How do I grep
and show the preceding and following 5 lines surrounding each matched line?
man grep | grep -C 1 context
:) - anyone man grep | grep -C 1 "\-C"
;) - anyone For BSD or GNU grep
you can use -B num
to set how many lines before the match and -A num
for the number of lines after the match.
grep -B 3 -A 2 foo README.txt
If you want the same number of lines before and after you can use -C num
.
grep -C 3 foo README.txt
This will show 3 lines before and 3 lines after.
Answered 2023-09-20 20:12:41
-A
and -B
will work, as will -C n
(for n
lines of context), or just -n
(for n
lines of context... as long as n is 1 to 9).
Answered 2023-09-20 20:12:41
-n
format and found out it only works till 9
. For 15
it returns 5 lines - anyone -A
, -B
or -C
). Usually, the option specifier is followed by a value (-o a.out
to specify output file in GCC), but it can also function as a simple switch / flag (-g
to enable debugging info in GCC). However spaces between options are optional, so for options without a value, it is possible to merge them (-ABC
), which means that -15
is interpreted -1 -5
(two separate options) and the -5
overrides the -1
. - anyone -n
option currently works for more than 9 lines on (GNU grep) 3.1. - anyone grep astring myfile -A 5 -B 5
That will grep "myfile" for "astring", and show 5 lines before and after each match
Answered 2023-09-20 20:12:41
ripgrep
If you care about the performance, use ripgrep
which has similar syntax to grep
, e.g.
rg -C5 "pattern" .
-C
,--context NUM
- Show NUM lines before and after each match.
There are also parameters such as -A
/--after-context
and -B
/--before-context
.
The tool is built on top of Rust's regex engine which makes it very efficient on the large data.
Answered 2023-09-20 20:12:41
I normally use
grep searchstring file -C n # n for number of lines of context up and down
Many of the tools like grep also have really great man files too. I find myself referring to grep's man page a lot because there is so much you can do with it.
man grep
Many GNU tools also have an info page that may have more useful information in addition to the man page.
info grep
Answered 2023-09-20 20:12:41
Use grep
$ grep --help | grep -i context
Context control:
-B, --before-context=NUM print NUM lines of leading context
-A, --after-context=NUM print NUM lines of trailing context
-C, --context=NUM print NUM lines of output context
-NUM same as --context=NUM
Answered 2023-09-20 20:12:41
Let's understand using an example.
We can use grep with options:
-A 5 # this will give you 5 lines after searched string.
-B 5 # this will give you 5 lines before searched string.
-C 5 # this will give you 5 lines before & after searched string
Example. File.txt contains 6 lines and following are the operations.
[abc@xyz]~/% cat file.txt # print all file data
this is first line
this is 2nd line
this is 3rd line
this is 4th line
this is 5th line
this is 6th line
[abc@xyz]~% grep "3rd" file.txt # we are searching for keyword '3rd' in the file
this is 3rd line
[abc@xyz]~% grep -A 2 "3rd" file.txt # print 2 lines after finding the searched string
this is 3rd line
this is 4th line
this is 5th line
[abc@xyz]~% grep -B 2 "3rd" file.txt # Print 2 lines before the search string.
this is first line
this is 2nd line
this is 3rd line
[abc@xyz]~% grep -C 2 "3rd" file.txt # print 2 line before and 2 line after the searched string
this is first line
this is 2nd line
this is 3rd line
this is 4th line
this is 5th line
Trick to remember options:
-A
→ A means "After"-B
→ B means "Before"-C
→ C means "in between"Answered 2023-09-20 20:12:41
If you search code often, AG the silver searcher is much more efficient (ie faster) than grep.
You show context lines by using the -C
option.
Eg:
ag -C 3 "foo" myFile
line 1
line 2
line 3
line that has "foo"
line 5
line 6
line 7
Answered 2023-09-20 20:12:41
Search for "17655" in /some/file.txt
showing 10 lines context before and after (using Awk
), output preceded with line number followed by a colon. Use this on Solaris when grep
does not support the -[ACB]
options.
awk '
/17655/ {
for (i = (b + 1) % 10; i != b; i = (i + 1) % 10) {
print before[i]
}
print (NR ":" ($0))
a = 10
}
a-- > 0 {
print (NR ":" ($0))
}
{
before[b] = (NR ":" ($0))
b = (b + 1) % 10
}' /some/file.txt;
Answered 2023-09-20 20:12:41
I do it the compact way:
grep -5 string file
That is the equivalent of:
grep -A 5 -B 5 string file
Answered 2023-09-20 20:12:41
Here is the @Ygor solution in awk
awk 'c-->0;$0~s{if(b)for(c=b+1;c>1;c--)print r[(NR-c+1)%b];print;c=a}b{r[NR%b]=$0}' b=3 a=3 s="pattern" myfile
Note: Replace a
and b
variables with number of lines before and after.
It's especially useful for system which doesn't support grep's -A
, -B
and -C
parameters.
Answered 2023-09-20 20:12:41
Grep has an option called Context Line Control
, you can use the --context
in that, simply,
| grep -C 5
or
| grep -5
Should do the trick
Answered 2023-09-20 20:12:41
$ grep thestring thefile -5
-5
gets you 5
lines above and below the match 'thestring' is equivalent to -C 5
or -A 5 -B 5
.
Answered 2023-09-20 20:12:41