Compare two dates with JavaScript

Asked 2023-09-20 20:25:02 View 356,401

Can someone suggest a way to compare the values of two dates greater than, less than, and not in the past using JavaScript? The values will be coming from text boxes.

  • When it comes to DateTime and manipulation in JS, I look no further than momentjs :) - anyone
  • no need to use momentjs to compare 2 dates. Just use pure javascript's Date object. Check main answer for more details. - anyone
  • You can refer following answer : stackoverflow.com/questions/4812152/… Check getDateDifference and getDifferenceInDays if it can help. - anyone
  • I'll give you a reason to look further than Moment.js (which I love, BUT...): Don't use for looping loads - anyone
  • For those like me who may have come along later, moment.js is now in "maintenance mode," i.e. no longer being actively developed. - anyone

Answers

The Date object will do what you want - construct one for each date, then compare them using the >, <, <= or >=.

The ==, !=, ===, and !== operators require you to use date.getTime() as in

var d1 = new Date();
var d2 = new Date(d1);
var same = d1.getTime() === d2.getTime();
var notSame = d1.getTime() !== d2.getTime();

to be clear just checking for equality directly with the date objects won't work

var d1 = new Date();
var d2 = new Date(d1);

console.log(d1 == d2);   // prints false (wrong!) 
console.log(d1 === d2);  // prints false (wrong!)
console.log(d1 != d2);   // prints true  (wrong!)
console.log(d1 !== d2);  // prints true  (wrong!)
console.log(d1.getTime() === d2.getTime()); // prints true (correct)

I suggest you use drop-downs or some similar constrained form of date entry rather than text boxes, though, lest you find yourself in input validation hell.


For the curious, date.getTime() documentation:

Returns the numeric value of the specified date as the number of milliseconds since January 1, 1970, 00:00:00 UTC. (Negative values are returned for prior times.)

Answered   2023-09-20 20:25:02

  • Even Ace's method is not failsafe. You need to reset the milliseconds first, and you might even want to reset the whole time. date1.setHours(0); date1.setMinutes(0); date1.setSeconds(0); date1.setMilliseconds(0); That combined with using .getTime() will give you an accurate compare result - anyone
  • @patrick, suggest calling setHours(0,0,0,0) this way. Eliminates the need for calling setMinutes() etc. Also, executes faster. - anyone
  • avoiding == or === to get desired result: jsfiddle.net/P4y5J now >= anotherNow && now <= anotherNow IS true FYI - anyone
  • You can also compare the numeric values of your dates in order to avoid comparing the objects themselves: date1.valueOf() == date2.valueOf() - anyone
  • @Karl even shorter than setHours(0,0,0,0) and getTime() would be d1.toDateString() === d2.toDateString() if you just wanted to compare the 'date part of the Date' only rather than the 'date and time parts of the Date' (how confusing can naming be ;-) - anyone

Compare < and > just as usual, but anything involving == or === should use a + prefix. Like so:

const x = new Date('2013-05-23');
const y = new Date('2013-05-23');

// less than, greater than is fine:
console.log('x < y', x < y); // false
console.log('x > y', x > y); // false
console.log('x <= y', x <= y); // true
console.log('x >= y', x >= y); // true
console.log('x === y', x === y); // false, oops!

// anything involving '==' or '===' should use the '+' prefix
// it will then compare the dates' millisecond values

console.log('+x === +y', +x === +y); // true

Answered   2023-09-20 20:25:02

  • terribly slow :) I prefer x.getTime() === y.getTime() method, both readable and extremely fast see jsperf - anyone
  • The + operator attempts to convert the expression into a Number. Date.valueOf() is used for the conversion (which returns the same thing as Date.getTime(). - anyone
  • @daniel < and <= use same algorithm (abstract relational comparison), likewise for > and >=. The answer was popular but wrong. Please correct the first line which I forgot to edit. - anyone
  • @huysentruitw The original jsperf URL is down, but it has been archived on web.archive.org. You can even run the benchmark from the archived version. TL;DR: comparing using .getTime() is at least 100 times quicker than comparing the Date objects directly. - anyone
  • if standard == needs type coercion with +, does <= work correctly for the case the dates are equal? - anyone

The easiest way to compare dates in javascript is to first convert it to a Date object and then compare these date-objects.

Below you find an object with three functions:

  • dates.compare(a,b)

    Returns a number:

    • -1 if a < b
    • 0 if a = b
    • 1 if a > b
    • NaN if a or b is an illegal date
  • dates.inRange (d,start,end)

    Returns a boolean or NaN:

    • true if d is between the start and end (inclusive)
    • false if d is before start or after end.
    • NaN if one or more of the dates are illegal.
  • dates.convert

    Used by the other functions to convert their input to a date object. The input can be

    • a date-object : The input is returned as is.
    • an array: Interpreted as [year,month,day]. NOTE month is 0-11.
    • a number : Interpreted as number of milliseconds since 1 Jan 1970 (a timestamp)
    • a string : Several different formats is supported, like "YYYY/MM/DD", "MM/DD/YYYY", "Jan 31 2009" etc.
    • an object: Interpreted as an object with year, month and date attributes. NOTE month is 0-11.

.

// Source: http://stackoverflow.com/questions/497790
var dates = {
    convert:function(d) {
        // Converts the date in d to a date-object. The input can be:
        //   a date object: returned without modification
        //  an array      : Interpreted as [year,month,day]. NOTE: month is 0-11.
        //   a number     : Interpreted as number of milliseconds
        //                  since 1 Jan 1970 (a timestamp) 
        //   a string     : Any format supported by the javascript engine, like
        //                  "YYYY/MM/DD", "MM/DD/YYYY", "Jan 31 2009" etc.
        //  an object     : Interpreted as an object with year, month and date
        //                  attributes.  **NOTE** month is 0-11.
        return (
            d.constructor === Date ? d :
            d.constructor === Array ? new Date(d[0],d[1],d[2]) :
            d.constructor === Number ? new Date(d) :
            d.constructor === String ? new Date(d) :
            typeof d === "object" ? new Date(d.year,d.month,d.date) :
            NaN
        );
    },
    compare:function(a,b) {
        // Compare two dates (could be of any type supported by the convert
        // function above) and returns:
        //  -1 : if a < b
        //   0 : if a = b
        //   1 : if a > b
        // NaN : if a or b is an illegal date
        // NOTE: The code inside isFinite does an assignment (=).
        return (
            isFinite(a=this.convert(a).valueOf()) &&
            isFinite(b=this.convert(b).valueOf()) ?
            (a>b)-(a<b) :
            NaN
        );
    },
    inRange:function(d,start,end) {
        // Checks if date in d is between dates in start and end.
        // Returns a boolean or NaN:
        //    true  : if d is between start and end (inclusive)
        //    false : if d is before start or after end
        //    NaN   : if one or more of the dates is illegal.
        // NOTE: The code inside isFinite does an assignment (=).
       return (
            isFinite(d=this.convert(d).valueOf()) &&
            isFinite(start=this.convert(start).valueOf()) &&
            isFinite(end=this.convert(end).valueOf()) ?
            start <= d && d <= end :
            NaN
        );
    }
}

Answered   2023-09-20 20:25:02

  • (a > b) - (a < b) is useful for sorting dates array - anyone

The relational operators < <= > >= can be used to compare JavaScript dates:

var d1 = new Date(2013, 0, 1);
var d2 = new Date(2013, 0, 2);
d1 <  d2; // true
d1 <= d2; // true
d1 >  d2; // false
d1 >= d2; // false

However, the equality operators == != === !== cannot be used to compare (the value of) dates because:

  • Two distinct objects are never equal for either strict or abstract comparisons.
  • An expression comparing Objects is only true if the operands reference the same Object.

You can compare the value of dates for equality using any of these methods:

var d1 = new Date(2013, 0, 1);
var d2 = new Date(2013, 0, 1);
/*
 * note: d1 == d2 returns false as described above
 */
d1.getTime() == d2.getTime(); // true
d1.valueOf() == d2.valueOf(); // true
Number(d1)   == Number(d2);   // true
+d1          == +d2;          // true

Both Date.getTime() and Date.valueOf() return the number of milliseconds since January 1, 1970, 00:00 UTC. Both Number function and unary + operator call the valueOf() methods behind the scenes.

Answered   2023-09-20 20:25:02

By far the easiest method is to subtract one date from the other and compare the result.

var oDateOne = new Date();
var oDateTwo = new Date();

console.log(oDateOne - oDateTwo === 0);
console.log(oDateOne - oDateTwo < 0);
console.log(oDateOne - oDateTwo > 0);

Answered   2023-09-20 20:25:02

  • Why is this not the top answer? So simple. - anyone

Comparing dates in JavaScript is quite easy... JavaScript has built-in comparison system for dates which makes it so easy to do the comparison...

Just follow these steps for comparing 2 dates value, for example you have 2 inputs which each has a Date value in String and you to compare them...

1. you have 2 string values you get from an input and you'd like to compare them, they are as below:

var date1 = '01/12/2018';
var date2 = '12/12/2018';

2. They need to be Date Object to be compared as date values, so simply convert them to date, using new Date(), I just re-assign them for simplicity of explanation, but you can do it anyway you like:

date1 = new Date(date1);
date2 = new Date(date2);

3. Now simply compare them, using the > < >= <=

date1 > date2;  //false
date1 < date2;  //true
date1 >= date2; //false
date1 <= date2; //true

compare dates in javascript

Answered   2023-09-20 20:25:02

Compare day only (ignoring time component):

Date.prototype.sameDay = function(d) {
  return this.getFullYear() === d.getFullYear()
    && this.getDate() === d.getDate()
    && this.getMonth() === d.getMonth();
}

Usage:

if(date1.sameDay(date2)) {
    // highlight day on calendar or something else clever
}

I no longer recommend modifying the prototype of built-in objects. Try this instead:

function isSameDay(d1, d2) {
  return d1.getFullYear() === d2.getFullYear() &&
    d1.getDate() === d2.getDate() &&
    d1.getMonth() === d2.getMonth();
}


console.log(isSameDay(new Date('Jan 15 2021 02:39:53 GMT-0800'), new Date('Jan 15 2021 23:39:53 GMT-0800')));
console.log(isSameDay(new Date('Jan 15 2021 10:39:53 GMT-0800'), new Date('Jan 16 2021 10:39:53 GMT-0800')));

N.B. the year/month/day will be returned for your timezone; I recommend using a timezone-aware library if you want to check if two dates are on the same day in a different timezone.

e.g.

> (new Date('Jan 15 2021 01:39:53 Z')).getDate()  // Jan 15 in UTC
14  // Returns "14" because I'm in GMT-08

Answered   2023-09-20 20:25:02

what format?

If you construct a Javascript Date object, you can just subtract them to get a milliseconds difference (edit: or just compare them) :

js>t1 = new Date()
Thu Jan 29 2009 14:19:28 GMT-0500 (Eastern Standard Time)
js>t2 = new Date()
Thu Jan 29 2009 14:19:31 GMT-0500 (Eastern Standard Time)
js>t2-t1
2672
js>t3 = new Date('2009 Jan 1')
Thu Jan 01 2009 00:00:00 GMT-0500 (Eastern Standard Time)
js>t1-t3
2470768442
js>t1>t3
true

Answered   2023-09-20 20:25:02

Note - Compare Only Date Part:

When we compare two date in javascript. It takes hours, minutes and seconds also into consideration.. So If we only need to compare date only, this is the approach:

var date1= new Date("01/01/2014").setHours(0,0,0,0);

var date2= new Date("01/01/2014").setHours(0,0,0,0);

Now: if date1.valueOf()> date2.valueOf() will work like a charm.

Answered   2023-09-20 20:25:02

  • This is the answer I came to look for! - anyone

The simple way is,

var first = '2012-11-21';
var second = '2012-11-03';

if (new Date(first) > new Date(second) {
    .....
}

Answered   2023-09-20 20:25:02

  • This will not work for for == nor === - anyone

SHORT ANSWER

Here is a function that return {boolean} if the from dateTime > to dateTime Demo in action

var from = '08/19/2013 00:00'
var to = '08/12/2013 00:00 '

function isFromBiggerThanTo(dtmfrom, dtmto){
   return new Date(dtmfrom).getTime() >=  new Date(dtmto).getTime() ;
}
console.log(isFromBiggerThanTo(from, to)); //true

Explanation

jsFiddle

var date_one = '2013-07-29 01:50:00',
date_two = '2013-07-29 02:50:00';
//getTime() returns the number of milliseconds since 01.01.1970.
var timeStamp_date_one = new Date(date_one).getTime() ; //1375077000000 
console.log(typeof timeStamp_date_one);//number 
var timeStamp_date_two = new Date(date_two).getTime() ;//1375080600000 
console.log(typeof timeStamp_date_two);//number 

since you are now having both datetime in number type you can compare them with any Comparison operations

( >, < ,= ,!= ,== ,!== ,>= AND <=)

Then

if you are familiar with C# Custom Date and Time Format String this library should do the exact same thing and help you format your date and time dtmFRM whether you are passing in date time string or unix format

Usage

var myDateTime = new dtmFRM();

alert(myDateTime.ToString(1375077000000, "MM/dd/yyyy hh:mm:ss ampm"));
//07/29/2013 01:50:00 AM

alert(myDateTime.ToString(1375077000000,"the year is yyyy and the day is dddd"));
//this year is 2013 and the day is Monday

alert(myDateTime.ToString('1/21/2014', "this month is MMMM and the day is dd"));
//this month is january and the day is 21

DEMO

all you have to do is passing any of these format pacified in the library js file

Answered   2023-09-20 20:25:02

You can use this code:

var firstValue = "2012-05-12".split('-');
var secondValue = "2014-07-12".split('-');

 var firstDate=new Date();
 firstDate.setFullYear(firstValue[0],(firstValue[1] - 1 ),firstValue[2]);

 var secondDate=new Date();
 secondDate.setFullYear(secondValue[0],(secondValue[1] - 1 ),secondValue[2]);     

  if (firstDate > secondDate)
  {
   alert("First Date  is greater than Second Date");
  }
 else
  {
    alert("Second Date  is greater than First Date");
  }

And also check the MDN article for the Date class.

Answered   2023-09-20 20:25:02

  • This assumes a specific year month date ordering of the string and would be a very fragile implementation for dates expressed in various locale formats. - anyone
function datesEqual(a, b)
{
   return (!(a>b || b>a))
}

Answered   2023-09-20 20:25:02

var date = new Date(); // will give you todays date.

// following calls, will let you set new dates.
setDate()   
setFullYear()   
setHours()  
setMilliseconds()   
setMinutes()    
setMonth()  
setSeconds()    
setTime()

var yesterday = new Date();
yesterday.setDate(...date info here);

if(date>yesterday)  // will compare dates

Answered   2023-09-20 20:25:02

BEWARE THE TIMEZONE

A javascript date has no notion of timezone. It's a moment in time (ticks since the epoch) with handy functions for translating to and from strings in the "local" timezone. If you want to work with dates using date objects, as everyone here is doing, you want your dates to represent UTC midnight at the start of the date in question. This is a common and necessary convention that lets you work with dates regardless of the season or timezone of their creation. So you need to be very vigilant to manage the notion of timezone, particularly when you create your midnight UTC Date object.

Most of the time, you will want your date to reflect the timezone of the user. Click if today is your birthday. Users in NZ and US click at the same time and get different dates. In that case, do this...

// create a date (utc midnight) reflecting the value of myDate and the environment's timezone offset.
new Date(Date.UTC(myDate.getFullYear(),myDate.getMonth(), myDate.getDate()));

Sometimes, international comparability trumps local accuracy. In that case, do this...

// the date in London of a moment in time. Device timezone is ignored.
new Date(Date.UTC(myDate.getUTCYear(), myDate.getyUTCMonth(), myDate.getUTCDate()));

Now you can directly compare your date objects as the other answers suggest.

Having taken care to manage timezone when you create, you also need to be sure to keep timezone out when you convert back to a string representation. So you can safely use...

  • toISOString()
  • getUTCxxx()
  • getTime() //returns a number with no time or timezone.
  • .toLocaleDateString("fr",{timezone:"UTC"}) // whatever locale you want, but ALWAYS UTC.

And totally avoid everything else, especially...

  • getYear(),getMonth(),getDate()

Answered   2023-09-20 20:25:02

Via Moment.js

Jsfiddle: http://jsfiddle.net/guhokemk/1/

function compare(dateTimeA, dateTimeB) {
    var momentA = moment(dateTimeA,"DD/MM/YYYY");
    var momentB = moment(dateTimeB,"DD/MM/YYYY");
    if (momentA > momentB) return 1;
    else if (momentA < momentB) return -1;
    else return 0;
}

alert(compare("11/07/2015", "10/07/2015"));

The method returns 1 if dateTimeA is greater than dateTimeB

The method returns 0 if dateTimeA equals dateTimeB

The method returns -1 if dateTimeA is less than dateTimeB

Answered   2023-09-20 20:25:02

Just to add yet another possibility to the many existing options, you could try:

if (date1.valueOf()==date2.valueOf()) .....

...which seems to work for me. Of course you do have to ensure that both dates are not undefined...

if ((date1?date1.valueOf():0)==(date2?date2.valueOf():0) .....

This way we can ensure that a positive comparison is made if both are undefined also, or...

if ((date1?date1.valueOf():0)==(date2?date2.valueOf():-1) .....

...if you prefer them not to be equal.

Answered   2023-09-20 20:25:02

If following is your date format, you can use this code:

var first = '2012-11-21';
var second = '2012-11-03';
if(parseInt(first.replace(/-/g,""),10) > parseInt(second.replace(/-/g,""),10)){
   //...
}

It will check whether 20121121 number is bigger than 20121103 or not.

Answered   2023-09-20 20:25:02

  • If it already is in ISO8601 format (YYYY-MM-DD) you don't need to remove any characters or convert it to an integer. Just compare the strings first == second or first < second or first > second. That's one of the many beauties with ISO8601 compared to MM/DD/YY, DD/MM/YY, YY/DD/MM, DD/YY/MM or MM/YY/DD. - anyone

Subtract two date get the difference in millisecond, if you get 0 it's the same date

function areSameDate(d1, d2){
    return d1 - d2 === 0
}

Answered   2023-09-20 20:25:02

Say you got the date objects A and B, get their EPOC time value, then subtract to get the difference in milliseconds.

var diff = +A - +B;

That's all.

Answered   2023-09-20 20:25:02

One way to compare two dates is to use the dates.js library.

The Date.compare(Date date1, Date date2) method that returns a number which means the one of following result:

  • -1 = date1 is less than date2.
  • 0 = values are equal.
  • 1 = date1 is greater than date2.

Answered   2023-09-20 20:25:02

Performance

Today 2020.02.27 I perform tests of chosen solutions on Chrome v80.0, Safari v13.0.5 and Firefox 73.0.1 on MacOs High Sierra v10.13.6

Conclusions

  • solutions d1==d2 (D) and d1===d2 (E) are fastest for all browsers
  • solution getTime (A) is faster than valueOf (B) (both are medium fast)
  • solutions F,L,N are slowest for all browsers

enter image description here

Details

In below snippet solutions used in performance tests are presented. You can perform test in you machine HERE

function A(d1,d2) {
	return d1.getTime() == d2.getTime();
}

function B(d1,d2) {
	return d1.valueOf() == d2.valueOf();
}

function C(d1,d2) {
	return Number(d1)   == Number(d2);
}

function D(d1,d2) {
	return d1 == d2;
}

function E(d1,d2) {
	return d1 === d2;
}

function F(d1,d2) {
	return (!(d1>d2 || d2>d1));
}

function G(d1,d2) {
	return d1*1 == d2*1;
}

function H(d1,d2) {
	return +d1 == +d2;
}

function I(d1,d2) {
	return !(+d1 - +d2);
}

function J(d1,d2) {
	return !(d1 - d2);
}

function K(d1,d2) {
	return d1 - d2 == 0;
}

function L(d1,d2) {
	return !((d1>d2)-(d1<d2));
}

function M(d1,d2) {
  return d1.getFullYear() === d2.getFullYear()
    && d1.getDate() === d2.getDate()
    && d1.getMonth() === d2.getMonth();
}

function N(d1,d2) {
	return (isFinite(d1.valueOf()) && isFinite(d2.valueOf()) ? !((d1>d2)-(d1<d2)) : false );
}


// TEST

let past= new Date('2002-12-24'); // past
let now= new Date('2020-02-26');  // now

console.log('Code  d1>d2  d1<d2  d1=d2')
var log = (l,f) => console.log(`${l}     ${f(now,past)}  ${f(past,now)}  ${f(now,now)}`);

log('A',A);
log('B',B);
log('C',C);
log('D',D);
log('E',E);
log('G',G);
log('H',H);
log('I',I);
log('J',J);
log('K',K);
log('L',L);
log('M',M);
log('N',N);
p {color: red}
<p>This snippet only presents tested solutions (it not perform tests itself)</p>

Results for chrome

enter image description here

Answered   2023-09-20 20:25:02

  • But d1==d2 or d1===d2 is useless in the context of the question. - anyone

In order to create dates from free text in JavaScript you need to parse it into the Date object.

You could use Date.parse() which takes free text and tries to convert it into a new date but if you have control over the page I would recommend using HTML select boxes instead or a date picker such as the YUI calendar control or the jQuery UI Datepicker.

Once you have a date, as other people have pointed out, you can use simple arithmetic to subtract the dates and convert it back into a number of days by dividing the number (in seconds) by the number of seconds in a day (60*60*24 = 86400).

Answered   2023-09-20 20:25:02

var date_today=new Date();
var formated_date = formatDate(date_today);//Calling formatDate Function

var input_date="2015/04/22 11:12 AM";

var currentDateTime = new Date(Date.parse(formated_date));
var inputDateTime   = new Date(Date.parse(input_date));

if (inputDateTime <= currentDateTime){
    //Do something...
}

function formatDate(date) {
    var hours = date.getHours();
    var minutes = date.getMinutes();
    var ampm = hours >= 12 ? 'PM' : 'AM';

    hours = hours % 12;
    hours = hours ? hours : 12; // the hour '0' should be '12'
    hours   = hours < 10 ? '0'+hours : hours ;

    minutes = minutes < 10 ? '0'+minutes : minutes;

    var strTime = hours+":"+minutes+ ' ' + ampm;
    return  date.getFullYear()+ "/" + ((date.getMonth()+1) < 10 ? "0"+(date.getMonth()+1) :
    (date.getMonth()+1) ) + "/" + (date.getDate() < 10 ? "0"+date.getDate() :
    date.getDate()) + " " + strTime;
}

Answered   2023-09-20 20:25:02

An Improved version of the code posted by "some"

/* Compare the current date against another date.
 *
 * @param b  {Date} the other date
 * @returns   -1 : if this < b
 *             0 : if this === b
 *             1 : if this > b
 *            NaN : if a or b is an illegal date
*/ 
Date.prototype.compare = function(b) {
  if (b.constructor !== Date) {
    throw "invalid_date";
  }

 return (isFinite(this.valueOf()) && isFinite(b.valueOf()) ? 
          (this>b)-(this<b) : NaN 
        );
};

usage:

  var a = new Date(2011, 1-1, 1);
  var b = new Date(2011, 1-1, 1);
  var c = new Date(2011, 1-1, 31);
  var d = new Date(2011, 1-1, 31);

  assertEquals( 0, a.compare(b));
  assertEquals( 0, b.compare(a));
  assertEquals(-1, a.compare(c));
  assertEquals( 1, c.compare(a));

Answered   2023-09-20 20:25:02

  • Presumably a is the Date instance on which the method is called. In which case can a be an invalid date, but still be a Date instance? - anyone

I usually store Dates as timestamps(Number) in databases.

When I need to compare, I simply compare among those timestamps or

convert it to Date Object and then compare with > <if necessary.

Note that == or === does not work properly unless your variables are references of the same Date Object.

Convert those Date objects to timestamp(number) first and then compare equality of them.


Date to Timestamp

var timestamp_1970 = new Date(0).getTime(); // 1970-01-01 00:00:00
var timestamp = new Date().getTime(); // Current Timestamp

Timestamp to Date

var timestamp = 0; // 1970-01-01 00:00:00
var DateObject = new Date(timestamp);

Answered   2023-09-20 20:25:02

Before comparing the Dates object, try setting both of their milliseconds to zero like Date.setMilliseconds(0);.

In some cases where the Date object is dynamically created in javascript, if you keep printing the Date.getTime(), you'll see the milliseconds changing, which will prevent the equality of both dates.

Answered   2023-09-20 20:25:02

Let's suppose that you deal with this 2014[:-/.]06[:-/.]06 or this 06[:-/.]06[:-/.]2014 date format, then you may compare dates this way

var a = '2014.06/07', b = '2014-06.07', c = '07-06/2014', d = '07/06.2014';

parseInt(a.replace(/[:\s\/\.-]/g, '')) == parseInt(b.replace(/[:\s\/\.-]/g, '')); // true
parseInt(c.replace(/[:\s\/\.-]/g, '')) == parseInt(d.replace(/[:\s\/\.-]/g, '')); // true
parseInt(a.replace(/[:\s\/\.-]/g, '')) < parseInt(b.replace(/[:\s\/\.-]/g, '')); // false
parseInt(c.replace(/[:\s\/\.-]/g, '')) > parseInt(d.replace(/[:\s\/\.-]/g, '')); // false

As you can see, we strip separator(s) and then compare integers.

Answered   2023-09-20 20:25:02

My simple answer for this question

checkDisabled(date) {
    const today = new Date()
    const newDate = new Date(date._d)
    if (today.getTime() > newDate.getTime()) {
        return true
    }
    return false
}
       

Answered   2023-09-20 20:25:02

If both of your dates come in the format "YYYY-MM-DD", you can skip the Date object and compare strings directly.

This works because of how the strings are compared in JS

let date1 = '2022-12-13';
let date2 = '2022-02-13';

console.log(`${date1} > ${date2}`, date1 > date2);
console.log(`${date1} < ${date2}`, date1 < date2);
console.log(`${date1} == ${date2}`, date1 == date2);

Answered   2023-09-20 20:25:02