV variables or files in to a list.
Changing the internal field separator from a space, to what ever you want.
In the example below it is changed to a comma
List="Item 1,Item 2,Item 3"
Backup_of_internal_field_separator=$IFS
IFS=,
for item in $List;
do
echo $item
done
IFS=$Backup_of_internal_field_separator
Output:
Item 1
Item 2
Item 3
If need to number them:
`
this is called a back tick. Put the command inside back ticks.
`command`
It is next to the number one on your keyboard and or above the tab key, on a standard American English language keyboard.
List=()
Start_count=0
Step_count=0.1
Stop_count=1
for Item in `seq $Start_count $Step_count $Stop_count`
do
List+=(Item_$Item)
done
for Item in ${List[*]}
do
echo $Item
done
Output is:
Item_0.0
Item_0.1
Item_0.2
Item_0.3
Item_0.4
Item_0.5
Item_0.6
Item_0.7
Item_0.8
Item_0.9
Item_1.0
Becoming more familiar with bashes behavior:
Create a list in a file
cat <<EOF> List_entries.txt
Item1
Item 2
'Item 3'
"Item 4"
Item 7 : *
"Item 6 : * "
"Item 6 : *"
Item 8 : $PWD
'Item 8 : $PWD'
"Item 9 : $PWD"
EOF
Read the list file in to a list and display
List=$(cat List_entries.txt)
echo $List
echo '$List'
echo "$List"
echo ${List[*]}
echo '${List[*]}'
echo "${List[*]}"
echo ${List[@]}
echo '${List[@]}'
echo "${List[@]}"
BASH commandline reference manual: Special meaning of certain characters or words to the shell.
Answered 2023-09-20 20:54:21
"${List[@]}"
to be correct, with the quotes. ${List[@]}
is wrong. ${List[*]}
is wrong. Try List=( "* first item *" "* second item *" )
-- you'll get correct behavior for for item in "${List[@]}"; do echo "$item"; done
, but not from any other variant. - anyone List=( "first item" "second item" )
will be broken into first
, item
, second
, item
as well). - anyone ls
output, in contravention of best practices. - anyone In the same spirit as 4ndrew's answer:
listOfNames="RA
RB
R C
RD"
# To allow for other whitespace in the string:
# 1. add double quotes around the list variable, or
# 2. see the IFS note (under 'Side Notes')
for databaseName in "$listOfNames" # <-- Note: Added "" quotes.
do
echo "$databaseName" # (i.e. do action / processing of $databaseName here...)
done
# Outputs
# RA
# RB
# R C
# RD
B. No whitespace in the names:
listOfNames="RA
RB
R C
RD"
for databaseName in $listOfNames # Note: No quotes
do
echo "$databaseName" # (i.e. do action / processing of $databaseName here...)
done
# Outputs
# RA
# RB
# R
# C
# RD
Notes
listOfNames="RA RB R C RD"
has the same output.Other ways to bring in data include:
Read from stdin
# line delimited (each databaseName is stored on a line)
while read databaseName
do
echo "$databaseName" # i.e. do action / processing of $databaseName here...
done # <<< or_another_input_method_here
IFS='\n'
, or for MacOS IFS='\r'
)#!/bin/bash
at the top of the script file indicates the execution environment.Other Sources (while read loop)
Answered 2023-09-20 20:54:21
IFS
. (For everyone, IFS
lets one specify a specific delimiter, which allows other whitespace to be included in strings without being separated into substrings). - anyone $databaseName
just contains the whole list, thus does only a single iteration. - anyone You can use the syntax of ${arrayName[@]}
#!/bin/bash
# declare an array called files, that contains 3 values
files=( "/etc/passwd" "/etc/group" "/etc/hosts" )
for i in "${files[@]}"
do
echo "$i"
done
Answered 2023-09-20 20:54:21
Surprised that nobody's posted this yet -- if you need the indices of the elements while you're looping through the array, you can do this:
arr=(foo bar baz)
for i in ${!arr[@]}
do
echo $i "${arr[i]}"
done
Output:
0 foo
1 bar
2 baz
I find this a lot more elegant than the "traditional" for-loop style (for (( i=0; i<${#arr[@]}; i++ ))
).
(${!arr[@]}
and $i
don't need to be quoted because they're just numbers; some would suggest quoting them anyway, but that's just personal preference.)
Answered 2023-09-20 20:54:21
I used this approach for my GitHub updates, and I found it simple.
## declare an array variable
arr_variable=("kofi" "kwame" "Ama")
## now loop through the above array
for i in "${arr_variable[@]}"
do
echo "$i"
done
You can iterate through bash array values using a counter with three-expression (C style) to read all values and indexes for loops syntax:
declare -a kofi=("kofi" "kwame" "Ama")
# get the length of the array
length=${#kofi[@]}
for (( j=0; j<${length}; j++ ));
do
print (f "Current index %d with value %s\n" $j "${kofi[$j]}")
done
Answered 2023-09-20 20:54:21
for i in "${!arr_variable[@]}"; do printf '%d: %s\n' "$i" "${arr_variable[i]}"; done
- anyone This is also easy to read:
FilePath=(
"/tmp/path1/" #FilePath[0]
"/tmp/path2/" #FilePath[1]
)
#Loop
for Path in "${FilePath[@]}"
do
echo "$Path"
done
Answered 2023-09-20 20:54:21
IFS=$'\n'
This may work for other solutions too in this scenario. - anyone listOfNames="db_one db_two db_three"
for databaseName in $listOfNames
do
echo $databaseName
done
or just
for databaseName in db_one db_two db_three
do
echo $databaseName
done
Answered 2023-09-20 20:54:21
Simple way :
arr=("sharlock" "bomkesh" "feluda" ) ##declare array
len=${#arr[*]} # it returns the array length
#iterate with while loop
i=0
while [ $i -lt $len ]
do
echo ${arr[$i]}
i=$((i+1))
done
#iterate with for loop
for i in $arr
do
echo $i
done
#iterate with splice
echo ${arr[@]:0:3}
Answered 2023-09-20 20:54:21
In addition to anubhava's correct answer: If basic syntax for loop is:
for var in "${arr[@]}" ;do ...$var... ;done
there is a special case in bash:
When running a script or a function, arguments passed at command lines will be assigned to $@
array variable, you can access by $1
, $2
, $3
, and so on.
This can be populated (for test) by
set -- arg1 arg2 arg3 ...
A loop over this array could be written simply:
for item ;do
echo "This is item: $item."
done
Note that the reserved work in
is not present and no array name too!
Sample:
set -- arg1 arg2 arg3 ...
for item ;do
echo "This is item: $item."
done
This is item: arg1.
This is item: arg2.
This is item: arg3.
This is item: ....
Note that this is same than
for item in "$@";do
echo "This is item: $item."
done
#!/bin/bash
for item ;do
printf "Doing something with '%s'.\n" "$item"
done
Save this in a script myscript.sh
, chmod +x myscript.sh
, then
./myscript.sh arg1 arg2 arg3 ...
Doing something with 'arg1'.
Doing something with 'arg2'.
Doing something with 'arg3'.
Doing something with '...'.
myfunc() { for item;do cat <<<"Working about '$item'."; done ; }
Then
myfunc item1 tiem2 time3
Working about 'item1'.
Working about 'tiem2'.
Working about 'time3'.
Answered 2023-09-20 20:54:21
The declare array doesn't work for Korn shell. Use the below example for the Korn shell:
promote_sla_chk_lst="cdi xlob"
set -A promote_arry $promote_sla_chk_lst
for i in ${promote_arry[*]};
do
echo $i
done
Answered 2023-09-20 20:54:21
for i in ${foo[*]}
is basically always the wrong thing -- for i in "${foo[@]}"
is the form that preserves the original list's boundaries and prevents glob expansion. And the echo needs to be echo "$i"
- anyone Try this. It is working and tested.
for k in "${array[@]}"
do
echo $k
done
# For accessing with the echo command: echo ${array[0]}, ${array[1]}
Answered 2023-09-20 20:54:21
array=( "hello world" )
, or arrray=( "*" )
; in the first case it will print hello
and world
separately, in the second it will print a list of files instead of the *
- anyone This is similar to user2533809's answer, but each file will be executed as a separate command.
#!/bin/bash
names="RA
RB
R C
RD"
while read -r line; do
echo line: "$line"
done <<< "$names"
Answered 2023-09-20 20:54:21
If you are using Korn shell, there is "set -A databaseName ", else there is "declare -a databaseName"
To write a script working on all shells,
set -A databaseName=("db1" "db2" ....) ||
declare -a databaseName=("db1" "db2" ....)
# now loop
for dbname in "${arr[@]}"
do
echo "$dbname" # or whatever
done
It should be work on all shells.
Answered 2023-09-20 20:54:21
$ bash --version
GNU bash, version 4.3.33(0)-release (amd64-portbld-freebsd10.0) $ set -A databaseName=("db1" "db2" ....) || declare -a databaseName=("db1" "db2" ....)
bash: syntax error near unexpected token `(' - anyone $ ./myscript.sh
instead of $ sh myscript.sh
and of course chmod +x myscript.sh
- anyone What I really needed for this was something like this:
for i in $(the_array); do something; done
For instance:
for i in $(ps -aux | grep vlc | awk '{ print $2 }'); do kill -9 $i; done
(Would kill all processes with vlc in their name)
Answered 2023-09-20 20:54:21
Possible first line of every Bash script/session:
say() { for line in "${@}" ; do printf "%s\n" "${line}" ; done ; }
Use e.g.:
$ aa=( 7 -4 -e ) ; say "${aa[@]}"
7
-4
-e
May consider: echo
interprets -e
as option here
Answered 2023-09-20 20:54:21
Single line looping,
declare -a listOfNames=('db_a' 'db_b' 'db_c')
for databaseName in ${listOfNames[@]}; do echo $databaseName; done;
you will get an output like this,
db_a
db_b
db_c
Answered 2023-09-20 20:54:21
How you loop through an array, depends on the presence of new line characters. With new line characters separating the array elements, the array can be referred to as "$array"
, otherwise it should be referred to as "${array[@]}"
. The following script will make it clear:
#!/bin/bash
mkdir temp
mkdir temp/aaa
mkdir temp/bbb
mkdir temp/ccc
array=$(ls temp)
array1=(aaa bbb ccc)
array2=$(echo -e "aaa\nbbb\nccc")
echo '$array'
echo "$array"
echo
for dirname in "$array"; do
echo "$dirname"
done
echo
for dirname in "${array[@]}"; do
echo "$dirname"
done
echo
echo '$array1'
echo "$array1"
echo
for dirname in "$array1"; do
echo "$dirname"
done
echo
for dirname in "${array1[@]}"; do
echo "$dirname"
done
echo
echo '$array2'
echo "$array2"
echo
for dirname in "$array2"; do
echo "$dirname"
done
echo
for dirname in "${array2[@]}"; do
echo "$dirname"
done
rmdir temp/aaa
rmdir temp/bbb
rmdir temp/ccc
rmdir temp
Answered 2023-09-20 20:54:21
I loop through an array of my projects for a git pull
update:
#!/bin/sh
projects="
web
ios
android
"
for project in $projects do
cd $HOME/develop/$project && git pull
end
Answered 2023-09-20 20:54:21
IFS
variable behavior in your script - anyone