I've been using the idiom below for some time now. And it seems to be the most wide-spread, at least on the sites I've visited.
Is there a better/different way to read a file into a string in Java?
private String readFile(String file) throws IOException {
BufferedReader reader = new BufferedReader(new FileReader (file));
String line = null;
StringBuilder stringBuilder = new StringBuilder();
String ls = System.getProperty("line.separator");
try {
while((line = reader.readLine()) != null) {
stringBuilder.append(line);
stringBuilder.append(ls);
}
return stringBuilder.toString();
} finally {
reader.close();
}
}
byte[] Files.readAllBytes(file);
To those, who suggest the 'one-line' Scanner solution: Don't yo need to close it? - anyone Java 11 added the readString() method to read small files as a String
, preserving line terminators:
String content = Files.readString(path, encoding);
For versions between Java 7 and 11, here's a compact, robust idiom, wrapped up in a utility method:
static String readFile(String path, Charset encoding)
throws IOException
{
byte[] encoded = Files.readAllBytes(Paths.get(path));
return new String(encoded, encoding);
}
Java 7 added a convenience method to read a file as lines of text, represented as a List<String>
. This approach is "lossy" because the line separators are stripped from the end of each line.
List<String> lines = Files.readAllLines(Paths.get(path), encoding);
Java 8 added the Files.lines()
method to produce a Stream<String>
. Again, this method is lossy because line separators are stripped. If an IOException
is encountered while reading the file, it is wrapped in an UncheckedIOException
, since Stream
doesn't accept lambdas that throw checked exceptions.
try (Stream<String> lines = Files.lines(path, encoding)) {
lines.forEach(System.out::println);
}
This Stream
does need a close()
call; this is poorly documented on the API, and I suspect many people don't even notice Stream
has a close()
method. Be sure to use an ARM-block as shown.
If you are working with a source other than a file, you can use the lines()
method in BufferedReader
instead.
If your file is small enough relative to your available memory, reading the entire file at once might work fine. However, if your file is too large, reading one line at a time, processing it, and then discarding it before moving on to the next could be a better approach. Stream processing in this way can eliminate the total file size as a factor in your memory requirement.
One thing that is missing from the sample in the original post is the character encoding. This encoding generally can't be determined from the file itself, and requires meta-data such as an HTTP header to convey this important information.
The StandardCharsets
class defines some constants for the encodings required of all Java runtimes:
String content = readFile("test.txt", StandardCharsets.UTF_8);
The platform default is available from the Charset
class itself:
String content = readFile("test.txt", Charset.defaultCharset());
There are some special cases where the platform default is what you want, but they are rare. You should be able justify your choice, because the platform default is not portable. One example where it might be correct is when reading standard input or writing standard output.
Note: This answer largely replaces my Java 6 version. The utility of Java 7 safely simplifies the code, and the old answer, which used a mapped byte buffer, prevented the file that was read from being deleted until the mapped buffer was garbage collected. You can view the old version via the "edited" link on this answer.
Answered 2023-09-21 08:12:09
Files.readString(…)
, is the only one that can work without requiring additional memory. - anyone If you're willing to use an external library, check out Apache Commons IO (200KB JAR). It contains an org.apache.commons.io.FileUtils.readFileToString()
method that allows you to read an entire File
into a String
with one line of code.
Example:
import java.io.*;
import java.nio.charset.*;
import org.apache.commons.io.*;
public String readFile() throws IOException {
File file = new File("data.txt");
return FileUtils.readFileToString(file, StandardCharsets.UTF_8);
}
Answered 2023-09-21 08:12:09
A very lean solution based on Scanner
:
Scanner scanner = new Scanner( new File("poem.txt") );
String text = scanner.useDelimiter("\\A").next();
scanner.close(); // Put this call in a finally block
Or, if you want to set the charset:
Scanner scanner = new Scanner( new File("poem.txt"), "UTF-8" );
String text = scanner.useDelimiter("\\A").next();
scanner.close(); // Put this call in a finally block
Or, with a try-with-resources block, which will call scanner.close()
for you:
try (Scanner scanner = new Scanner( new File("poem.txt"), "UTF-8" )) {
String text = scanner.useDelimiter("\\A").next();
}
Remember that the Scanner
constructor can throw an IOException
. And don't forget to import java.io
and java.util
.
Source: Pat Niemeyer's blog
Answered 2023-09-21 08:12:09
import java.nio.charset.StandardCharsets;
import java.nio.file.Files;
import java.nio.file.Paths;
Java 7
String content = new String(Files.readAllBytes(Paths.get("readMe.txt")), StandardCharsets.UTF_8);
Java 11
String content = Files.readString(Paths.get("readMe.txt"));
Answered 2023-09-21 08:12:09
If you're looking for an alternative that doesn't involve a third-party library (e.g. Commons I/O), you can use the Scanner class:
private String readFile(String pathname) throws IOException {
File file = new File(pathname);
StringBuilder fileContents = new StringBuilder((int)file.length());
try (Scanner scanner = new Scanner(file)) {
while(scanner.hasNextLine()) {
fileContents.append(scanner.nextLine() + System.lineSeparator());
}
return fileContents.toString();
}
}
Answered 2023-09-21 08:12:09
Guava has a method similar to the one from Commons IOUtils that Willi aus Rohr mentioned:
import com.google.common.base.Charsets;
import com.google.common.io.Files;
// ...
String text = Files.toString(new File(path), Charsets.UTF_8);
EDIT by PiggyPiglet
Files#toString
is deprecated, and due for removal Octobor 2019. Instead use
Files.asCharSource(new File(path), StandardCharsets.UTF_8).read();
EDIT by Oscar Reyes
This is the (simplified) underlying code on the cited library:
InputStream in = new FileInputStream(file);
byte[] b = new byte[file.length()];
int len = b.length;
int total = 0;
while (total < len) {
int result = in.read(b, total, len - total);
if (result == -1) {
break;
}
total += result;
}
return new String( b , Charsets.UTF_8 );
Edit (by Jonik): The above doesn't match the source code of recent Guava versions. For the current source, see the classes Files, CharStreams, ByteSource and CharSource in com.google.common.io package.
Answered 2023-09-21 08:12:09
Closer
in CharSource. The code in the answer isn't the actual, current Guava source. - anyone import java.nio.file.Files;
.......
String readFile(String filename) {
File f = new File(filename);
try {
byte[] bytes = Files.readAllBytes(f.toPath());
return new String(bytes,"UTF-8");
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return "";
}
Answered 2023-09-21 08:12:09
new String(Files.readAllBytes(Paths.get(filename)));
:-) - anyone If you need a string processing (parallel processing) Java 8 has the great Stream API.
String result = Files.lines(Paths.get("file.txt"))
.parallel() // for parallel processing
.map(String::trim) // to change line
.filter(line -> line.length() > 2) // to filter some lines by a predicate
.collect(Collectors.joining()); // to join lines
More examples are available in JDK samples sample/lambda/BulkDataOperations
that can be downloaded from Oracle Java SE 8 download page
Another one liner example
String out = String.join("\n", Files.readAllLines(Paths.get("file.txt")));
Answered 2023-09-21 08:12:09
Files.lines(Paths.get("file.txt"))
is not closed and is a resource leak. You should wrap in a try-with-resources block. - anyone That code will normalize line breaks, which may or may not be what you really want to do.
Here's an alternative which doesn't do that, and which is (IMO) simpler to understand than the NIO code (although it still uses java.nio.charset.Charset
):
public static String readFile(String file, String csName)
throws IOException {
Charset cs = Charset.forName(csName);
return readFile(file, cs);
}
public static String readFile(String file, Charset cs)
throws IOException {
// No real need to close the BufferedReader/InputStreamReader
// as they're only wrapping the stream
FileInputStream stream = new FileInputStream(file);
try {
Reader reader = new BufferedReader(new InputStreamReader(stream, cs));
StringBuilder builder = new StringBuilder();
char[] buffer = new char[8192];
int read;
while ((read = reader.read(buffer, 0, buffer.length)) > 0) {
builder.append(buffer, 0, read);
}
return builder.toString();
} finally {
// Potential issue here: if this throws an IOException,
// it will mask any others. Normally I'd use a utility
// method which would log exceptions and swallow them
stream.close();
}
}
Answered 2023-09-21 08:12:09
Gathered all the possible ways to read the File as String from Disk or Network.
Guava: Google using classes Resources
, Files
static Charset charset = com.google.common.base.Charsets.UTF_8;
public static String guava_ServerFile( URL url ) throws IOException {
return Resources.toString( url, charset );
}
public static String guava_DiskFile( File file ) throws IOException {
return Files.toString( file, charset );
}
APACHE - COMMONS IO using classes IOUtils, FileUtils
static Charset encoding = org.apache.commons.io.Charsets.UTF_8;
public static String commons_IOUtils( URL url ) throws IOException {
java.io.InputStream in = url.openStream();
try {
return IOUtils.toString( in, encoding );
} finally {
IOUtils.closeQuietly(in);
}
}
public static String commons_FileUtils( File file ) throws IOException {
return FileUtils.readFileToString( file, encoding );
/*List<String> lines = FileUtils.readLines( fileName, encoding );
return lines.stream().collect( Collectors.joining("\n") );*/
}
Java 8 BufferReader using Stream API
public static String streamURL_Buffer( URL url ) throws IOException {
java.io.InputStream source = url.openStream();
BufferedReader reader = new BufferedReader( new InputStreamReader( source ) );
//List<String> lines = reader.lines().collect( Collectors.toList() );
return reader.lines().collect( Collectors.joining( System.lineSeparator() ) );
}
public static String streamFile_Buffer( File file ) throws IOException {
BufferedReader reader = new BufferedReader( new FileReader( file ) );
return reader.lines().collect(Collectors.joining(System.lineSeparator()));
}
Scanner Class with regex \A
. which matches the beginning of input.
static String charsetName = java.nio.charset.StandardCharsets.UTF_8.toString();
public static String streamURL_Scanner( URL url ) throws IOException {
java.io.InputStream source = url.openStream();
Scanner scanner = new Scanner(source, charsetName).useDelimiter("\\A");
return scanner.hasNext() ? scanner.next() : "";
}
public static String streamFile_Scanner( File file ) throws IOException {
Scanner scanner = new Scanner(file, charsetName).useDelimiter("\\A");
return scanner.hasNext() ? scanner.next() : "";
}
Java 7 (java.nio.file.Files.readAllBytes
)
public static String getDiskFile_Java7( File file ) throws IOException {
byte[] readAllBytes = java.nio.file.Files.readAllBytes(Paths.get( file.getAbsolutePath() ));
return new String( readAllBytes );
}
BufferedReader
using InputStreamReader
.
public static String getDiskFile_Lines( File file ) throws IOException {
StringBuffer text = new StringBuffer();
FileInputStream fileStream = new FileInputStream( file );
BufferedReader br = new BufferedReader( new InputStreamReader( fileStream ) );
for ( String line; (line = br.readLine()) != null; )
text.append( line + System.lineSeparator() );
return text.toString();
}
Example with main method to access the above methods.
public static void main(String[] args) throws IOException {
String fileName = "E:/parametarisation.csv";
File file = new File( fileName );
String fileStream = commons_FileUtils( file );
// guava_DiskFile( file );
// streamFile_Buffer( file );
// getDiskFile_Java7( file );
// getDiskFile_Lines( file );
System.out.println( " File Over Disk : \n"+ fileStream );
try {
String src = "https://code.jquery.com/jquery-3.2.1.js";
URL url = new URL( src );
String urlStream = commons_IOUtils( url );
// guava_ServerFile( url );
// streamURL_Scanner( url );
// streamURL_Buffer( url );
System.out.println( " File Over Network : \n"+ urlStream );
} catch (MalformedURLException e) {
e.printStackTrace();
}
}
@see
Answered 2023-09-21 08:12:09
If it's a text file why not use apache commons-io?
It has the following method
public static String readFileToString(File file) throws IOException
If you want the lines as a list use
public static List<String> readLines(File file) throws IOException
Answered 2023-09-21 08:12:09
Since JDK 11:
String file = ...
Path path = Paths.get(file);
String content = Files.readString(path);
// Or readString(path, someCharset), if you need a Charset different from UTF-8
Answered 2023-09-21 08:12:09
To read a File as binary and convert at the end
public static String readFileAsString(String filePath) throws IOException {
DataInputStream dis = new DataInputStream(new FileInputStream(filePath));
try {
long len = new File(filePath).length();
if (len > Integer.MAX_VALUE) throw new IOException("File "+filePath+" too large, was "+len+" bytes.");
byte[] bytes = new byte[(int) len];
dis.readFully(bytes);
return new String(bytes, "UTF-8");
} finally {
dis.close();
}
}
Answered 2023-09-21 08:12:09
With Java 7, this is my preferred option to read a UTF-8 file:
String content = new String(Files.readAllBytes(Paths.get(filename)), "UTF-8");
Since Java 7, the JDK has the new java.nio.file
API, which provides many shortcuts, so 3rd party libraries are not always required for simple file operations.
Since people are still upvoting this answer, here is a better solution that got introduced in Java 11:
String content = Files.readString(path);
Answered 2023-09-21 08:12:09
Java attempts to be extremely general and flexible in all it does. As a result, something which is relatively simple in a scripting language (your code would be replaced with "open(file).read()
" in python) is a lot more complicated. There doesn't seem to be any shorter way of doing it, except using an external library (like Willi aus Rohr mentioned). Your options:
Your best bet is probably the 2nd one, as it has the least dependencies.
Answered 2023-09-21 08:12:09
byte[] bytes = Files.readAllBytes(someFile.toPath());
- anyone no external libraries used
You can create a new String object from the file content (Using classes from java.nio.file
package):
public String readStringFromFile(String filePath) throws IOException {
String fileContent = new String(Files.readAllBytes(Paths.get(filePath)));
return fileContent;
}
Answered 2023-09-21 08:12:09
There is a variation on the same theme that uses a for loop, instead of a while loop, to limit the scope of the line variable. Whether it's "better" is a matter of personal taste.
for(String line = reader.readLine(); line != null; line = reader.readLine()) {
stringBuilder.append(line);
stringBuilder.append(ls);
}
Answered 2023-09-21 08:12:09
line
variable. The edit declared it twice, which would be a compile error. - anyone If you do not have access to the Files
class, you can use a native solution.
static String readFile(File file, String charset)
throws IOException
{
FileInputStream fileInputStream = new FileInputStream(file);
byte[] buffer = new byte[fileInputStream.available()];
int length = fileInputStream.read(buffer);
fileInputStream.close();
return new String(buffer, 0, length, charset);
}
Answered 2023-09-21 08:12:09
A flexible solution using IOUtils from Apache commons-io in combination with StringWriter:
Reader input = new FileReader();
StringWriter output = new StringWriter();
try {
IOUtils.copy(input, output);
} finally {
input.close();
}
String fileContents = output.toString();
It works with any reader or input stream (not just with files), for example when reading from a URL.
Answered 2023-09-21 08:12:09
Be aware when using fileInputStream.available()
the returned integer does not have to represent the actual file size, but rather the guessed amount of bytes the system should be able to read from the stream without blocking IO. A safe and simple way could look like this
public String readStringFromInputStream(FileInputStream fileInputStream) {
StringBuffer stringBuffer = new StringBuffer();
try {
byte[] buffer;
while (fileInputStream.available() > 0) {
buffer = new byte[fileInputStream.available()];
fileInputStream.read(buffer);
stringBuffer.append(new String(buffer, "ISO-8859-1"));
}
} catch (FileNotFoundException e) {
} catch (IOException e) { }
return stringBuffer.toString();
}
It should be considered that this approach is not suitable for multi-byte character encodings like UTF-8.
Answered 2023-09-21 08:12:09
available()
method, there is no guarantee that the end of file is reached in the event that the method returns 0. In that case you might end up with an incomplete file. What's worse, the number of bytes actually read can be smaller than the value returned by available()
, in which case you get corrupted output. - anyone This one uses the method RandomAccessFile.readFully
, it seems to be available from JDK 1.0 !
public static String readFileContent(String filename, Charset charset) throws IOException {
RandomAccessFile raf = null;
try {
raf = new RandomAccessFile(filename, "r");
byte[] buffer = new byte[(int)raf.length()];
raf.readFully(buffer);
return new String(buffer, charset);
} finally {
closeStream(raf);
}
}
private static void closeStream(Closeable c) {
if (c != null) {
try {
c.close();
} catch (IOException ex) {
// do nothing
}
}
}
Answered 2023-09-21 08:12:09
Using this library, it is one line:
String data = IO.from(new File("data.txt")).toString();
Answered 2023-09-21 08:12:09
You can try Scanner and File class, a few lines solution
try
{
String content = new Scanner(new File("file.txt")).useDelimiter("\\Z").next();
System.out.println(content);
}
catch(FileNotFoundException e)
{
System.out.println("not found!");
}
Answered 2023-09-21 08:12:09
Based on @erickson`s answer, you can use:
public String readAll(String fileName) throws IOException {
List<String> lines = Files.readAllLines(new File(fileName).toPath());
return String.join("\n", lines.toArray(new String[lines.size()]));
}
Answered 2023-09-21 08:12:09
User java.nio.Files
to read all lines of file.
public String readFile() throws IOException {
File fileToRead = new File("file path");
List<String> fileLines = Files.readAllLines(fileToRead.toPath());
return StringUtils.join(fileLines, StringUtils.EMPTY);
}
Answered 2023-09-21 08:12:09
public static String slurp (final File file)
throws IOException {
StringBuilder result = new StringBuilder();
BufferedReader reader = new BufferedReader(new FileReader(file));
try {
char[] buf = new char[1024];
int r = 0;
while ((r = reader.read(buf)) != -1) {
result.append(buf, 0, r);
}
}
finally {
reader.close();
}
return result.toString();
}
Answered 2023-09-21 08:12:09
cannot find symbol
. - anyone I cannot comment other entries yet, so I'll just leave it here.
One of best answers here (https://stackoverflow.com/a/326448/1521167):
private String readFile(String pathname) throws IOException {
File file = new File(pathname);
StringBuilder fileContents = new StringBuilder((int)file.length());
Scanner scanner = new Scanner(file);
String lineSeparator = System.getProperty("line.separator");
try {
while(scanner.hasNextLine()) {
fileContents.append(scanner.nextLine() + lineSeparator);
}
return fileContents.toString();
} finally {
scanner.close();
}
}
still has one flaw. It always puts new line char in the end of string, which may cause some weirds bugs. My suggestion is to change it to:
private String readFile(String pathname) throws IOException {
File file = new File(pathname);
StringBuilder fileContents = new StringBuilder((int) file.length());
Scanner scanner = new Scanner(new BufferedReader(new FileReader(file)));
String lineSeparator = System.getProperty("line.separator");
try {
if (scanner.hasNextLine()) {
fileContents.append(scanner.nextLine());
}
while (scanner.hasNextLine()) {
fileContents.append(lineSeparator + scanner.nextLine());
}
return fileContents.toString();
} finally {
scanner.close();
}
}
Answered 2023-09-21 08:12:09
After Ctrl+F'ing after Scanner, I think that the Scanner solution should be listed too. In the easiest to read fashion it goes like this:
public String fileToString(File file, Charset charset) {
Scanner fileReader = new Scanner(file, charset);
fileReader.useDelimiter("\\Z"); // \Z means EOF.
String out = fileReader.next();
fileReader.close();
return out;
}
If you use Java 7 or newer (and you really should) consider using try-with-resources to make the code easier to read. No more dot-close stuff littering everything. But that's mostly a stylistic choice methinks.
I'm posting this mostly for completionism, since if you need to do this a lot, there should be things in java.nio.file.Files that should do the job better.
My suggestion would be to use Files#readAllBytes(Path) to grab all the bytes, and feed it to new String(byte[] Charset) to get a String out of it that you can trust. Charsets will be mean to you during your lifetime, so beware of this stuff now.
Others have given code and stuff, and I don't want to steal their glory. ;)
Answered 2023-09-21 08:12:09
Also if your file happens to be inside a jar, you can also use this:
public String fromFileInJar(String path) {
try ( Scanner scanner
= new Scanner(getClass().getResourceAsStream(path))) {
return scanner.useDelimiter("\\A").next();
}
}
The path should start with /
for instance if your jar is
my.jar/com/some/thing/a.txt
Then you want to invoke it like this:
String myTxt = fromFileInJar("/com/com/thing/a.txt");
Answered 2023-09-21 08:12:09
In one line (Java 8), assuming you have a Reader:
String sMessage = String.join("\n", reader.lines().collect(Collectors.toList()));
Answered 2023-09-21 08:12:09