How do I raise an exception in Python so that it can later be caught via an except
block?
How do I manually throw/raise an exception in Python?
Use the most specific Exception constructor that semantically fits your issue.
Be specific in your message, e.g.:
raise ValueError('A very specific bad thing happened.')
Avoid raising a generic Exception
. To catch it, you'll have to catch all other more specific exceptions that subclass it.
raise Exception('I know Python!') # Don't! If you catch, likely to hide bugs.
For example:
def demo_bad_catch():
try:
raise ValueError('Represents a hidden bug, do not catch this')
raise Exception('This is the exception you expect to handle')
except Exception as error:
print('Caught this error: ' + repr(error))
>>> demo_bad_catch()
Caught this error: ValueError('Represents a hidden bug, do not catch this',)
And more specific catches won't catch the general exception:
def demo_no_catch():
try:
raise Exception('general exceptions not caught by specific handling')
except ValueError as e:
print('we will not catch exception: Exception')
>>> demo_no_catch()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "<stdin>", line 3, in demo_no_catch
Exception: general exceptions not caught by specific handling
raise
statementInstead, use the most specific Exception constructor that semantically fits your issue.
raise ValueError('A very specific bad thing happened')
which also handily allows an arbitrary number of arguments to be passed to the constructor:
raise ValueError('A very specific bad thing happened', 'foo', 'bar', 'baz')
These arguments are accessed by the args
attribute on the Exception
object. For example:
try:
some_code_that_may_raise_our_value_error()
except ValueError as err:
print(err.args)
prints
('message', 'foo', 'bar', 'baz')
In Python 2.5, an actual message
attribute was added to BaseException
in favor of encouraging users to subclass Exceptions and stop using args
, but the introduction of message
and the original deprecation of args has been retracted.
except
clauseWhen inside an except clause, you might want to, for example, log that a specific type of error happened, and then re-raise. The best way to do this while preserving the stack trace is to use a bare raise statement. For example:
logger = logging.getLogger(__name__)
try:
do_something_in_app_that_breaks_easily()
except AppError as error:
logger.error(error)
raise # just this!
# raise AppError # Don't do this, you'll lose the stack trace!
You can preserve the stacktrace (and error value) with sys.exc_info()
, but this is way more error prone and has compatibility problems between Python 2 and 3, prefer to use a bare raise
to re-raise.
To explain - the sys.exc_info()
returns the type, value, and traceback.
type, value, traceback = sys.exc_info()
This is the syntax in Python 2 - note this is not compatible with Python 3:
raise AppError, error, sys.exc_info()[2] # avoid this.
# Equivalently, as error *is* the second object:
raise sys.exc_info()[0], sys.exc_info()[1], sys.exc_info()[2]
If you want to, you can modify what happens with your new raise - e.g. setting new args
for the instance:
def error():
raise ValueError('oops!')
def catch_error_modify_message():
try:
error()
except ValueError:
error_type, error_instance, traceback = sys.exc_info()
error_instance.args = (error_instance.args[0] + ' <modification>',)
raise error_type, error_instance, traceback
And we have preserved the whole traceback while modifying the args. Note that this is not a best practice and it is invalid syntax in Python 3 (making keeping compatibility much harder to work around).
>>> catch_error_modify_message()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "<stdin>", line 3, in catch_error_modify_message
File "<stdin>", line 2, in error
ValueError: oops! <modification>
In Python 3:
raise error.with_traceback(sys.exc_info()[2])
Again: avoid manually manipulating tracebacks. It's less efficient and more error prone. And if you're using threading and sys.exc_info
you may even get the wrong traceback (especially if you're using exception handling for control flow - which I'd personally tend to avoid.)
In Python 3, you can chain Exceptions, which preserve tracebacks:
raise RuntimeError('specific message') from error
Be aware:
These can easily hide and even get into production code. You want to raise an exception, and doing them will raise an exception, but not the one intended!
Valid in Python 2, but not in Python 3 is the following:
raise ValueError, 'message' # Don't do this, it's deprecated!
Only valid in much older versions of Python (2.4 and lower), you may still see people raising strings:
raise 'message' # really really wrong. don't do this.
In all modern versions, this will actually raise a TypeError
, because you're not raising a BaseException
type. If you're not checking for the right exception and don't have a reviewer that's aware of the issue, it could get into production.
I raise Exceptions to warn consumers of my API if they're using it incorrectly:
def api_func(foo):
'''foo should be either 'baz' or 'bar'. returns something very useful.'''
if foo not in _ALLOWED_ARGS:
raise ValueError('{foo} wrong, use "baz" or "bar"'.format(foo=repr(foo)))
"I want to make an error on purpose, so that it would go into the except"
You can create your own error types, if you want to indicate something specific is wrong with your application, just subclass the appropriate point in the exception hierarchy:
class MyAppLookupError(LookupError):
'''raise this when there's a lookup error for my app'''
and usage:
if important_key not in resource_dict and not ok_to_be_missing:
raise MyAppLookupError('resource is missing, and that is not ok.')
Answered 2023-09-20 20:19:59
ValueError
and reporting it as the type, Exception
, and that's an unnecessary loss of precision. repr(e)
will at least report the type for you. - anyone raise TypeError("my message")
- anyone TypeError
, was a call to a class constructor! Makes sense now. The message is therefore a common constructor arg for error-type classes. - anyone Don't do this. Raising a bare
Exception
is absolutely not the right thing to do; see Aaron Hall's excellent answer instead.
It can't get much more Pythonic than this:
raise Exception("I know Python!")
Replace Exception
with the specific type of exception you want to throw.
See the raise statement documentation for Python if you'd like more information.
Answered 2023-09-20 20:19:59
In Python 3 there are four different syntaxes for raising exceptions:
If you use raise exception (args)
to raise an exception then the args
will be printed when you print the exception object - as shown in the example below.
# Raise exception (args)
try:
raise ValueError("I have raised an Exception")
except ValueError as exp:
print("Error", exp) # Output -> Error I have raised an Exception
# Raise exception
try:
raise ValueError
except ValueError as exp:
print("Error", exp) # Output -> Error
The raise
statement without any arguments re-raises the last exception.
This is useful if you need to perform some actions after catching the exception and then want to re-raise it. But if there wasn't any exception before, the raise
statement raises a TypeError
Exception.
def somefunction():
print("some cleaning")
a = 10
b = 0
result = None
try:
result = a / b
print(result)
except Exception: # Output ->
somefunction() # Some cleaning
raise # Traceback (most recent call last):
# File "python", line 9, in <module>
# ZeroDivisionError: division by zero
This statement is used to create exception chaining in which an exception that is raised in response to another exception can contain the details of the original exception - as shown in the example below.
class MyCustomException(Exception):
pass
a = 10
b = 0
reuslt = None
try:
try:
result = a / b
except ZeroDivisionError as exp:
print("ZeroDivisionError -- ",exp)
raise MyCustomException("Zero Division ") from exp
except MyCustomException as exp:
print("MyException",exp)
print(exp.__cause__)
Output:
ZeroDivisionError -- division by zero
MyException Zero Division
division by zero
Answered 2023-09-20 20:19:59
exception(args)
over exception (args)
- anyone raise exception(args) from None
to say that the currently active exception was handled and is no longer of interest. Otherwise if you raise an exception inside an except
block and it isn't handled, tracebacks for both exceptions will be shown separated by the message “During handling of the above exception, another exception occurred” - anyone For the common case where you need to throw an exception in response to some unexpected conditions, and that you never intend to catch, but simply to fail fast to enable you to debug from there if it ever happens — the most logical one seems to be AssertionError
:
if 0 < distance <= RADIUS:
#Do something.
elif RADIUS < distance:
#Do something.
else:
raise AssertionError("Unexpected value of 'distance'!", distance)
Answered 2023-09-20 20:19:59
ValueError
than AssertionError
because there's no problem with an assertion (because none is being made here) -- the problem is with a value. If you really want an AssertionError
in this case, write assert distance > 0, 'Distance must be positive'
. But you shouldn't error check that way because assertions can be turned off (python -O
). - anyone -O
. - anyone Read the existing answers first, this is just an addendum.
Notice that you can raise exceptions with or without arguments.
Example:
raise SystemExit
exits the program, but you might want to know what happened. So you can use this.
raise SystemExit("program exited")
This will print "program exited" to standard error before closing the program.
Answered 2023-09-20 20:19:59
raise SystemExit()
be the better choice? Why does the first one even work? - anyone Just to note: there are times when you do want to handle generic exceptions. If you're processing a bunch of files and logging your errors, you might want to catch any error that occurs for a file, log it, and continue processing the rest of the files. In that case, a
try:
foo()
except Exception as e:
print(e) # Print out handled error
block is a good way to do it. You'll still want to raise
specific exceptions so you know what they mean, though.
Answered 2023-09-20 20:19:59
Another way to throw an exception is using assert
. You can use assert to verify a condition is being fulfilled. If not, then it will raise AssertionError
. For more details have a look here.
def avg(marks):
assert len(marks) != 0, "List is empty."
return sum(marks)/len(marks)
mark2 = [55,88,78,90,79]
print("Average of mark2:", avg(mark2))
mark1 = []
print("Average of mark1:", avg(mark1))
Answered 2023-09-20 20:19:59
raise AssertionError()
- anyone You might also want to raise custom exceptions. For example, if you're writing a library, it's a very good practice to make a base exception class for your module, and then have custom sub-exceptions to be more specific.
You can achieve that like this:
class MyModuleBaseClass(Exception):
pass
class MoreSpecificException(MyModuleBaseClass):
pass
# To raise custom exceptions, you can just
# use the raise keyword
raise MoreSpecificException
raise MoreSpecificException('message')
If you're not interested in having a custom base class, you can just inherit your custom exception classes from an ordinary exception class like Exception
, TypeError
, ValueError
, etc.
Answered 2023-09-20 20:19:59
If you don't care about which error to raise, you could use assert
to raise an AssertionError
:
>>> assert False, "Manually raised error"
Traceback (most recent call last):
File "<pyshell#24>", line 1, in <module>
assert False, "Manually raised error"
AssertionError: Manually raised error
>>>
The assert
keyword raises an AssertionError
if the condition is False
. In this case, we specified False
directly, so it raises the error, but to have it have a text we want it to raise to, we add a comma and specify the error text we want. In this case, I wrote Manually raised error
and this raises it with that text.
Answered 2023-09-20 20:19:59
You should learn the raise statement of Python for that.
It should be kept inside the try block.
Example -
try:
raise TypeError # Replace TypeError by any other error if you want
except TypeError:
print('TypeError raised')
Answered 2023-09-20 20:19:59
If you don’t care about the raised exception, do:
def crash(): return 0/0
It does not allow you to throw a specific message to your user but will crash the python interpriter.
For the more advanced python users who have used python may think that the expression will be evaluated at compile time (python is compiled) but the python compiler wont evaluate the expression at run time.
If we look at what tthe dis
dissasembely module for python shows, we can see the bytecode.
2 LOAD_CONST 1 (0)
4 LOAD_CONST 1 (0)
6 BINARY_OP 11 (/)
So essentialy python will push the constant 0 onto the stack and another 0 then run a binary operator, to divide.
Although this function is quite useless, and should never be used in production code, it can still crash the python interpriter.
Answered 2023-09-20 20:19:59