[1,2,3].forEach(function(el) {
if(el === 1) break;
});
How can I do this using the new forEach
method in JavaScript? I've tried return;
, return false;
and break
. break
crashes and return
does nothing but continue iteration.
return
does indeed continue the iteration, it will skip any code that comes after it in the block. Take this code for instance: [1,2,3].forEach(function(el) { if(el === 2) { console.log(`Match on 2!`); return; } console.log(el); });
.The console.log(el);
will be skipped when 2 is matched. - anyone There's no built-in ability to break
in forEach
. To interrupt execution you would have to throw an exception of some sort. eg.
var BreakException = {};
try {
[1, 2, 3].forEach(function(el) {
console.log(el);
if (el === 2) throw BreakException;
});
} catch (e) {
if (e !== BreakException) throw e;
}
JavaScript exceptions aren't terribly pretty. A traditional for
loop might be more appropriate if you really need to break
inside it.
Array#some
Instead, use Array#some
:
[1, 2, 3].some(function(el) {
console.log(el);
return el === 2;
});
This works because some
returns true
as soon as any of the callbacks, executed in array order, return true
, short-circuiting the execution of the rest.
some
, its inverse every
(which will stop on a return false
), and forEach
are all ECMAScript Fifth Edition methods which will need to be added to the Array.prototype
on browsers where they're missing.
Array#every
[1, 2, 3].every(v => {
if (v > 2) {
return false // "break"
}
console.log(v);
return true // must return true if doesn't break
});
Answered 2023-09-20 20:55:31
Array#some
is really nice. Firstly its compatible with most browsers including ie9 and firefox 1.5 also works really well. My example use case will be to find the index in an array of ranges[a,b] where a number is between a lower boundary and upper boundary pair, test and return true when found. for..of
would be the next best solution though only for newer browsers. - anyone forever
. All other loop constructs are formed from forever
and appropriate iterable exceptions, such as ContinueIteration
and StopIteration
(which break
is a macro to raise). On one hand: never. On the other hand: always. On the gripping hand: sometimes? The "PERIOD" in your comment implies there may be a citation to back up your suggestion? - anyone __next__()
raises StopIteration
after generator exhaustion for that reason, as it is generally the best way to detect the end of a generator - it's way better than relying on magic return values. Python's ducktyping and EAFP patterns generally depend on exception handling as a flow control mechanic. - anyone There is now an even better way to do this in ECMAScript2015 (aka ES6) using the new for of loop. For example, this code does not print the array elements after the number 5:
const arr = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
for (const el of arr) {
console.log(el);
if (el === 5) {
break;
}
}
From the docs:
Both for...in and for...of statements iterate over something. The main difference between them is in what they iterate over. The for...in statement iterates over the enumerable properties of an object, in original insertion order. The for...of statement iterates over data that iterable object defines to be iterated over.
Need the index in the iteration? You can use Array.entries()
:
for (const [index, el] of arr.entries()) {
if ( index === 5 ) break;
}
Answered 2023-09-20 20:55:31
entries
. for (const [index, element] of someArray.entries()) { // ... } - anyone Object.entries(myObject)
and then use it exactly like you use the for..in
for the array. Note that JS arrays are basically objects under the hood: blog.niftysnippets.org/2011/01/myth-of-arrays.html - anyone You can use every method:
[1,2,3].every(function(el) {
return !(el === 1);
});
ES6
[1,2,3].every( el => el !== 1 )
for old browser support use:
if (!Array.prototype.every)
{
Array.prototype.every = function(fun /*, thisp*/)
{
var len = this.length;
if (typeof fun != "function")
throw new TypeError();
var thisp = arguments[1];
for (var i = 0; i < len; i++)
{
if (i in this &&
!fun.call(thisp, this[i], i, this))
return false;
}
return true;
};
}
more details here.
Answered 2023-09-20 20:55:31
[1,2,3].every( el => el !== 1 )
- anyone every
guarantee that calls are made in sequence? - anyone k
starts at 0 and is incremented by 1: http://www.ecma-international.org/ecma-262/6.0/#sec-array.prototype.every - anyone Quoting from the MDN documentation of Array.prototype.forEach()
:
There is no way to stop or break a
forEach()
loop other than by throwing an exception. If you need such behaviour, the.forEach()
method is the wrong tool, use a plain loop instead. If you are testing the array elements for a predicate and need a boolean return value, you can useevery()
orsome()
instead.
For your code (in the question), as suggested by @bobince, use Array.prototype.some()
instead. It suits very well to your usecase.
Array.prototype.some()
executes the callback function once for each element present in the array until it finds one where callback returns a truthy value (a value that becomes true when converted to aBoolean
). If such an element is found,some()
immediately returns true. Otherwise,some()
returns false. callback is invoked only for indexes of the array which have assigned values; it is not invoked for indexes which have been deleted or which have never been assigned values.
Answered 2023-09-20 20:55:31
Unfortunately in this case it will be much better if you don't use forEach
.
Instead use a regular for
loop and it will now work exactly as you would expect.
var array = [1, 2, 3];
for (var i = 0; i < array.length; i++) {
if (array[i] === 1){
break;
}
}
Answered 2023-09-20 20:55:31
From your code example, it looks like Array.prototype.find
is what you are looking for: Array.prototype.find() and Array.prototype.findIndex()
[1, 2, 3].find(function(el) {
return el === 2;
}); // returns 2
Answered 2023-09-20 20:55:31
Consider to use jquery
's each
method, since it allows to return false inside callback function:
$.each([{user: "barney", active: false}, {user: "fred", active: false}],function(e, i) {
if (i % 2) return false;
console.log(e)
})
Lodash libraries also provides takeWhile
method that can be chained with map/reduce/fold etc:
var users = [
{ 'user': 'barney', 'active': false },
{ 'user': 'fred', 'active': false },
{ 'user': 'pebbles', 'active': true }
];
_.takeWhile(users, function(o) { return !o.active; });
// => objects for ['barney', 'fred']
// The `_.matches` iteratee shorthand.
_.takeWhile(users, { 'user': 'barney', 'active': false });
// => objects for ['barney']
// The `_.matchesProperty` iteratee shorthand.
_.takeWhile(users, ['active', false]);
// => objects for ['barney', 'fred']
// The `_.property` iteratee shorthand.
_.takeWhile(users, 'active');
// => []
Answered 2023-09-20 20:55:31
each
is incorrect. It takes an array and a callback. It should rather be something like: $.each(array,function(e, i) { if (i % 2) return false; console.log(e) });
See: jQuery documentation - anyone If you would like to use Dean Edward's suggestion and throw the StopIteration error to break out of the loop without having to catch the error, you can use the following the function (originally from here):
// Use a closure to prevent the global namespace from be polluted.
(function() {
// Define StopIteration as part of the global scope if it
// isn't already defined.
if(typeof StopIteration == "undefined") {
StopIteration = new Error("StopIteration");
}
// The original version of Array.prototype.forEach.
var oldForEach = Array.prototype.forEach;
// If forEach actually exists, define forEach so you can
// break out of it by throwing StopIteration. Allow
// other errors will be thrown as normal.
if(oldForEach) {
Array.prototype.forEach = function() {
try {
oldForEach.apply(this, [].slice.call(arguments, 0));
}
catch(e) {
if(e !== StopIteration) {
throw e;
}
}
};
}
})();
The above code will give you the ability to run code such as the following without having to do your own try-catch clauses:
// Show the contents until you get to "2".
[0,1,2,3,4].forEach(function(val) {
if(val == 2)
throw StopIteration;
alert(val);
});
One important thing to remember is that this will only update the Array.prototype.forEach function if it already exists. If it doesn't exist already, it will not modify the it.
Answered 2023-09-20 20:55:31
Short answer: use for...break
for this or change your code to avoid breaking of forEach
. Do not use .some()
or .every()
to emulate for...break
. Rewrite your code to avoid for...break
loop, or use for...break
. Every time you use these methods as for...break
alternative God kills kitten.
Long answer:
.some()
and .every()
both return boolean
value, .some()
returns true
if there any element for which passed function returns true
, every returns false
if there any element for which passed function returns false
. This is what that functions mean. Using functions for what they doesn't mean is much worse then using tables for layout instead of CSS, because it frustrates everybody who reads your code.
Also, the only possible way to use these methods as for...break
alternative is to make side-effects (change some vars outside of .some()
callback function), and this is not much different from for...break
.
So, using .some()
or .every()
as for...break
loop alternative isn't free of side effects, this isn't much cleaner then for...break
, this is frustrating, so this isn't better.
You can always rewrite your code so that there will be no need in for...break
. You can filter array using .filter()
, you can split array using .slice()
and so on, then use .forEach()
or .map()
for that part of array.
Answered 2023-09-20 20:55:31
for...break
loop if you need performance. for
loop is the most performant iteration tool than .forEach()
, .any()
, .map()
, .filter()
etc. - anyone As mentioned before, you can't break .forEach()
.
Here's a slightly more modern way of doing a foreach with ES6 Iterators. Allows you to get direct access to index
/value
when iterating.
const array = ['one', 'two', 'three'];
for (const [index, val] of array.entries()) {
console.log('item:', { index, val });
if (index === 1) {
console.log('break!');
break;
}
}
Output:
item: { index: 0, val: 'one' }
item: { index: 1, val: 'two' }
break!
Answered 2023-09-20 20:55:31
Another concept I came up with:
function forEach(array, cb) {
var shouldBreak;
function _break() { shouldBreak = true; }
for (var i = 0, bound = array.length; i < bound; ++i) {
if (shouldBreak) { break; }
cb(array[i], i, array, _break);
}
}
// Usage
forEach(['a','b','c','d','e','f'], function (char, i, array, _break) {
console.log(i, char);
if (i === 2) { _break(); }
});
Answered 2023-09-20 20:55:31
Array.prototype.forEach()
. for
and break
existed long before this question was asked; the OP was looking for that behaviour using, the more functional, forEach
. - anyone for...in
and break
. - anyone This is just something I came up with to solve the problem... I'm pretty sure it fixes the problem that the original asker had:
Array.prototype.each = function(callback){
if(!callback) return false;
for(var i=0; i<this.length; i++){
if(callback(this[i], i) == false) break;
}
};
And then you would call it by using:
var myarray = [1,2,3];
myarray.each(function(item, index){
// do something with the item
// if(item != somecondition) return false;
});
Returning false inside the callback function will cause a break. Let me know if that doesn't actually work.
Answered 2023-09-20 20:55:31
=== false
might be better than == false
so you don't have to explicitly return true (or a truthy value) to continue the loop, lest some control path doesn't return a value and the loop breaks unexpectedly. - anyone If you don't need to access your array after iteration you can bail out by setting the array's length to 0. If you do still need it after your iteration you could clone it using slice..
[1,3,4,5,6,7,8,244,3,5,2].forEach(function (item, index, arr) {
if (index === 3) arr.length = 0;
});
Or with a clone:
var x = [1,3,4,5,6,7,8,244,3,5,2];
x.slice().forEach(function (item, index, arr) {
if (index === 3) arr.length = 0;
});
Which is a far better solution then throwing random errors in your code.
Answered 2023-09-20 20:55:31
array.length
to 0
they will apply in current iteration, so probably it's sometimes better to use return
after such assigning - anyone Found this solution on another site. You can wrap the forEach in a try / catch scenario.
if(typeof StopIteration == "undefined") {
StopIteration = new Error("StopIteration");
}
try {
[1,2,3].forEach(function(el){
alert(el);
if(el === 1) throw StopIteration;
});
} catch(error) { if(error != StopIteration) throw error; }
More details here: http://dean.edwards.name/weblog/2006/07/enum/
Answered 2023-09-20 20:55:31
This is a for loop, but maintains the object reference in the loop just like a forEach() but you can break out.
var arr = [1,2,3];
for (var i = 0, el; el = arr[i]; i++) {
if(el === 1) break;
}
Answered 2023-09-20 20:55:31
try with "find" :
var myCategories = [
{category: "start", name: "Start", color: "#AC193D"},
{category: "action", name: "Action", color: "#8C0095"},
{category: "exit", name: "Exit", color: "#008A00"}
];
function findCategory(category) {
return myCategories.find(function(element) {
return element.category === category;
});
}
console.log(findCategory("start"));
// output: { category: "start", name: "Start", color: "#AC193D" }
Answered 2023-09-20 20:55:31
Yet another approach:
var wageType = types.filter(function(element){
if(e.params.data.text == element.name){
return element;
}
});
console.dir(wageType);
Answered 2023-09-20 20:55:31
I use nullhack for that purpose, it tries to access property of null
, which is an error:
try {
[1,2,3,4,5]
.forEach(
function ( val, idx, arr ) {
if ( val == 3 ) null.NULLBREAK;
}
);
} catch (e) {
// e <=> TypeError: null has no properties
}
//
Answered 2023-09-20 20:55:31
throw BREAK
? - anyone FOOBARED
and it would throw an error. - anyone Use the array.prototype.every
function, which provide you the utility to break the looping. See example here Javascript documentation on Mozilla developer network
Answered 2023-09-20 20:55:31
Agree with @bobince, upvoted.
Also, FYI:
Prototype.js has something for this purpose:
<script type="text/javascript">
$$('a').each(function(el, idx) {
if ( /* break condition */ ) throw $break;
// do something
});
</script>
$break
will be catched and handled by Prototype.js internally, breaking the "each" cycle but not generating external errors.
See Prototype.JS API for details.
jQuery also has a way, just return false in the handler to break the loop early:
<script type="text/javascript">
jQuery('a').each( function(idx) {
if ( /* break condition */ ) return false;
// do something
});
</script>
See jQuery API for details.
Answered 2023-09-20 20:55:31
If you want to keep your forEach
syntax, this is a way to keep it efficient (although not as good as a regular for loop). Check immediately for a variable that knows if you want to break out of the loop.
This example uses a anonymous function for creating a function scope around the forEach
which you need to store the done information.
(function(){
var element = document.getElementById('printed-result');
var done = false;
[1,2,3,4].forEach(function(item){
if(done){ return; }
var text = document.createTextNode(item);
element.appendChild(text);
if (item === 2){
done = true;
return;
}
});
})();
<div id="printed-result"></div>
My two cents.
Answered 2023-09-20 20:55:31
If you need to break based on the value of elements that are already in your array as in your case (i.e. if break condition does not depend on run-time variable that may change after array is assigned its element values) you could also use combination of slice() and indexOf() as follows.
If you need to break when forEach reaches 'Apple' you can use
var fruits = ["Banana", "Orange", "Lemon", "Apple", "Mango"];
var fruitsToLoop = fruits.slice(0, fruits.indexOf("Apple"));
// fruitsToLoop = Banana,Orange,Lemon
fruitsToLoop.forEach(function(el) {
// no need to break
});
As stated in W3Schools.com the slice() method returns the selected elements in an array, as a new array object. The original array will not be changed.
See it in JSFiddle
Hope it helps someone.
Answered 2023-09-20 20:55:31
Why don't you try wrapping the function in a Promise?
The only reason I bring it up is that I am using a function in an API that acts in a similar manner to forEach. I don't want it to keep iterating once it finds a value, and I need to return something so I am simply going to resolve a Promise and do it that way.
traverseTree(doc): Promise<any> {
return new Promise<any>((resolve, reject) => {
this.gridOptions.api.forEachNode((node, index) => {
//the above function is the one I want to short circuit.
if(node.data.id === doc.id) {
return resolve(node);
}
});
});
}
Then all you need to do is do something with the result like
this.traverseTree(doc).then((result) => {
this.doSomething(result);
});
My above example is in typescript, simply ignore the types. The logic should hopefully help you "break" out of your loop.
Answered 2023-09-20 20:55:31
This isn't the most efficient, since you still cycle all the elements, but I thought it might be worth considering the very simple:
let keepGoing = true;
things.forEach( (thing) => {
if (noMore) keepGoing = false;
if (keepGoing) {
// do things with thing
}
});
Answered 2023-09-20 20:55:31
continue
is a keyword, your code is a syntax error. - anyone for of
loop and break;
from that as usual. - anyone you can follow the code below which works for me:
var loopStop = false;
YOUR_ARRAY.forEach(function loop(){
if(loopStop){ return; }
if(condition){ loopStop = true; }
});
Answered 2023-09-20 20:55:31
Array.prototype.map
function esp in ReactThe key thing to note here is the use of statement return
to BREAK
let isBroken = false;
colours.map(item => {
if (isBroken) {
return;
}
if (item.startsWith("y")) {
console.log("The yessiest colour!");
isBroken = true;
return;
}
});
More information here: https://www.codegrepper.com/code-examples/javascript/break+out+of+map+javascript
Answered 2023-09-20 20:55:31
I know it not right way. It is not break the loop. It is a Jugad
let result = true;
[1, 2, 3].forEach(function(el) {
if(result){
console.log(el);
if (el === 2){
result = false;
}
}
});
Answered 2023-09-20 20:55:31
You can create a variant of forEach
that allows for break
, continue
, return
, and even async
/await
: (example written in TypeScript)
export type LoopControlOp = "break" | "continue" | ["return", any];
export type LoopFunc<T> = (value: T, index: number, array: T[])=>LoopControlOp;
Array.prototype.ForEach = function ForEach<T>(this: T[], func: LoopFunc<T>) {
for (let i = 0; i < this.length; i++) {
const controlOp = func(this[i], i, this);
if (controlOp == "break") break;
if (controlOp == "continue") continue;
if (controlOp instanceof Array) return controlOp[1];
}
};
// this variant lets you use async/await in the loop-func, with the loop "awaiting" for each entry
Array.prototype.ForEachAsync = async function ForEachAsync<T>(this: T[], func: LoopFunc<T>) {
for (let i = 0; i < this.length; i++) {
const controlOp = await func(this[i], i, this);
if (controlOp == "break") break;
if (controlOp == "continue") continue;
if (controlOp instanceof Array) return controlOp[1];
}
};
Usage:
function GetCoffee() {
const cancelReason = peopleOnStreet.ForEach((person, index)=> {
if (index == 0) return "continue";
if (person.type == "friend") return "break";
if (person.type == "boss") return ["return", "nevermind"];
});
if (cancelReason) console.log("Coffee canceled because: " + cancelReason);
}
Answered 2023-09-20 20:55:31
ForEach
function (it's not the generic forEach
function) -- the caller does not need to read anything on the Array prototype. That said, I don't actually use the solution above in production code -- it's just showing how one could accomplish those various operators within a forEach
-like function, if they wished to. - anyone In fact, I don't understand the reward for this old question. But if you really want to interrupt the foreach cycle, using only the foreach cycle, you can use the second parameter of the method to save the original array after its zeroing. Something like this:
let array = [1, 2, 3];
array.forEach(function(el) {
console.log(el);
if(el === 1) {
array = [...this];
this.length = 0;
}
}, array);
console.log(array);
P.S. I am in no way not advise that this should be done. On the contrary, I advise you to bypass my answer and use the previous best suggestions. Best regards.
Answered 2023-09-20 20:55:31