I've got a nested loop construct like this:
for (Type type : types) {
for (Type t : types2) {
if (some condition) {
// Do something and break...
break; // Breaks out of the inner loop
}
}
}
Now how can I break out of both loops? I've looked at similar questions, but none concerns Java specifically. I couldn't apply these solutions because most used gotos.
I don't want to put the inner loop in a different method.
I don't want to return the loops. When breaking I'm finished with the execution of the loop block.
Like other answerers, I'd definitely prefer to put the loops in a different method, at which point you can just return to stop iterating completely. This answer just shows how the requirements in the question can be met.
You can use break
with a label for the outer loop. For example:
public class Test {
public static void main(String[] args) {
outerloop:
for (int i=0; i < 5; i++) {
for (int j=0; j < 5; j++) {
if (i * j > 6) {
System.out.println("Breaking");
break outerloop;
}
System.out.println(i + " " + j);
}
}
System.out.println("Done");
}
}
This prints:
0 0
0 1
0 2
0 3
0 4
1 0
1 1
1 2
1 3
1 4
2 0
2 1
2 2
2 3
Breaking
Done
Answered 2023-09-20 20:58:50
Technically the correct answer is to label the outer loop. In practice if you want to exit at any point inside an inner loop then you would be better off externalizing the code into a method (a static method if needs be) and then call it.
That would pay off for readability.
The code would become something like that:
private static String search(...)
{
for (Type type : types) {
for (Type t : types2) {
if (some condition) {
// Do something and break...
return search;
}
}
}
return null;
}
Matching the example for the accepted answer:
public class Test {
public static void main(String[] args) {
loop();
System.out.println("Done");
}
public static void loop() {
for (int i = 0; i < 5; i++) {
for (int j = 0; j < 5; j++) {
if (i * j > 6) {
System.out.println("Breaking");
return;
}
System.out.println(i + " " + j);
}
}
}
}
Answered 2023-09-20 20:58:50
You can use a named block around the loops:
search: {
for (Type type : types) {
for (Type t : types2) {
if (some condition) {
// Do something and break...
break search;
}
}
}
}
Answered 2023-09-20 20:58:50
I never use labels. It seems like a bad practice to get into. Here's what I would do:
boolean finished = false;
for (int i = 0; i < 5 && !finished; i++) {
for (int j = 0; j < 5; j++) {
if (i * j > 6) {
finished = true;
break;
}
}
}
By having flag variable ,We can easily control execution of any number of loops ,Just we need to keep this flag value check at loop condition statement as done in main loop->i < 5 && !finished.
Answered 2023-09-20 20:58:50
You can use labels:
label1:
for (int i = 0;;) {
for (int g = 0;;) {
break label1;
}
}
Answered 2023-09-20 20:58:50
Use a function:
public void doSomething(List<Type> types, List<Type> types2){
for(Type t1 : types){
for (Type t : types2) {
if (some condition) {
// Do something and return...
return;
}
}
}
}
Answered 2023-09-20 20:58:50
You can use a temporary variable:
boolean outerBreak = false;
for (Type type : types) {
if(outerBreak) break;
for (Type t : types2) {
if (some condition) {
// Do something and break...
outerBreak = true;
break; // Breaks out of the inner loop
}
}
}
Depending on your function, you can also exit/return from the inner loop:
for (Type type : types) {
for (Type t : types2) {
if (some condition) {
// Do something and break...
return;
}
}
}
Answered 2023-09-20 20:58:50
Using 'break' keyword alone is not the appropriate way when you need to exit from more than one loops. You can exit from immediate loop No matter with how many loops your statement is surrounded with. You can use 'break' with a label! Here I've used the label "abc" You can write your code as following, within any function in Java
This code shows how to exit from the most outer loop
abc:
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++) {
for (int k = 0; k < 10; k++) {
if (k == 1){
break abc;
}
}
}
}
Also you can use break statement to exit from any loop in a nested loop.
for (int i = 0; i < 10; i++) {
abc:for (int j = 0; j < 10; j++) {
for (int k = 0; k < 10; k++) {
if (k == 1){
break abc;
}
}
}
}
The following code shows an example of exiting from the innermost loop. In other works,after executing the following code, you are at the outside of the loop of 'k' variables and still inside the loop of 'j' and 'i' variables.
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++) {
for (int k = 0; k < 10; k++) {
if (k == 1){
break;
}
}
}
}
Answered 2023-09-20 20:58:50
If you don't like break
s and goto
s, you can use a "traditional" for loop instead the for-in, with an extra abort condition:
int a, b;
bool abort = false;
for (a = 0; a < 10 && !abort; a++) {
for (b = 0; b < 10 && !abort; b++) {
if (condition) {
doSomeThing();
abort = true;
}
}
}
Answered 2023-09-20 20:58:50
I needed to do a similar thing, but I chose not to use the enhanced for loop to do it.
int s = type.size();
for (int i = 0; i < s; i++) {
for (int j = 0; j < t.size(); j++) {
if (condition) {
// do stuff after which you want
// to completely break out of both loops
s = 0; // enables the _main_ loop to terminate
break;
}
}
}
Answered 2023-09-20 20:58:50
s
to a value which is lower than i
or change i
to a value greater or equal than s
, both should do the trick. You're right about changing s
, because it can be used elsewhere later, but changing i
won't harm, just will make sure the first for
won't continue looping. - anyone I prefer to add an explicit "exit" to the loop tests. It makes it clear to any casual reader that the loop may terminate early.
boolean earlyExit = false;
for(int i = 0 ; i < 10 && !earlyExit; i++) {
for(int j = 0 ; i < 10 && !earlyExit; j++) { earlyExit = true; }
}
Answered 2023-09-20 20:58:50
Java 8 Stream
solution:
List<Type> types1 = ...
List<Type> types2 = ...
types1.stream()
.flatMap(type1 -> types2.stream().map(type2 -> new Type[]{type1, type2}))
.filter(types -> /**some condition**/)
.findFirst()
.ifPresent(types -> /**do something**/);
Answered 2023-09-20 20:58:50
Labeled break concept is used to break out nested loops in java, by using labeled break you can break nesting of loops at any position. Example 1:
loop1:
for(int i= 0; i<6; i++){
for(int j=0; j<5; j++){
if(i==3)
break loop1;
}
}
suppose there are 3 loops and you want to terminate the loop3: Example 2:
loop3:
for(int i= 0; i<6; i++){
loop2:
for(int k= 0; k<6; k++){
loop1:
for(int j=0; j<5; j++){
if(i==3)
break loop3;
}
}
}
Answered 2023-09-20 20:58:50
Usually in such cases, it is coming in scope of more meaningful logic, let's say some searching or manipulating over some of the iterated 'for'-objects in question, so I usually use the functional approach:
public Object searching(Object[] types) { // Or manipulating
List<Object> typesReferences = new ArrayList<Object>();
List<Object> typesReferences2 = new ArrayList<Object>();
for (Object type : typesReferences) {
Object o = getByCriterion(typesReferences2, type);
if(o != null) return o;
}
return null;
}
private Object getByCriterion(List<Object> typesReferences2, Object criterion) {
for (Object typeReference : typesReferences2) {
if(typeReference.equals(criterion)) {
// here comes other complex or specific logic || typeReference.equals(new Object())
return typeReference;
}
}
return null;
}
Major cons:
The pros:
So it is just handling the case via a different approach.
Basically a question to the author of this question: what do you consider of this approach?
Answered 2023-09-20 20:58:50
Demo
public static void main(String[] args) {
outer:
while (true) {
while (true) {
break outer;
}
}
}
Answered 2023-09-20 20:58:50
You can break from all loops without using any label: and flags.
It's just tricky solution.
Here condition1 is the condition which is used to break from loop K and J. And condition2 is the condition which is used to break from loop K , J and I.
For example:
public class BreakTesting {
public static void main(String[] args) {
for (int i = 0; i < 9; i++) {
for (int j = 0; j < 9; j++) {
for (int k = 0; k < 9; k++) {
if (condition1) {
System.out.println("Breaking from Loop K and J");
k = 9;
j = 9;
}
if (condition2) {
System.out.println("Breaking from Loop K, J and I");
k = 9;
j = 9;
i = 9;
}
}
}
}
System.out.println("End of I , J , K");
}
}
Answered 2023-09-20 20:58:50
(int k = 0; k < 10; k++)
and you didn't fix all of the k = 9
to k = 10
. You might get into an infinite loop. - anyone Use Labels.
INNER:for(int j = 0; j < numbers.length; j++) {
System.out.println("Even number: " + i + ", break from INNER label");
break INNER;
}
Refer to this article
Answered 2023-09-20 20:58:50
It's fairly easy to use label
, You can break the outer loop from inner loop using the label, Consider the example below,
public class Breaking{
public static void main(String[] args) {
outerscope:
for (int i=0; i < 5; i++) {
for (int j=0; j < 5; j++) {
if (condition) {
break outerscope;
}
}
}
}
}
Another approach is to use the breaking variable/flag to keep track of required break. consider the following example.
public class Breaking{
public static void main(String[] args) {
boolean isBreaking = false;
for (int i=0; i < 5; i++) {
for (int j=0; j < 5; j++) {
if (condition) {
isBreaking = true;
break;
}
}
if(isBreaking){
break;
}
}
}
}
However, I prefer using the first approach.
Answered 2023-09-20 20:58:50
boolean broken = false; // declared outside of the loop for efficiency
for (Type type : types) {
for (Type t : types2) {
if (some condition) {
broken = true;
break;
}
}
if (broken) {
break;
}
}
Answered 2023-09-20 20:58:50
If it is inside some function why don't you just return it:
for (Type type : types) {
for (Type t : types2) {
if (some condition) {
return value;
}
}
}
Answered 2023-09-20 20:58:50
Best and Easy Method..
outerloop:
for(int i=0; i<10; i++){
// here we can break Outer loop by
break outerloop;
innerloop:
for(int i=0; i<10; i++){
// here we can break innerloop by
break innerloop;
}
}
Answered 2023-09-20 20:58:50
Rather unusual approach but in terms of code length (not performance) this is the easiest thing you could do:
for(int i = 0; i++; i < j) {
if(wanna exit) {
i = i + j; // if more nested, also add the
// maximum value for the other loops
}
}
Answered 2023-09-20 20:58:50
Another one solution, mentioned without example (it actually works in prod code).
try {
for (Type type : types) {
for (Type t : types2) {
if (some condition #1) {
// Do something and break the loop.
throw new BreakLoopException();
}
}
}
}
catch (BreakLoopException e) {
// Do something on look breaking.
}
Of course BreakLoopException
should be internal, private and accelerated with no-stack-trace:
private static class BreakLoopException extends Exception {
@Override
public StackTraceElement[] getStackTrace() {
return new StackTraceElement[0];
}
}
Answered 2023-09-20 20:58:50
Demo for break
, continue
, and label
:
Java keywords break
and continue
have a default value. It's the "nearest loop", and today, after a few years of using Java, I just got it!
It's seem used rare, but useful.
import org.junit.Test;
/**
* Created by cui on 17-5-4.
*/
public class BranchLabel {
@Test
public void test() {
System.out.println("testBreak");
testBreak();
System.out.println("testBreakLabel");
testBreakLabel();
System.out.println("testContinue");
testContinue();
System.out.println("testContinueLabel");
testContinueLabel();
}
/**
testBreak
a=0,b=0
a=0,b=1
a=1,b=0
a=1,b=1
a=2,b=0
a=2,b=1
a=3,b=0
a=3,b=1
a=4,b=0
a=4,b=1
*/
public void testBreak() {
for (int a = 0; a < 5; a++) {
for (int b = 0; b < 5; b++) {
if (b == 2) {
break;
}
System.out.println("a=" + a + ",b=" + b);
}
}
}
/**
testContinue
a=0,b=0
a=0,b=1
a=0,b=3
a=0,b=4
a=1,b=0
a=1,b=1
a=1,b=3
a=1,b=4
a=2,b=0
a=2,b=1
a=2,b=3
a=2,b=4
a=3,b=0
a=3,b=1
a=3,b=3
a=3,b=4
a=4,b=0
a=4,b=1
a=4,b=3
a=4,b=4
*/
public void testContinue() {
for (int a = 0; a < 5; a++) {
for (int b = 0; b < 5; b++) {
if (b == 2) {
continue;
}
System.out.println("a=" + a + ",b=" + b);
}
}
}
/**
testBreakLabel
a=0,b=0,c=0
a=0,b=0,c=1
* */
public void testBreakLabel() {
anyName:
for (int a = 0; a < 5; a++) {
for (int b = 0; b < 5; b++) {
for (int c = 0; c < 5; c++) {
if (c == 2) {
break anyName;
}
System.out.println("a=" + a + ",b=" + b + ",c=" + c);
}
}
}
}
/**
testContinueLabel
a=0,b=0,c=0
a=0,b=0,c=1
a=1,b=0,c=0
a=1,b=0,c=1
a=2,b=0,c=0
a=2,b=0,c=1
a=3,b=0,c=0
a=3,b=0,c=1
a=4,b=0,c=0
a=4,b=0,c=1
*/
public void testContinueLabel() {
anyName:
for (int a = 0; a < 5; a++) {
for (int b = 0; b < 5; b++) {
for (int c = 0; c < 5; c++) {
if (c == 2) {
continue anyName;
}
System.out.println("a=" + a + ",b=" + b + ",c=" + c);
}
}
}
}
}
Answered 2023-09-20 20:58:50
for (int j = 0; j < 5; j++) //inner loop
should be replaced with
for (int j = 0; j < 5 && !exitloops; j++)
.
Here, in this case complete nested loops should be exit if condition is True
. But if we use exitloops
only to the upper loop
for (int i = 0; i < 5 && !exitloops; i++) //upper loop
Then inner loop will continues, because there is no extra flag that notify this inner loop to exit.
Example : if
i = 3
andj=2
then condition isfalse
. But in next iteration of inner loopj=3
then condition(i*j)
become9
which istrue
but inner loop will be continue tillj
become5
.
So, it must use exitloops
to the inner loops too.
boolean exitloops = false;
for (int i = 0; i < 5 && !exitloops; i++) { //here should exitloops as a Conditional Statement to get out from the loops if exitloops become true.
for (int j = 0; j < 5 && !exitloops; j++) { //here should also use exitloops as a Conditional Statement.
if (i * j > 6) {
exitloops = true;
System.out.println("Inner loop still Continues For i * j is => "+i*j);
break;
}
System.out.println(i*j);
}
}
Answered 2023-09-20 20:58:50
Like @1800 INFORMATION suggestion, use the condition that breaks the inner loop as a condition on the outer loop:
boolean hasAccess = false;
for (int i = 0; i < x && hasAccess == false; i++){
for (int j = 0; j < y; j++){
if (condition == true){
hasAccess = true;
break;
}
}
}
Answered 2023-09-20 20:58:50
Java does not have a goto feature like there is in C++. But still, goto
is a reserved keyword in Java. They might implement it in the future. For your question, the answer is that there is something called label in Java to which you can apply a continue
and break
statement. Find the code below:
public static void main(String ...args) {
outerLoop: for(int i=0;i<10;i++) {
for(int j=10;j>0;j--) {
System.out.println(i+" "+j);
if(i==j) {
System.out.println("Condition Fulfilled");
break outerLoop;
}
}
}
System.out.println("Got out of the outer loop");
}
Answered 2023-09-20 20:58:50
If it's a new implementation, you can try rewriting the logic as if-else_if-else statements.
while(keep_going) {
if(keep_going && condition_one_holds) {
// Code
}
if(keep_going && condition_two_holds) {
// Code
}
if(keep_going && condition_three_holds) {
// Code
}
if(keep_going && something_goes_really_bad) {
keep_going=false;
}
if(keep_going && condition_four_holds) {
// Code
}
if(keep_going && condition_five_holds) {
// Code
}
}
Otherwise you can try setting a flag when that special condition has occured and check for that flag in each of your loop-conditions.
something_bad_has_happened = false;
while(something is true && !something_bad_has_happened){
// Code, things happen
while(something else && !something_bad_has_happened){
// Lots of code, things happens
if(something happened){
-> Then control should be returned ->
something_bad_has_happened=true;
continue;
}
}
if(something_bad_has_happened) { // The things below will not be executed
continue;
}
// Other things may happen here as well, but they will not be executed
// once control is returned from the inner cycle.
}
HERE! So, while a simple break will not work, it can be made to work using continue
.
If you are simply porting the logic from one programming language to Java and just want to get the thing working you can try using labels.
Answered 2023-09-20 20:58:50
You just use label for breaking inner loops
public class Test {
public static void main(String[] args) {
outerloop:
for (int i=0; i < 5; i++) {
for (int j=0; j < 5; j++) {
if (i * j > 6) {
System.out.println("Breaking");
break outerloop;
}
System.out.println(i + " " + j);
}
}
System.out.println("Done");
}
}
Answered 2023-09-20 20:58:50
You can do the following:
set a local variable to false
set that variable true
in the first loop, when you want to break
then you can check in the outer loop, that whether the condition is set then break from the outer loop as well.
boolean isBreakNeeded = false;
for (int i = 0; i < some.length; i++) {
for (int j = 0; j < some.lengthasWell; j++) {
//want to set variable if (){
isBreakNeeded = true;
break;
}
if (isBreakNeeded) {
break; //will make you break from the outer loop as well
}
}
Answered 2023-09-20 20:58:50