I have an object:
myObject = { 'a': 1, 'b': 2, 'c': 3 }
I am looking for a native method, similar to Array.prototype.map
that would be used as follows:
newObject = myObject.map(function (value, label) {
return value * value;
});
// newObject is now { 'a': 1, 'b': 4, 'c': 9 }
Does JavaScript have such a map
function for objects? (I want this for Node.JS, so I don't care about cross-browser issues.)
Object.keys
, which doesn't have any well-defined order. That can be problematic, I suggest using Object.getOwnPropertyNames
instead. - anyone Object.keys
and Object.getOwnPropertyNames
. See developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/… - anyone Object.keys
is implementation-dependent. See stackoverflow.com/a/30919039/1529630 - anyone There is no native map
to the Object
object, but how about this:
var myObject = { 'a': 1, 'b': 2, 'c': 3 };
Object.keys(myObject).forEach(function(key, index) {
myObject[key] *= 2;
});
console.log(myObject);
// => { 'a': 2, 'b': 4, 'c': 6 }
But you could easily iterate over an object using for ... in
:
var myObject = { 'a': 1, 'b': 2, 'c': 3 };
for (var key in myObject) {
if (myObject.hasOwnProperty(key)) {
myObject[key] *= 2;
}
}
console.log(myObject);
// { 'a': 2, 'b': 4, 'c': 6 }
A lot of people are mentioning that the previous methods do not return a new object, but rather operate on the object itself. For that matter I wanted to add another solution that returns a new object and leaves the original object as it is:
var myObject = { 'a': 1, 'b': 2, 'c': 3 };
// returns a new object with the values at each key mapped using mapFn(value)
function objectMap(object, mapFn) {
return Object.keys(object).reduce(function(result, key) {
result[key] = mapFn(object[key])
return result
}, {})
}
var newObject = objectMap(myObject, function(value) {
return value * 2
})
console.log(newObject);
// => { 'a': 2, 'b': 4, 'c': 6 }
console.log(myObject);
// => { 'a': 1, 'b': 2, 'c': 3 }
Array.prototype.reduce
reduces an array to a single value by somewhat merging the previous value with the current. The chain is initialized by an empty object {}
. On every iteration a new key of myObject
is added with twice the key as the value.
With new ES6 features, there is a more elegant way to express objectMap
.
const objectMap = (obj, fn) =>
Object.fromEntries(
Object.entries(obj).map(
([k, v], i) => [k, fn(v, k, i)]
)
)
const myObject = { a: 1, b: 2, c: 3 }
console.log(objectMap(myObject, v => 2 * v))
Answered 2023-09-21 08:11:51
map
correctly because it isn't doing a return
- it's abusing map
as if it were a forEach
call. If he actually did return myObject[value] * 2
then the result would be an array containing the original values doubled, instead of an object containing the original keys with doubled values, the latter clearly being what the OP asked for. - anyone .reduce
example is OK, but IMHO it still falls a long way short of the convenience of a .map
for Objects, since your .reduce
callback not only has to match the way that .reduce
works, but also requires that myObject
be available in the lexical scope. The latter in particular makes it impossible to just pass a function reference in the callback, requiring an in-place anonymous function instead. - anyone .map
is not the appropriate method to use when you aren't going to use the resulting mapped array - if you want side-effects only, such as in your first code, you should most definitely use forEach
instead. - anyone Object.fromEntries
is ES2019, not ES2015. Also, as others have said, I'd highly recommend replacing the .map
in the first snippet with forEach
, or something else more appropriate than .map
- anyone How about a one-liner in JS ES10 / ES2019 ?
Making use of Object.entries()
and Object.fromEntries()
:
let newObj = Object.fromEntries(Object.entries(obj).map(([k, v]) => [k, v * v]));
The same thing written as a function:
function objMap(obj, func) {
return Object.fromEntries(Object.entries(obj).map(([k, v]) => [k, func(v)]));
}
// To square each value you can call it like this:
let mappedObj = objMap(obj, (x) => x * x);
This function uses recursion to square nested objects as well:
function objMap(obj, func) {
return Object.fromEntries(
Object.entries(obj).map(([k, v]) =>
[k, v === Object(v) ? objMap(v, func) : func(v)]
)
);
}
// To square each value you can call it like this:
let mappedObj = objMap(obj, (x) => x * x);
With ES7 / ES2016 you can't use Objects.fromEntries
, but you can achieve the same using Object.assign
in combination with spread operators and computed key names syntax:
let newObj = Object.assign({}, ...Object.entries(obj).map(([k, v]) => ({[k]: v * v})));
ES6 / ES2015 Doesn't allow Object.entries
, but you could use Object.keys
instead:
let newObj = Object.assign({}, ...Object.keys(obj).map(k => ({[k]: obj[k] * obj[k]})));
ES6 also introduced for...of
loops, which allow a more imperative style:
let newObj = {}
for (let [k, v] of Object.entries(obj)) {
newObj[k] = v * v;
}
Instead of Object.fromEntries
and Object.assign
you can also use reduce for this:
let newObj = Object.entries(obj).reduce((p, [k, v]) => ({ ...p, [k]: v * v }), {});
In some rare situation you may need to map a class-like object which holds properties of an inherited object on its prototype-chain. In such cases Object.keys()
and Object.entries()
won't work, because these functions do not include the prototype chain.
If you need to map inherited properties, you can use for (key in myObj) {...}
.
Here is an example of such situation:
const obj1 = { 'a': 1, 'b': 2, 'c': 3}
const obj2 = Object.create(obj1); // One of multiple ways to inherit an object in JS.
// Here you see how the properties of obj1 sit on the 'prototype' of obj2
console.log(obj2) // Prints: obj2.__proto__ = { 'a': 1, 'b': 2, 'c': 3}
console.log(Object.keys(obj2)); // Prints: an empty Array.
console.log(Object.entries(obj2)); // Prints: an empty Array.
for (let key in obj2) {
console.log(key); // Prints: 'a', 'b', 'c'
}
However, please do me a favor and avoid inheritance. :-)
Answered 2023-09-21 08:11:51
Object.keys
doesn't enumerate inherited properties. I suggest you add a warning. - anyone Object.entries({a: 1, b: 2, c: 3})
. - anyone (o, f)
as arguments but use obj
in the body. - anyone Object.assign(...Object.entries(obj).map(([k, v]) => ({[k]: v * v})))
does not work if obj
is an empty object. Change to: Object.assign({}, ...Object.entries(obj).map(([k, v]) => ({[k]: v * v})))
. - anyone No native methods, but lodash#mapValues will do the job brilliantly
_.mapValues({ 'a': 1, 'b': 2, 'c': 3} , function(num) { return num * 3; });
// → { 'a': 3, 'b': 6, 'c': 9 }
Answered 2023-09-21 08:11:51
Object.entries({a: 1, b: 2, c: 3})
to get an array. - anyone _.map()
so you get the key as the second argument - as required by the OP. - anyone _.mapValues()
does also provide the key as the 2nd argument. Also _.map()
would not work here as it only returns arrays, not objects: _.map({ 'a': 1, 'b': 2, 'c': 3}, n => n * 3) // [3, 6, 9]
- anyone It's pretty easy to write one:
Object.map = function(o, f, ctx) {
ctx = ctx || this;
var result = {};
Object.keys(o).forEach(function(k) {
result[k] = f.call(ctx, o[k], k, o);
});
return result;
}
with example code:
> o = { a: 1, b: 2, c: 3 };
> r = Object.map(o, function(v, k, o) {
return v * v;
});
> r
{ a : 1, b: 4, c: 9 }
NB: this version also allows you to (optionally) set the this
context for the callback, just like the Array
method.
EDIT - changed to remove use of Object.prototype
, to ensure that it doesn't clash with any existing property named map
on the object.
Answered 2023-09-21 08:11:51
map
, but I must say that modifying Object.prototype
doesn't sit well with me, even if it isn't enumerable. - anyone Object.prototype
other than the (theoretical) risk of collision with other methods. FWIW, I can't understand how the other answer got as many votes as it has, it's completely wrong. - anyone map
. - anyone o = {map: true, image: false}
. You're risking it just to write o.map(fn)
instead of map(o,fn)
- anyone Object
that I think if ES ever did acquire this method it would be Object.map
rather than Object.prototype.map
(and this is also consistent with the other "static" methods on Object
) - anyone You could use Object.keys
and then forEach
over the returned array of keys:
var myObject = { 'a': 1, 'b': 2, 'c': 3 },
newObject = {};
Object.keys(myObject).forEach(function (key) {
var value = myObject[key];
newObject[key] = value * value;
});
Or in a more modular fashion:
function map(obj, callback) {
var result = {};
Object.keys(obj).forEach(function (key) {
result[key] = callback.call(obj, obj[key], key, obj);
});
return result;
}
newObject = map(myObject, function(x) { return x * x; });
Note that Object.keys
returns an array containing only the object's own enumerable properties, thus it behaves like a for..in
loop with a hasOwnProperty
check.
Answered 2023-09-21 08:11:51
This is really annoying, and everyone in the JS community knows it. There should be this functionality:
const obj1 = {a:4, b:7};
const obj2 = Object.map(obj1, (k,v) => v + 5);
console.log(obj1); // {a:4, b:7}
console.log(obj2); // {a:9, b:12}
here is the naïve implementation:
Object.map = function(obj, fn, ctx){
const ret = {};
for(let k of Object.keys(obj)){
ret[k] = fn.call(ctx || null, k, obj[k]);
});
return ret;
};
it is super annoying to have to implement this yourself all the time ;)
If you want something a little more sophisticated, that doesn't interfere with the Object class, try this:
const map = function (obj, fn, ctx) {
return Object.keys(obj).reduce((a, b) => {
a[b] = fn.call(ctx || null, b, obj[b]);
return a;
}, {});
};
const x = map({a: 2, b: 4}, (k,v) => {
return v*2;
});
but it is safe to add this map function to Object, just don't add to Object.prototype.
Object.map = ... // fairly safe
Object.prototype.map ... // not ok
Answered 2023-09-21 08:11:51
Object
object? Just have const mapObject = (obj, fn) => { [...]; return ret; }
. - anyone .map
is generally understood as a Functor interface, and there's no single definition of Functor for "Object" because virtually anything in javascript can be an Object, including things with their own very distinct and defined .map interfaces/logic. - anyone Object.entries(obj).reduce((a, [k, v]) => (a[k] = v * v, a), {})
↑↑↑↑↑
Object.fromEntries(Object.entries(obj).map(([k, v]) => [k, v * v]))
↑↑↑↑↑
Answered 2023-09-21 08:11:51
Object.entries(obj).reduce((a, [k, v]) => [a[k] = v * v, a], {})
, angled-brackets instead of parentheses. - anyone Object.entries(obj).reduce((a, [k, v]) => {a[k] = v * v; return a}, {})
- anyone I came here looking to find and answer for mapping an object to an array and got this page as a result. In case you came here looking for the same answer I was, here is how you can map and object to an array.
You can use map to return a new array from the object like so:
var newObject = Object.keys(myObject).map(function(key) {
return myObject[key];
});
Answered 2023-09-21 08:11:51
Object.values(myObject)
- anyone JavaScript just got the new Object.fromEntries
method.
function mapObject (obj, fn) {
return Object.fromEntries(
Object
.entries(obj)
.map(fn)
)
}
const myObject = { a: 1, b: 2, c: 3 }
const myNewObject = mapObject(myObject, ([key, value]) => ([key, value * value]))
console.log(myNewObject)
The code above converts the Object into an nested Array ([[<key>,<value>], ...]
) wich you can map over. Object.fromEntries
converts the Array back to an Object.
The cool thing about this pattern, is that you can now easily take object keys into account while mapping.
Object.fromEntries
is currently only supported by these browsers/engines, nevertheless there are polyfills available (e.g @babel/polyfill).
Answered 2023-09-21 08:11:51
Object.fromEntries
is the opposite of Object.entries
. Object.entries
converts an object to a list of key-value pairs. Object.fromEntries
converts a list of key-value pairs to an object. - anyone Array.map()
. My preference would be for the map function params to be (value, key)
. I know this seems somewhat backwards, however that's the order used for Array.map()
and Array.forEach()
so it's more consistent. - anyone The accepted answer has two drawbacks:
Array.prototype.reduce
, because reducing means to change the structure of a composite type, which doesn't happen in this case.Please note that all functions are defined in curried form.
// small, reusable auxiliary functions
const keys = o => Object.keys(o);
const assign = (...o) => Object.assign({}, ...o);
const map = f => xs => xs.map(x => f(x));
const mul = y => x => x * y;
const sqr = x => mul(x) (x);
// the actual map function
const omap = f => o => {
o = assign(o); // A
map(x => o[x] = f(o[x])) (keys(o)); // B
return o;
};
// mock data
const o = {"a":1, "b":2, "c":3};
// and run
console.log(omap(sqr) (o));
console.log(omap(mul(10)) (o));
o
is reassigned. Since Javascript passes reference values by sharing, a shallow copy of o
is generated. We are now able to mutate o
within omap
without mutating o
in the parent scope.map
's return value is ignored, because map
performs a mutation of o
. Since this side effect remains within omap
and isn't visible in the parent scope, it is totally acceptable.This is not the fastest solution, but a declarative and reusable one. Here is the same implementation as a one-line, succinct but less readable:
const omap = f => o => (o = assign(o), map(x => o[x] = f(o[x])) (keys(o)), o);
ES2015 specified the iterator and iterable protocols. But objects are still not iterable and thus not mappable. The reason is the mixing of data and program level.
Answered 2023-09-21 08:11:51
Array.prototype.reduce
either. All I want to illustrate here is that the accepted answer somehow "abuses" Array.prototype.reduce
and how a purely functional mapping could be implemented. If you're not interested in functional programming, just ignore my answer. - anyone fold
is more generic than a map
(functor). However, this was my knowledge from mid-2016. That's half an eternity :D - anyone For maximum performance.
If your object doesn't change often but needs to be iterated on often I suggest using a native Map as a cache.
// example object
var obj = {a: 1, b: 2, c: 'something'};
// caching map
var objMap = new Map(Object.entries(obj));
// fast iteration on Map object
objMap.forEach((item, key) => {
// do something with an item
console.log(key, item);
});
Object.entries already works in Chrome, Edge, Firefox and beta Opera so it's a future-proof feature. It's from ES7 so polyfill it https://github.com/es-shims/Object.entries for IE where it doesn't work.
Answered 2023-09-21 08:11:51
const fn = v => v * 2; const newObj = Object.entries(myObject).reduce((acc, [k,v]) => Object.assign({}, acc, {[k]: fn(v)}), {});
- anyone You can convert an object to array simply by using the following:
You can convert the object values to an array:
myObject = { 'a': 1, 'b': 2, 'c': 3 };
let valuesArray = Object.values(myObject);
console.log(valuesArray);
You can convert the object keys to an array:
myObject = { 'a': 1, 'b': 2, 'c': 3 };
let keysArray = Object.keys(myObject);
console.log(keysArray);
Now you can perform normal array operations, including the 'map' function
Answered 2023-09-21 08:11:51
you can use map
method and forEach
on arrays but if you want to use it on Object
then you can use it with twist like below:
Using Javascript (ES6)
var obj = { 'a': 2, 'b': 4, 'c': 6 };
Object.entries(obj).map( v => obj[v[0]] *= v[1] );
console.log(obj); //it will log as {a: 4, b: 16, c: 36}
var obj2 = { 'a': 4, 'b': 8, 'c': 10 };
Object.entries(obj2).forEach( v => obj2[v[0]] *= v[1] );
console.log(obj2); //it will log as {a: 16, b: 64, c: 100}
Using jQuery
var ob = { 'a': 2, 'b': 4, 'c': 6 };
$.map(ob, function (val, key) {
ob[key] *= val;
});
console.log(ob) //it will log as {a: 4, b: 16, c: 36}
Or you can use other loops also like $.each
method as below example:
$.each(ob,function (key, value) {
ob[key] *= value;
});
console.log(ob) //it will also log as {a: 4, b: 16, c: 36}
Answered 2023-09-21 08:11:51
$
is jquery? - anyone The map function
does not exist on the Object.prototype
however you can emulate it like so
var myMap = function ( obj, callback ) {
var result = {};
for ( var key in obj ) {
if ( Object.prototype.hasOwnProperty.call( obj, key ) ) {
if ( typeof callback === 'function' ) {
result[ key ] = callback.call( obj, obj[ key ], key, obj );
}
}
}
return result;
};
var myObject = { 'a': 1, 'b': 2, 'c': 3 };
var newObject = myMap( myObject, function ( value, key ) {
return value * value;
});
Answered 2023-09-21 08:11:51
typeof callback === 'function'
absolutely redundant. 1) map
has no meaning without callback 2) if callback
isn't function, yours map
implementation just runs meaningless for-loop. Also, Object.prototype.hasOwnProperty.call( obj, key )
is a bit overkill. - anyone EDIT: The canonical way using newer JavaScript features is -
const identity = x =>
x
const omap = (f = identity, o = {}) =>
Object.fromEntries(
Object.entries(o).map(([ k, v ]) =>
[ k, f(v) ]
)
)
Where o
is some object and f
is your mapping function. Or we could say, given a function from a -> b
, and an object with values of type a
, produce an object with values of type b
. As a pseudo type signature -
// omap : (a -> b, { a }) -> { b }
The original answer was written to demonstrate a powerful combinator, mapReduce
which allows us to think of our transformation in a different way
m
, the mapping function – gives you a chance to transform the incoming element before…r
, the reducing function – this function combines the accumulator with the result of the mapped elementIntuitively, mapReduce
creates a new reducer we can plug directly into Array.prototype.reduce
. But more importantly, we can implement our object functor implementation omap
plainly by utilizing the object monoid, Object.assign
and {}
.
const identity = x =>
x
const mapReduce = (m, r) =>
(a, x) => r (a, m (x))
const omap = (f = identity, o = {}) =>
Object
.keys (o)
.reduce
( mapReduce
( k => ({ [k]: f (o[k]) })
, Object.assign
)
, {}
)
const square = x =>
x * x
const data =
{ a : 1, b : 2, c : 3 }
console .log (omap (square, data))
// { a : 1, b : 4, c : 9 }
Notice the only part of the program we actually had to write is the mapping implementation itself –
k => ({ [k]: f (o[k]) })
Which says, given a known object o
and some key k
, construct an object and whose computed property k
is the result of calling f
on the key's value, o[k]
.
We get a glimpse of mapReduce
's sequencing potential if we first abstract oreduce
// oreduce : (string * a -> string * b, b, { a }) -> { b }
const oreduce = (f = identity, r = null, o = {}) =>
Object
.keys (o)
.reduce
( mapReduce
( k => [ k, o[k] ]
, f
)
, r
)
// omap : (a -> b, {a}) -> {b}
const omap = (f = identity, o = {}) =>
oreduce
( mapReduce
( ([ k, v ]) =>
({ [k]: f (v) })
, Object.assign
)
, {}
, o
)
Everything works the same, but omap
can be defined at a higher-level now. Of course the new Object.entries
makes this look silly, but the exercise is still important to the learner.
You won't see the full potential of mapReduce
here, but I share this answer because it's interesting to see just how many places it can be applied. If you're interested in how it is derived and other ways it could be useful, please see this answer.
Answered 2023-09-21 08:11:51
Map
and Map.entries
, OK :D. I'm tired of abusing plain objects as map data types. - anyone Map
should be used where/when possible, but it does not totally replace the need to use these procedures on plain JS objects tho :D - anyone const array = Object.keys(object)
//returns all keys as array ["key", "key"]
const array = Object.values(object)
//returns all values as array ["value", "value"]
const array = Object.entries(object)
//returns all entries as array = [["key","value"], ["key","value"]]
Use Map on the result.
array.map()
Answered 2023-09-21 08:11:51
Based on @Amberlamps answer, here's a utility function (as a comment it looked ugly)
function mapObject(obj, mapFunc){
return Object.keys(obj).reduce(function(newObj, value) {
newObj[value] = mapFunc(obj[value]);
return newObj;
}, {});
}
and the use is:
var obj = {a:1, b:3, c:5}
function double(x){return x * 2}
var newObj = mapObject(obj, double);
//=> {a: 2, b: 6, c: 10}
Answered 2023-09-21 08:11:51
I came upon this as a first-item in a Google search trying to learn to do this, and thought I would share for other folsk finding this recently the solution I found, which uses the npm package immutable.
I think its interesting to share because immutable uses the OP's EXACT situation in their own documentation - the following is not my own code but pulled from the current immutable-js documentation:
const { Seq } = require('immutable')
const myObject = { a: 1, b: 2, c: 3 }
Seq(myObject).map(x => x * x).toObject();
// { a: 1, b: 4, c: 9 }
Not that Seq has other properties ("Seq describes a lazy operation, allowing them to efficiently chain use of all the higher-order collection methods (such as map and filter) by not creating intermediate collections") and that some other immutable-js data structures might also do the job quite efficiently.
Anyone using this method will of course have to npm install immutable
and might want to read the docs:
Answered 2023-09-21 08:11:51
I like the examples that use Object.fromEntries
such as this one, but still, they are not very easy to use. The answers that use Object.keys
and then look up the key
are actually doing multiple look-ups that may not be necessary.
I wished there was an Object.map
function, but we can create our own and call it objectMap
with the ability to modify both key
and value
:
Usage (JavaScript):
const myObject = { 'a': 1, 'b': 2, 'c': 3 };
// keep the key and modify the value
let obj = objectMap(myObject, val => val * 2);
// obj = { a: 2, b: 4, c: 6 }
// modify both key and value
obj = objectMap(myObject,
val => val * 2 + '',
key => (key + key).toUpperCase());
// obj = { AA: '2', BB: '4', CC: '6' }
Code (TypeScript):
interface Dictionary<T> {
[key: string]: T;
}
function objectMap<TValue, TResult>(
obj: Dictionary<TValue>,
valSelector: (val: TValue, obj: Dictionary<TValue>) => TResult,
keySelector?: (key: string, obj: Dictionary<TValue>) => string,
ctx?: Dictionary<TValue>
) {
const ret = {} as Dictionary<TResult>;
for (const key of Object.keys(obj)) {
const retKey = keySelector
? keySelector.call(ctx || null, key, obj)
: key;
const retVal = valSelector.call(ctx || null, obj[key], obj);
ret[retKey] = retVal;
}
return ret;
}
If you are not using TypeScript then copy the above code in TypeScript Playground to get the JavaScript code.
Also, the reason I put keySelector
after valSelector
in the parameter list, is because it is optional.
* Some credit go to alexander-mills' answer.
Answered 2023-09-21 08:11:51
My response is largely based off the highest rated response here and hopefully everyone understands (have the same explanation on my GitHub, too). This is why his impementation with map works:
Object.keys(images).map((key) => images[key] = 'url(' + '"' + images[key] + '"' +
')');
The purpose of the function is to take an object and modify the original contents of the object using a method available to all objects (objects and arrays alike) without returning an array. Almost everything within JS is an object, and for that reason elements further down the pipeline of inheritance can potentially technically use those available to those up the line (and the reverse it appears).
The reason that this works is due to the .map functions returning an array REQUIRING that you provide an explicit or implicit RETURN of an array instead of simply modifying an existing object. You essentially trick the program into thinking the object is an array by using Object.keys which will allow you to use the map function with its acting on the values the individual keys are associated with (I actually accidentally returned arrays but fixed it). As long as there isn't a return in the normal sense, there will be no array created with the original object stil intact and modified as programmed.
This particular program takes an object called images and takes the values of its keys and appends url tags for use within another function. Original is this:
var images = {
snow: 'https://www.trbimg.com/img-5aa059f5/turbine/bs-md-weather-20180305',
sunny: 'http://www.cubaweather.org/images/weather-photos/large/Sunny-morning-east-
Matanzas-city- Cuba-20170131-1080.jpg',
rain: 'https://i.pinimg.com/originals/23/d8
/ab/23d8ab1eebc72a123cebc80ce32b43d8.jpg' };
...and modified is this:
var images = {
snow: url('https://www.trbimg.com/img-5aa059f5/turbine/bs-md-weather-20180305'),
sunny: url('http://www.cubaweather.org/images/weather-photos/large/Sunny-morning-
east-Matanzas-city- Cuba-20170131-1080.jpg'),
rain: url('https://i.pinimg.com/originals/23/d8
/ab/23d8ab1eebc72a123cebc80ce32b43d8.jpg')
};
The object's original structure is left intact allowing for normal property access as long as there isn't a return. Do NOT have it return an array like normal and everything will be fine. The goal is REASSIGNING the original values (images[key]) to what is wanted and not anything else. As far as I know, in order to prevent array output there HAS to be REASSIGNMENT of images[key] and no implicit or explicit request to return an array (variable assignment does this and was glitching back and forth for me).
EDIT:
Going to address his other method regarding new object creation to avoid modifying original object (and reassignment appears to still be necessary in order to avoid accidentally creating an array as output). These functions use arrow syntax and are if you simply want to create a new object for future use.
const mapper = (obj, mapFn) => Object.keys(obj).reduce((result, key) => {
result[key] = mapFn(obj)[key];
return result;
}, {});
var newImages = mapper(images, (value) => value);
The way these functions work is like so:
mapFn takes the function to be added later (in this case (value) => value) and simply returns whatever is stored there as a value for that key (or multiplied by two if you change the return value like he did) in mapFn(obj)[key],
and then redefines the original value associated with the key in result[key] = mapFn(obj)[key]
and returns the operation performed on result (the accumulator located in the brackets initiated at the end of the .reduce function).
All of this is being performed on the chosen object and STILL there CANNOT be an implicit request for a returned array and only works when reassigning values as far as I can tell. This requires some mental gymnastics but reduces the lines of code needed as can be seen above. Output is exactly the same as can be seen below:
{snow: "https://www.trbimg.com/img-5aa059f5/turbine/bs-
md-weather-20180305", sunny: "http://www.cubaweather.org/images/weather-
photos/l…morning-east-Matanzas-city-Cuba-20170131-1080.jpg", rain:
"https://i.pinimg.com/originals/23/d8
/ab/23d8ab1eebc72a123cebc80ce32b43d8.jpg"}
Keep in mind this worked with NON-NUMBERS. You CAN duplicate ANY object by SIMPLY RETURNING THE VALUE in the mapFN function.
Answered 2023-09-21 08:11:51
const mapObject = (targetObject, callbackFn) => {
if (!targetObject) return targetObject;
if (Array.isArray(targetObject)){
return targetObject.map((v)=>mapObject(v, callbackFn))
}
return Object.entries(targetObject).reduce((acc,[key, value]) => {
const res = callbackFn(key, value);
if (!Array.isArray(res) && typeof res ==='object'){
return {...acc, [key]: mapObject(res, callbackFn)}
}
if (Array.isArray(res)){
return {...acc, [key]: res.map((v)=>mapObject(v, callbackFn))}
}
return {...acc, [key]: res};
},{})
};
const mapped = mapObject(a,(key,value)=> {
if (!Array.isArray(value) && key === 'a') return ;
if (!Array.isArray(value) && key === 'e') return [];
if (!Array.isArray(value) && key === 'g') return value * value;
return value;
});
console.log(JSON.stringify(mapped));
// {"b":2,"c":[{"d":2,"e":[],"f":[{"g":4}]}]}
This function goes recursively through the object and arrays of objects. Attributes can be deleted if returned undefined
Answered 2023-09-21 08:11:51
This is my way to do it and results to be worth in terms of efficiency and readability.
myObject = { 'a': 1, 'b': 2, 'c': 3 }
const newObject = Object.entries(myObject)
.map(([key, value]) => `${key}: ${value * value}`)
.join(', ');
console.log(newObject)
Answered 2023-09-21 08:11:51
I needed a version that allowed modifying the keys as well (based on @Amberlamps and @yonatanmn answers);
var facts = [ // can be an object or array - see jsfiddle below
{uuid:"asdfasdf",color:"red"},
{uuid:"sdfgsdfg",color:"green"},
{uuid:"dfghdfgh",color:"blue"}
];
var factObject = mapObject({}, facts, function(key, item) {
return [item.uuid, {test:item.color, oldKey:key}];
});
function mapObject(empty, obj, mapFunc){
return Object.keys(obj).reduce(function(newObj, key) {
var kvPair = mapFunc(key, obj[key]);
newObj[kvPair[0]] = kvPair[1];
return newObj;
}, empty);
}
factObject=
{
"asdfasdf": {"color":"red","oldKey":"0"},
"sdfgsdfg": {"color":"green","oldKey":"1"},
"dfghdfgh": {"color":"blue","oldKey":"2"}
}
Edit: slight change to pass in the starting object {}. Allows it to be [] (if the keys are integers)
Answered 2023-09-21 08:11:51
var myObject = { 'a': 1, 'b': 2, 'c': 3 };
Object.prototype.map = function(fn){
var oReturn = {};
for (sCurObjectPropertyName in this) {
oReturn[sCurObjectPropertyName] = fn(this[sCurObjectPropertyName], sCurObjectPropertyName);
}
return oReturn;
}
Object.defineProperty(Object.prototype,'map',{enumerable:false});
newObject = myObject.map(function (value, label) {
return value * value;
});
// newObject is now { 'a': 1, 'b': 4, 'c': 9 }
Answered 2023-09-21 08:11:51
enumerable
defaults to false
- anyone If anyone was looking for a simple solution that maps an object to a new object or to an array:
// Maps an object to a new object by applying a function to each key+value pair.
// Takes the object to map and a function from (key, value) to mapped value.
const mapObject = (obj, fn) => {
const newObj = {};
Object.keys(obj).forEach(k => { newObj[k] = fn(k, obj[k]); });
return newObj;
};
// Maps an object to a new array by applying a function to each key+value pair.
// Takes the object to map and a function from (key, value) to mapped value.
const mapObjectToArray = (obj, fn) => (
Object.keys(obj).map(k => fn(k, obj[k]))
);
This may not work for all objects or all mapping functions, but it works for plain shallow objects and straightforward mapping functions which is all I needed.
Answered 2023-09-21 08:11:51
To responds more closely to what precisely the OP asked for, the OP wants an object:
myObject = { 'a': 1, 'b': 2, 'c': 3 }
to have a map method myObject.map
,
similar to Array.prototype.map that would be used as follows:
newObject = myObject.map(function (value, label) { return value * value; }); // newObject is now { 'a': 1, 'b': 4, 'c': 9 }
The imho best (measured in terms to "close to what is asked" + "no ES{5,6,7} required needlessly") answer would be:
myObject.map = function mapForObject(callback)
{
var result = {};
for(var property in this){
if(this.hasOwnProperty(property) && property != "map"){
result[property] = callback(this[property],property,this);
}
}
return result;
}
The code above avoids intentionally using any language features, only available in recent ECMAScript editions. With the code above the problem can be solved lke this:
myObject = { 'a': 1, 'b': 2, 'c': 3 };
myObject.map = function mapForObject(callback)
{
var result = {};
for(var property in this){
if(this.hasOwnProperty(property) && property != "map"){
result[property] = callback(this[property],property,this);
}
}
return result;
}
newObject = myObject.map(function (value, label) {
return value * value;
});
console.log("newObject is now",newObject);
Besides frowned upon by some, it would be a possibility to insert the solution in the prototype chain like this.
Object.prototype.map = function(callback)
{
var result = {};
for(var property in this){
if(this.hasOwnProperty(property)){
result[property] = callback(this[property],property,this);
}
}
return result;
}
Something, which when done with careful oversight should not have any ill effects and not impact map
method of other objects (i.e. Array's map
).
Answered 2023-09-21 08:11:51
First, convert your HTMLCollection using Object.entries(collection). Then it’s an iterable you can now use the .map method on it.
Object.entries(collection).map(...)
Answered 2023-09-21 08:11:51
I handle only strings to reduce exemptions:
Object.keys(params).map(k => typeof params[k] == "string" ? params[k] = params[k].trim() : null);
Answered 2023-09-21 08:11:51
If you're interested in map
ping not only values but also keys, I have written Object.map(valueMapper, keyMapper)
, that behaves this way:
var source = { a: 1, b: 2 };
function sum(x) { return x + x }
source.map(sum); // returns { a: 2, b: 4 }
source.map(undefined, sum); // returns { aa: 1, bb: 2 }
source.map(sum, sum); // returns { aa: 2, bb: 4 }
Answered 2023-09-21 08:11:51
npm install @mattisg/object.map
. - anyone Hey wrote a little mapper function that might help.
function propertyMapper(object, src){
for (var property in object) {
for (var sourceProp in src) {
if(property === sourceProp){
if(Object.prototype.toString.call( property ) === '[object Array]'){
propertyMapper(object[property], src[sourceProp]);
}else{
object[property] = src[sourceProp];
}
}
}
}
}
Answered 2023-09-21 08:11:51