Is there a ternary conditional operator in Python?
case [...] { when ... then ...} [ else ... ] end
for a similar effect but not at all ternary. - anyone Yes, it was added in version 2.5. The expression syntax is:
a if condition else b
First condition
is evaluated, then exactly one of either a
or b
is evaluated and returned based on the Boolean value of condition
. If condition
evaluates to True
, then a
is evaluated and returned but b
is ignored, or else when b
is evaluated and returned but a
is ignored.
This allows short-circuiting because when condition
is true only a
is evaluated and b
is not evaluated at all, but when condition
is false only b
is evaluated and a
is not evaluated at all.
For example:
>>> 'true' if True else 'false'
'true'
>>> 'true' if False else 'false'
'false'
Note that conditionals are an expression, not a statement. This means you can't use statements such as pass
, or assignments with =
(or "augmented" assignments like +=
), within a conditional expression:
>>> pass if False else pass
File "<stdin>", line 1
pass if False else pass
^
SyntaxError: invalid syntax
>>> # Python parses this as `x = (1 if False else y) = 2`
>>> # The `(1 if False else x)` part is actually valid, but
>>> # it can't be on the left-hand side of `=`.
>>> x = 1 if False else y = 2
File "<stdin>", line 1
SyntaxError: cannot assign to conditional expression
>>> # If we parenthesize it instead...
>>> (x = 1) if False else (y = 2)
File "<stdin>", line 1
(x = 1) if False else (y = 2)
^
SyntaxError: invalid syntax
(In 3.8 and above, the :=
"walrus" operator allows simple assignment of values as an expression, which is then compatible with this syntax. But please don't write code like that; it will quickly become very difficult to understand.)
Similarly, because it is an expression, the else
part is mandatory:
# Invalid syntax: we didn't specify what the value should be if the
# condition isn't met. It doesn't matter if we can verify that
# ahead of time.
a if True
You can, however, use conditional expressions to assign a variable like so:
x = a if True else b
Or for example to return a value:
# Of course we should just use the standard library `max`;
# this is just for demonstration purposes.
def my_max(a, b):
return a if a > b else b
Think of the conditional expression as switching between two values. We can use it when we are in a 'one value or another' situation, where we will do the same thing with the result, regardless of whether the condition is met. We use the expression to compute the value, and then do something with it. If you need to do something different depending on the condition, then use a normal if
statement instead.
Keep in mind that it's frowned upon by some Pythonistas for several reasons:
condition ? a : b
ternary operator from many other languages (such as C, C++, Go, Perl, Ruby, Java, JavaScript, etc.), which may lead to bugs when people unfamiliar with Python's "surprising" behaviour use it (they may reverse the argument order).if
' can be really useful, and make your script more concise, it really does complicate your code)If you're having trouble remembering the order, then remember that when read aloud, you (almost) say what you mean. For example, x = 4 if b > 8 else 9
is read aloud as x will be 4 if b is greater than 8 otherwise 9
.
Official documentation:
Answered 2023-09-20 19:54:05
f(x) = |x| = x if x > 0 else -x
sounds very natural to mathematicians. You may also understand it as do A in most case, except when C then you should do B instead... - anyone z = 3 + x if x < y else y
. If x=2
and y=1
, you might expect that to yield 4, but it would actually yield 1. z = 3 + (x if x > y else y)
is the correct usage. - anyone z = 3 + x if x < y else 3 + y
), or group the conditional (z = 3 + (x if x < y else y)
or z = (x if x < y else y) + 3
) - anyone You can index into a tuple:
(falseValue, trueValue)[test]
test
needs to return True or False.
It might be safer to always implement it as:
(falseValue, trueValue)[test == True]
or you can use the built-in bool()
to assure a Boolean value:
(falseValue, trueValue)[bool(<expression>)]
Answered 2023-09-20 19:54:05
(lambda: print("a"), lambda: print("b"))[test==true]()
- anyone []
s can be an arbitrary expression. Also, for safety you can explicitly test for truthiness by writing [bool(<expression>)]
. The bool()
function has been around since v2.2.1. - anyone True
and False
as the keys: {True:trueValue, False:falseValue}[test]
I don't know whether this is any less efficient, but it does at least avoid the whole "elegant" vs. "ugly" debate. There's no ambiguity that you're dealing with a boolean rather than an int. - anyone For versions prior to 2.5, there's the trick:
[expression] and [on_true] or [on_false]
It can give wrong results when on_true
has a false Boolean value.1
Although it does have the benefit of evaluating expressions left to right, which is clearer in my opinion.
Answered 2023-09-20 19:54:05
<expression 1> if <condition> else <expression 2>
a = 1
b = 2
1 if a > b else -1
# Output is -1
1 if a > b else -1 if a < b else 0
# Output is -1
Answered 2023-09-20 19:54:05
return 3 if t > 10 else t/2
- anyone From the documentation:
Conditional expressions (sometimes called a “ternary operator”) have the lowest priority of all Python operations.
The expression
x if C else y
first evaluates the condition, C (not x); if C is true, x is evaluated and its value is returned; otherwise, y is evaluated and its value is returned.See PEP 308 for more details about conditional expressions.
New since version 2.5.
Answered 2023-09-20 19:54:05
An operator for a conditional expression in Python was added in 2006 as part of Python Enhancement Proposal 308. Its form differs from common ?:
operator and it looks like this:
<expression1> if <condition> else <expression2>
which is equivalent to:
if <condition>: <expression1> else: <expression2>
Here is an example:
result = x if a > b else y
Another syntax which can be used (compatible with versions before 2.5):
result = (lambda:y, lambda:x)[a > b]()
where operands are lazily evaluated.
Another way is by indexing a tuple (which isn't consistent with the conditional operator of most other languages):
result = (y, x)[a > b]
or explicitly constructed dictionary:
result = {True: x, False: y}[a > b]
Another (less reliable), but simpler method is to use and
and or
operators:
result = (a > b) and x or y
however this won't work if x
would be False
.
A possible workaround is to make x
and y
lists or tuples as in the following:
result = ((a > b) and [x] or [y])[0]
or:
result = ((a > b) and (x,) or (y,))[0]
If you're working with dictionaries, instead of using a ternary conditional, you can take advantage of get(key, default)
, for example:
shell = os.environ.get('SHELL', "/bin/sh")
Source: ?: in Python at Wikipedia
Answered 2023-09-20 19:54:05
result = {1: x, 0: y}[a > b]
is another possible variant (True
and False
are actually integers with values 1
and 0
) - anyone Unfortunately, the
(falseValue, trueValue)[test]
solution doesn't have short-circuit behaviour; thus both falseValue
and trueValue
are evaluated regardless of the condition. This could be suboptimal or even buggy (i.e. both trueValue
and falseValue
could be methods and have side effects).
One solution to this would be
(lambda: falseValue, lambda: trueValue)[test]()
(execution delayed until the winner is known ;)), but it introduces inconsistency between callable and non-callable objects. In addition, it doesn't solve the case when using properties.
And so the story goes - choosing between three mentioned solutions is a trade-off between having the short-circuit feature, using at least Python 2.5 (IMHO, not a problem anymore) and not being prone to "trueValue
-evaluates-to-false" errors.
Answered 2023-09-20 19:54:05
if else if
. - anyone Here I just try to show some important differences in the ternary operator between a couple of programming languages.
var a = true ? 1 : 0;
# 1
var b = false ? 1 : 0;
# 0
a = true ? 1 : 0
# 1
b = false ? 1 : 0
# 0
val a = true ? 1 | 0
# 1
val b = false ? 1 | 0
# 0
a <- if (TRUE) 1 else 0
# 1
b <- if (FALSE) 1 else 0
# 0
a = 1 if True else 0
# 1
b = 1 if False else 0
# 0
Answered 2023-09-20 19:54:05
print a || '<alt text>'
in ruby is pita in python print a if a is not None else 'alt text'
- anyone print(a or 'alt text')
in Python. - anyone For Python 2.5 and newer there is a specific syntax:
[on_true] if [cond] else [on_false]
In older Pythons, a ternary operator is not implemented but it's possible to simulate it.
cond and on_true or on_false
Though there is a potential problem, which is if cond
evaluates to True
and on_true
evaluates to False
then on_false
is returned instead of on_true
. If you want this behaviour the method is OK, otherwise use this:
{True: on_true, False: on_false}[cond is True] # is True, not == True
which can be wrapped by:
def q(cond, on_true, on_false)
return {True: on_true, False: on_false}[cond is True]
and used this way:
q(cond, on_true, on_false)
It is compatible with all Python versions.
Answered 2023-09-20 19:54:05
q("blob", on_true, on_false)
returns on_false
, whereas on_true if cond else on_false
returns on_true
. A workaround is to replace cond
with cond is not None
in these cases, although that is not a perfect solution. - anyone bool(cond)
instead of cond is True
? The former checks the truthiness of cond
, the latter checks for pointer-equality with the True
object. As highlighted by @AndrewCecil, "blob"
is truthy but it is not True
. - anyone You might often find
cond and on_true or on_false
but this leads to a problem when on_true == 0
>>> x = 0
>>> print x == 0 and 0 or 1
1
>>> x = 1
>>> print x == 0 and 0 or 1
1
Where you would expect this result for a normal ternary operator:
>>> x = 0
>>> print 0 if x == 0 else 1
0
>>> x = 1
>>> print 0 if x == 0 else 1
1
Answered 2023-09-20 19:54:05
Does Python have a ternary conditional operator?
Yes. From the grammar file:
test: or_test ['if' or_test 'else' test] | lambdef
The part of interest is:
or_test ['if' or_test 'else' test]
So, a ternary conditional operation is of the form:
expression1 if expression2 else expression3
expression3
will be lazily evaluated (that is, evaluated only if expression2
is false in a boolean context). And because of the recursive definition, you can chain them indefinitely (though it may considered bad style.)
expression1 if expression2 else expression3 if expression4 else expression5 # and so on
Note that every if
must be followed with an else
. People learning list comprehensions and generator expressions may find this to be a difficult lesson to learn - the following will not work, as Python expects a third expression for an else:
[expression1 if expression2 for element in iterable]
# ^-- need an else here
which raises a SyntaxError: invalid syntax
.
So the above is either an incomplete piece of logic (perhaps the user expects a no-op in the false condition) or what may be intended is to use expression2
as a filter - notes that the following is legal Python:
[expression1 for element in iterable if expression2]
expression2
works as a filter for the list comprehension, and is not a ternary conditional operator.
You may find it somewhat painful to write the following:
expression1 if expression1 else expression2
expression1
will have to be evaluated twice with the above usage. It can limit redundancy if it is simply a local variable. However, a common and performant Pythonic idiom for this use-case is to use or
's shortcutting behavior:
expression1 or expression2
which is equivalent in semantics. Note that some style-guides may limit this usage on the grounds of clarity - it does pack a lot of meaning into very little syntax.
Answered 2023-09-20 19:54:05
expression1 or expression2
being similar and with the same drawbacks/positives as expression1 || expression2
in javascript - anyone expressionN
for all instances is consistent, it might be easier to understand with naming that distinguished the conditional test expression from the two result expressions; eg, result1 if condition else result2
. This is especially evident when nesting (aka chaining): result1 if condition1 else result2 if condition2 else result3
. See how much better that reads this way? - anyone One of the alternatives to Python's conditional expression
"yes" if boolean else "no"
is the following:
{True: "yes", False: "no"}[boolean]
which has the following nice extension:
{True: "yes", False: "no", None: "maybe"}[boolean_or_none]
The shortest alternative remains
("no", "yes")[boolean]
which works because issubclass(bool, int)
.
Careful, though: the alternative to
yes() if boolean else no()
is not
(no(), yes())[boolean] # bad: BOTH no() and yes() are called
but
(no, yes)[boolean]()
This works fine as long as no
and yes
are to be called with exactly the same parameters. If they are not, like in
yes("ok") if boolean else no() # (1)
or in
yes("ok") if boolean else no("sorry") # (2)
then a similar alternative either does not exist (1) or is hardly viable (2). (In rare cases, depending on the context, something like
msg = ("sorry", "ok")[boolean]
(no, yes)[boolean](msg)
could make sense.)
Thanks to Radek Rojík for his comment
Answered 2023-09-20 19:54:05
As already answered, yes, there is a ternary operator in Python:
<expression 1> if <condition> else <expression 2>
In many cases <expression 1>
is also used as Boolean evaluated <condition>
. Then you can use short-circuit evaluation.
a = 0
b = 1
# Instead of this:
x = a if a else b
# Evaluates as 'a if bool(a) else b'
# You could use short-circuit evaluation:
x = a or b
One big pro of short-circuit evaluation is the possibility of chaining more than two expressions:
x = a or b or c or d or e
When working with functions it is more different in detail:
# Evaluating functions:
def foo(x):
print('foo executed')
return x
def bar(y):
print('bar executed')
return y
def blubb(z):
print('blubb executed')
return z
# Ternary Operator expression 1 equals to False
print(foo(0) if foo(0) else bar(1))
''' foo and bar are executed once
foo executed
bar executed
1
'''
# Ternary Operator expression 1 equals to True
print(foo(2) if foo(2) else bar(3))
''' foo is executed twice!
foo executed
foo executed
2
'''
# Short-circuit evaluation second equals to True
print(foo(0) or bar(1) or blubb(2))
''' blubb is not executed
foo executed
bar executed
1
'''
# Short-circuit evaluation third equals to True
print(foo(0) or bar(0) or blubb(2))
'''
foo executed
bar executed
blubb executed
2
'''
# Short-circuit evaluation all equal to False
print(foo(0) or bar(0) or blubb(0))
''' Result is 0 (from blubb(0)) because no value equals to True
foo executed
bar executed
blubb executed
0
'''
PS: Of course, a short-circuit evaluation is not a ternary operator, but often the ternary is used in cases where the short circuit would be enough. It has a better readability and can be chained.
Answered 2023-09-20 19:54:05
Simulating the Python ternary operator.
For example
a, b, x, y = 1, 2, 'a greather than b', 'b greater than a'
result = (lambda:y, lambda:x)[a > b]()
Output:
'b greater than a'
Answered 2023-09-20 19:54:05
result = (y, x)[a < b]
Why do you uses lambda
function ? - anyone lambda
functions is an overkill for this question - anyone P ? x : y
or x if P else y
can be written as (lambda:y, lambda:x)[P]()
— but I doubt it has better performance and thus its necessity. - anyone a if condition else b
Just memorize this pyramid if you have trouble remembering:
condition
if else
a b
Answered 2023-09-20 19:54:05
Vinko Vrsalovic's answer is good enough. There is only one more thing:
Note that conditionals are an expression, not a statement. This means you can't use assignment statements or
pass
or other statements within a conditional expression
After the walrus operator was introduced in Python 3.8, something changed.
(a := 3) if True else (b := 5)
gives a = 3
and b is not defined
,
(a := 3) if False else (b := 5)
gives a is not defined
and b = 5
, and
c = (a := 3) if False else (b := 5)
gives c = 5
, a is not defined
and b = 5
.
Even if this may be ugly, assignments can be done inside conditional expressions after Python 3.8. Anyway, it is still better to use normal if
statement instead in this case.
Answered 2023-09-20 19:54:05
(a := 3) if True else (b := 5)
actually it's a redundant first walrus operator. This will do: a = 3 if True else (b := 5)
- anyone (a := 3) if x else (b := 5)
, you always get either a
or b
assigned, not both. However, consider a = 3 if x else (b := 5)
, when x == False
, you will get a = 5
and b = 5
, where both them are assigned. - anyone x=True
case which is of course is limited. - anyone if True else
, the reason of the first example is only compared with other examples. - anyone The ternary conditional operator simply allows testing a condition in a single line replacing the multiline if-else making the code compact.
[on_true] if [expression] else [on_false]
# Program to demonstrate conditional operator
a, b = 10, 20
# Copy value of a in min if a < b else copy b
min = a if a < b else b
print(min) # Output: 10
# Python program to demonstrate ternary operator
a, b = 10, 20
# Use tuple for selecting an item
print( (b, a) [a < b] )
# Use Dictionary for selecting an item
print({True: a, False: b} [a < b])
# lambda is more efficient than above two methods
# because in lambda we are assure that
# only one expression will be evaluated unlike in
# tuple and Dictionary
print((lambda: b, lambda: a)[a < b]()) # in output you should see three 10
# Python program to demonstrate nested ternary operator
a, b = 10, 20
print ("Both a and b are equal" if a == b else "a is greater than b"
if a > b else "b is greater than a")
Above approach can be written as:
# Python program to demonstrate nested ternary operator
a, b = 10, 20
if a != b:
if a > b:
print("a is greater than b")
else:
print("b is greater than a")
else:
print("Both a and b are equal")
# Output: b is greater than a
Answered 2023-09-20 19:54:05
if-else
isn't actually a rewrite of the ternary operator, and will produce different output for select values of a and b (specifically if one is a type which implements a weird __ne__
method). - anyone More a tip than an answer (I don't need to repeat the obvious for the hundredth time), but I sometimes use it as a one-liner shortcut in such constructs:
if conditionX:
print('yes')
else:
print('nah')
, becomes:
print('yes') if conditionX else print('nah')
Some (many :) may frown upon it as unpythonic (even, Ruby-ish :), but I personally find it more natural - i.e., how you'd express it normally, plus a bit more visually appealing in large blocks of code.
Answered 2023-09-20 19:54:05
print( 'yes' if conditionX else 'nah' )
over your answer. :-) - anyone print()
in both cases - and it looks a bit more pythonic, I have to admit :) But what if the expressions/functions are not the same - like print('yes') if conditionX else True
- to get the print()
only in truthy conditionX
- anyone print('yes') if conditionX else print('nah')
is that it gives a SyntaxError in Python2. - anyone print "yes"
, while in Python 3 it is a function - print("yes")
. That can be resolved by either using it as a statement, or better - from future import print_function
. - anyone You can do this:
[condition] and [expression_1] or [expression_2];
Example:
print(number%2 and "odd" or "even")
This would print "odd" if the number is odd or "even" if the number is even.
The result: If condition is true, exp_1 is executed, else exp_2 is executed.
Note: 0, None, False, emptylist, and emptyString evaluates as False.
And any data other than 0 evaluates to True.
If the condition [condition] becomes "True", then expression_1 will be evaluated, but not expression_2.
If we "and" something with 0 (zero), the result will always to be false. So in the below statement,
0 and exp
The expression exp won't be evaluated at all since "and" with 0 will always evaluate to zero and there is no need to evaluate the expression. This is how the compiler itself works, in all languages.
In
1 or exp
the expression exp won't be evaluated at all since "or" with 1 will always be 1. So it won't bother to evaluate the expression exp since the result will be 1 anyway (compiler optimization methods).
But in case of
True and exp1 or exp2
The second expression exp2 won't be evaluated since True and exp1
would be True when exp1 isn't false.
Similarly in
False and exp1 or exp2
The expression exp1 won't be evaluated since False is equivalent to writing 0 and doing "and" with 0 would be 0 itself, but after exp1 since "or" is used, it will evaluate the expression exp2 after "or".
Note:- This kind of branching using "or" and "and" can only be used when the expression_1 doesn't have a Truth value of False (or 0 or None or emptylist [ ] or emptystring ' '.) since if expression_1 becomes False, then the expression_2 will be evaluated because of the presence "or" between exp_1 and exp_2.
In case you still want to make it work for all the cases regardless of what exp_1 and exp_2 truth values are, do this:
[condition] and ([expression_1] or 1) or [expression_2];
Answered 2023-09-20 19:54:05
x = [condition] and ([expression_1] or 1) or [expression_2]
and expression_1
evaluates to false, x
will be 1
, not expression_1
. Use the accepted answer. - anyone Many programming languages derived from C usually have the following syntax of the ternary conditional operator:
<condition> ? <expression1> : <expression2>
At first, the Python's benevolent dictator for life (I mean Guido van Rossum, of course) rejected it (as non-Pythonic style), since it's quite hard to understand for people not used to C language. Also, the colon sign :
already has many uses in Python. After PEP 308 was approved, Python finally received its own shortcut conditional expression (what we use now):
<expression1> if <condition> else <expression2>
So, firstly it evaluates the condition. If it returns True
, expression1 will be evaluated to give the result, otherwise expression2 will be evaluated. Due to lazy evaluation mechanics – only one expression will be executed.
Here are some examples (conditions will be evaluated from left to right):
pressure = 10
print('High' if pressure < 20 else 'Critical')
# Result is 'High'
Ternary operators can be chained in series:
pressure = 5
print('Normal' if pressure < 10 else 'High' if pressure < 20 else 'Critical')
# Result is 'Normal'
The following one is the same as previous one:
pressure = 5
if pressure < 20:
if pressure < 10:
print('Normal')
else:
print('High')
else:
print('Critical')
# Result is 'Normal'
Answered 2023-09-20 19:54:05
Yes, Python have a ternary operator, here is the syntax and an example code to demonstrate the same :)
#[On true] if [expression] else[On false]
# if the expression evaluates to true then it will pass On true otherwise On false
a = input("Enter the First Number ")
b = input("Enter the Second Number ")
print("A is Bigger") if a>b else print("B is Bigger")
Answered 2023-09-20 19:54:05
print
is really not a good choice, as this will give a SyntaxError in Python2. - anyone Other answers correctly talk about the Python ternary operator. I would like to complement by mentioning a scenario for which the ternary operator is often used, but for which there is a better idiom. This is the scenario of using a default value.
Suppose we want to use option_value
with a default value if it is not set:
run_algorithm(option_value if option_value is not None else 10)
or, if option_value
is never set to a falsy value (0
, ""
, etc.), simply
run_algorithm(option_value if option_value else 10)
However, in this case an ever better solution is simply to write
run_algorithm(option_value or 10)
Answered 2023-09-20 19:54:05
option_value or 10
is not better than option_value if option_value is not None else 10
. It is shorter, indeed, but looks weird to me and may lead to bugs. What happens if option_value = 0
, for instance? The first snippet will run run_algorithm(0)
because option_value
is not None
. The second and third snippets, however, will run run_algorithm(10)
because 0
is a falsy. The two snippets are not equivalent, and hence one is not better than the other. And explicit is better than implicit. - anyone or
as a function mapping two arguments to a boolean, so I expect it to return either True
or False
(this happens in many other programming languages). But "use this or that" is a nice mnemonic and will definitely help me (and hopefully others) to remember this pattern. - anyone The syntax for the ternary operator in Python is:
[on_true] if [expression] else [on_false]
Using that syntax, here is how we would rewrite the code above using Python’s ternary operator:
game_type = 'home'
shirt = 'white' if game_type == 'home' else 'green'
It's still pretty clear, but much shorter. Note that the expression could be any type of expression, including a function call, that returns a value that evaluates to True or False.
Answered 2023-09-20 19:54:05
Python has a ternary form for assignments; however there may be even a shorter form that people should be aware of.
It's very common to need to assign to a variable one value or another depending on a condition.
>>> li1 = None
>>> li2 = [1, 2, 3]
>>>
>>> if li1:
... a = li1
... else:
... a = li2
...
>>> a
[1, 2, 3]
^ This is the long form for doing such assignments.
Below is the ternary form. But this isn't the most succinct way - see the last example.
>>> a = li1 if li1 else li2
>>>
>>> a
[1, 2, 3]
>>>
With Python, you can simply use or
for alternative assignments.
>>> a = li1 or li2
>>>
>>> a
[1, 2, 3]
>>>
The above works since li1
is None
and the interpreter treats that as False in logic expressions. The interpreter then moves on and evaluates the second expression, which is not None
and it's not an empty list - so it gets assigned to a.
This also works with empty lists. For instance, if you want to assign a
whichever list has items.
>>> li1 = []
>>> li2 = [1, 2, 3]
>>>
>>> a = li1 or li2
>>>
>>> a
[1, 2, 3]
>>>
Knowing this, you can simply such assignments whenever you encounter them. This also works with strings and other iterables. You could assign a
whichever string isn't empty.
>>> s1 = ''
>>> s2 = 'hello world'
>>>
>>> a = s1 or s2
>>>
>>> a
'hello world'
>>>
I always liked the C ternary syntax, but Python takes it a step further!
I understand that some may say this isn't a good stylistic choice, because it relies on mechanics that aren't immediately apparent to all developers. I personally disagree with that viewpoint. Python is a syntax-rich language with lots of idiomatic tricks that aren't immediately apparent to the dabbler. But the more you learn and understand the mechanics of the underlying system, the more you appreciate it.
Answered 2023-09-20 19:54:05
li1
and li2
is truthy, then li1 or li2
will return its value. If bool(li1)
returns the same value as bool(li2)
, will li1 or li2
consistently evaluate to be either one or the other (perhabs by position)? 2) how can you interpret what returns from li1 and li2
? I can't make sense of it with my test cases. - anyone Pythonic way of doing the things:
"true" if var else "false"
But there always exists a different way of doing a ternary condition too:
"true" and var or "false"
Answered 2023-09-20 19:54:05
There are multiple ways. The simplest one is to use the condition inside the "print" method.
You can use
print("Twenty" if number == 20 else "Not twenty")
Which is equivalent to:
if number == 20:
print("Twenty")
else:
print("Not twenty")
In this way, more than two statements are also possible to print. For example:
if number == 20:
print("Twenty")
elif number < 20:
print("Lesser")
elif 30 > number > 20:
print("Between")
else:
print("Greater")
can be written as:
print("Twenty" if number == 20 else "Lesser" if number < 20 else "Between" if 30 > number > 20 else "Greater")
Answered 2023-09-20 19:54:05
The if else-if version can be written as:
sample_set="train" if "Train" in full_path else ("test" if "Test" in full_path else "validation")
Answered 2023-09-20 19:54:05
Yes, it has, but it's different from C-syntax-like programming languages (which is condition ? value_if_true : value_if_false
In Python, it goes like this: value_if_true if condition else value_if_false
Example: even_or_odd = "even" if x % 2 == 0 else "odd"
Answered 2023-09-20 19:54:05
A neat way to chain multiple operators:
f = lambda x,y: 'greater' if x > y else 'less' if y > x else 'equal'
array = [(0,0),(0,1),(1,0),(1,1)]
for a in array:
x, y = a[0], a[1]
print(f(x,y))
# Output is:
# equal,
# less,
# greater,
# equal
Answered 2023-09-20 19:54:05
Yes, Python has a ternary conditional operator, also known as the conditional expression or the ternary operator. The syntax of the ternary operator in Python is:
value_if_true if condition else value_if_false
Here's an example to illustrate its usage:
x = 5
result = "Even" if (x % 2 == 0) else "Odd"
print(result)
In this example, the condition x % 2 == 0 checks if x is divisible by 2. If the condition is True, the value "Even" is assigned to the variable result. Otherwise, the value "Odd" is assigned. The output will be:
Odd
It is a good idea to use parenthesis, in order to increase readability, when working with medium complexity operations:
"Even" if (x % 2 == 0) else "Odd"
Instead of:
"Even" if x % 2 == 0 else "Odd"
The ternary operator is a concise way to write simple conditional expressions in a single line. It can be particularly useful when assigning values or constructing expressions based on conditions. However, for more complex conditions or longer expressions, if possible it's generally better to use if-else statements for improved readability.
Answered 2023-09-20 19:54:05